Exam 2 Review Flashcards
Michaelis-Menten Equation / Plot
V_0 = Vmax[S] / K_m + [S]
Hyperbolic curve
- V0 = “initial rate” = product/time
- Vmax = maximum V0 at infinite [S]
- kcat = inherent turnover number of enzyme =
observed Vmax normalized to amount of
enzyme present = Vmax/[Et] - Km = [S] at 1/2 Vmax = same as Kd if k2
(chemical step) is slow relative to S binding - kcat/Km = catalytic efficiency of enzyme
Nucleotides
- Three components (base, phosphate, and ribose – a pentose)
- Two kinds of pentose: Ribose (2’ OH, RNA), deoxyribose (2’ H, DNA)
- Three general uses:
- Present in DNA and RNA
- Act as a source of energy for living systems
(ATP and GTP) - Cellular signaling
Nucleosides lack the phosphate group of
nucleotides
What is the role of cofactors in enzymatic reactions?
Cofactors participate in catalysis or stabilize protein structure.
Define coenzymes.
Organic or metalloorganic molecules that carry functional groups necessary for enzymatic activity.
Nucleotides: Use as coenzymes
* Many enzyme cofactors or coenzymes include adenosine
* Adenosine part does not directly participate in catalysis, but contributes binding energy
* Examples:
* CoA: transfers acyl groups
* NAD: carries electrons
* FAD: carries electrons
Polymerase Chain Reaction: PCR
The polymerase chain reaction (PCR) provides
a convenient and rapid method for amplifying
segments of DNA if the sequences of the ends of the targeted DNA segment are known.
What is the transition state in a chemical reaction?
The point at which the formation of substrate or product is equally likely to happen.
What does ΔG‡ represent?
The activation energy, the difference between ground state energy level and transition state energy level.
What does the ES complex represent?
The transient complex of the enzyme with the substrate.
Ribose conformations
- Conformation of pentose: four different “puckered” conformations (4 of 5 atoms in a single plane), C-2’ endo or exo, C-3’ endo or exo
- Different conformations found in different DNA/RNA structures
DNA sequencing: Sanger method
- Four reactions are run, containing:
- template DNA (to be sequenced)
- oligonucleotide (short DNA)
- DNA polymerase (enzyme) to make the DNA
- dNTPs (dATP, dGTP, dCTP, and dTTP)
- In each reaction, one of the four nucleotide pools includes some radioactive dideoxy NTP (ddNTP) chemically altered bases
- Lack of 3’OH in ddNTP halts DNA synthesis (replication)
- ssDNA strands can be separated with electrophoresis
- The DNA sequence can then be read off from the gel from bottom (smallest) to top (biggest)
- NB: this sequence is complementary to the original DNA strand
What does the Michaelis-Menten equation describe?
The relationship between reaction velocity and substrate concentration.
What does K_m indicate?
Substrate binding affinity; it is the same as the dissociation constant K_d.
What is k_cat?
The turnover number, the number of molecules of substrate converted to product per second at saturating substrate concentration.
How is catalytic efficiency represented?
As k_cat/K_m, indicating how effectively an enzyme converts substrate to product.
What happens to V_max and K_m during reversible competitive inhibition?
V_max remains the same
K_m increases
What type of enzyme is chymotrypsin?
A protease that catalyzes hydrolytic cleavage of polypeptide bonds.
- substrate specificity: peptide bond after aromatic aa (F, Y, W)
- nucleophilic attack of substrate by Ser195
- Ser195 reactivity tuned by adjacent residues
- acyl-enzyme intermediate
Chymotrypsin’s reaction?
- Substrate (polypeptide containing an aromatic residue) binds to chymotrypsin active site
- Aromatic side chain fits in hydrophobic pocket
- Same residue’s C=O fits in oxyanion hole
- His57 H-bonds with Ser195, making it a nucleophile
- Ser195 attacks the substrate C=O carbon, forming covalent tetrahedral intermediate
- Oxyanion hole, including Ser195 and Gly193 main-chain N—H, stabilizes negative charge on C—O-
- The unstable tetrahedral intermediate breaks down
- The part of the substrate polypeptide that was C-terminal to the aromatic residue leaves as product 1
- His57 protonates the amino leaving group
- A covalent acyl-enzyme intermediate is left over
- Now for the second half of the reaction…
- A water molecule (from the surrounding solvent) gets deprotonated by His57
- The resulting OH- attacks the substrate C=O carbon of the acyl-enzyme intermediate
- Forms a second covalent tetrahedral intermediate
- Oxyanion hole again stabilizes negative charge on C—O-
- Second tetrahedral intermediate also breaks down
- The part of the substrate polypeptide that was N-terminal to the aromatic residue, now with a new C-terminus, becomes product 2
- Product 2 dissociates
- The cycle is complete
- Chymotrypsin can catalyze another cycle of proteolysis
What stabilizes the negative charge on the tetrahedral intermediate in chymotrypsin’s reaction?
The oxyanion hole, which includes Ser195 and Gly193 main-chain N—H.
Irreversible enzyme inhibition
An irreversible inhibitor prevents this by
permanently modifying the enzyme
- Reaction of chymotrypsin with
diisopropylfluorophosphate (DIFP) leads
to a covalent modification of the
enzyme’s nucleophile (Ser195) to
irreversibly inhibit the enzyme - Ser195 can’t carry out its function, thus
the enzyme is no longer active
What does the Lineweaver-Burk plot help to calculate?
V_max and K_m from the x- and y-intercepts.
What type of intermediate is formed when His57 protonates the amino leaving group?
Covalent acyl-enzyme intermediate
This intermediate is crucial for the reaction mechanism involving His57.
What role does water play in the second half of the reaction? Chymotrypsin
Deprotonated by His57 and attacks the substrate C=O carbon
This step leads to the formation of a second covalent tetrahedral intermediate.
How does pH affect enzyme activity?
-
pH alters ionization of R groups, coenzymes,
and cofactors which in turn may alter the 3D
structure of enzyme or chemistry of active site - often pH optimum is related to biological
setting: -
pepsin is a digestive enzyme in stomach
(pH optimum ~ 1.6); pH in gastric juice is ~
1.5 after eating a meal -
glucose 6-phosphatase acts in liver cells
(pH optimum ~ 7.8); pH in cell ~ 7.2
This can change the 3D structure of the enzyme or the chemistry of the active site.
Define allosteric enzymes.
- Allosteric enzymes have separate binding
sites for molecules that can affect catalysis at
the active site - Regulation can be positive or negative
- Analogy to H+, CO2, and BPG for hemoglobin
(though Hb is not an enzyme) - Allosteric modulator can be same as substrate (homotropic) or different from substrate (heterotropic)
- Many allosteric enzymes have multiple subunits (e.g. quaternary structure)
- Each subunit may bind substrate and/or positive and/or negative allosteric modulators
They can exhibit positive or negative regulation.