exam 3 Flashcards
(103 cards)
Write the full electron configuration for aluminum (Al)
1s^2s^2 3s^23p^1
How many core and valence electrons does aluminum have?
10 core 3 valence
What is ionization energy?
the energy required to remove an electron from an atom in the gas phase
Is it easier to remove a core or valence electron from an atom?
It is easier to remove a valence electron because a valence electron is further from the nucleus and has a weaker force of attraction to the nucleus. A weaker force of attraction needs LESS energy to overcome the force (lower ionization energy). A core electron is closer to the nucleus and has a stronger force of attraction to the nucleus. A stronger force of attraction needs more energy to overcome the force (higher ionization energy).
Draw a graph showing the first six ionization energies of Aluminum. Explain how this graph represents aluminum (explain changes in force and energy)
- You would draw the first 3 dots being closer to the x-axis, and the 4 dot in the middle of the graph and the other two linearly increasing until 6.
- There is a big jump in ionization energy between the 3rd and fourth ionizations. Aluminum has three valence electrons. ve- are further away from the nucleus and experience a lower effective nuclear charge than core electrons, making them less attracted to the nucleus and easier to remove with less energy. The fourth ionization requires more energy because of the attraction between the core electrons and the nucleus.
draw a PE curve for h atom and then he atoms. Identify the curve and label the axes.
Explain the depths of the potential wells.
Explain the positions.
draw a big dig closer to the PE line for H and a small dip closer to the r (or the right side) and label that He
the pe well is deeper for H because when two hydrogen atoms interact they form a covalent bond, while 2 He atoms interact through LDFs. Covalent bonds are much stronger than LDFs.
The potential well for He has a longer distance between the nuclei than H because when two atoms are interacting through LDFs they are further apart then when they are covalently bonded together.
The melting point for Iodine (I2) is 387K and the boiling point is 457K. Draw an atomic/molecular level representations of Iodine at 400K and 460K. Within each drawing indicate (with an arrow) and label any bonds and/or interactions present. If no bonds and/or interactions are present.
I2 at 400K (liquid) - draw ovals representing dipoles with two iodine molecules bonded together. (dont forget the d signs) Draw a arrow inside
12 at 460K (gas) - show two ovals separated and a covalent bond still exisiting.
The melting point of Xe is 161K and the boiling point is 165K. Draw Xe at 163K and 170K.
Xe at 163K (liquid) - only LDF is present. small circles of solo bonds.
Xe at 170K (gas) - (none) just two circles not touching.
What bonds/interactions are overcome when iodine (i2) and xenon (Xe) boils?
LDF
Iodine has a higher boiling point than Xe. What is the evidence and reasoning?
evidence:
The electron cloud for a Xe atom has 54 electrons. The electron cloud for an iodine molecule (I2) has 106 electrons.
reasoning:
More electrons in the electron cloud result in bigger dipoles (a bigger 𝛿+ and 𝛿−). Bigger dipoles result in a stronger force of attraction (stronger LDF) - remember Coulomb’s law. Stronger LDFs need more energy (a higher boiling point) to break.
a. List the elemental forms that have relatively low melting and boiling points? Identify if the element is a metal or a nonmetal
b. What type of bonding and/or interactions might be overcome during a phase change for each of the elemental forms you listed in part a?
H2, He, N2, O2, F2, Ne (nonmetals)
- LDF
List the elemental forms that have relatively high melting and boiling points? Identify if the element is a metal or a nonmetal.
What type of bonding and/or interactions might be overcome during a phase change for each of the elemental forms you listed in part c?
Li, Be - metal
B – nonmetal (metalloid)
C - nonmetal
-covalent bond or metallic bond
What elements overcome LDF during a phase change?
H2 (small mol) , He (discrete atoms) N2 (small mol), O2 (sm mol) F2 (sm mol), Ne (discrete atoms)
What elements overcome Covalent Bonds during a phase change?
B(s) , C(s) (extended network)
What elements overcome metallic bonds during a phase change?
Li(s) , Be (s) (extended network)
What pattern do you see regarding the melting and boiling points of these elements relative to the types of bonding and interactions overcome during a phase change?
Elemental forms with very high melting and boiling points are extended network solids. The atoms are held together by metallic bonding or covalent bonds.
Elemental forms with lower melting and boiling points are made of either discrete atoms or small molecules with LDFs between them.
The extended network solids have higher melting and boiling points because both metallic bonds and covalent bonds are very strong interactions. These strong interactions must be broken when the solid melts (or the liquid boils). It would require a lot of energy (high temperature) to break these interactions.
LDFs are relatively weak interactions. Less energy is required (lower temperatures) to overcome these interactions. It is the LDFs (not the bonds within the molecules) that are overcome when the solid melts (or the liquid boils).
Why is nitrogen a gas at room temperature and carbon is a solid?
The nitrogen exists as small, non-polar diatomic molecules interact with each other through LDFs caused by the momentary fluctuating dipoles (instantaneous diploes induce dipoles in nearby molecules – weak). Carbon atoms form localized, strong interactions between the atoms (extended networks in a lattice structure - think diamond or graphite). At room temperature there is enough energy to break the LDFs between the nitrogen molecules but there is not enough energy to break the stronger bonds between the carbon atoms.
Draw a molecular level picture of Copper and use it to describe the bonding present
explain how the model of bonding you discussed explains the properties you listed for each substance
Copper - high MP, has a color, malleable and ductile, shiny, and conducts electricity
Lattice of regularly spaced nuclei and core electrons. Valence electrons are delocalized and can move freely because they are in molecular orbitals that span the system.
you would draw about 12 spaced atoms with positive charges drawn in the middle and then delocalized valence electrons.
Draw a molecular level picture of Graphite and use it to describe the bonding present
explain how the model of bonding you discussed explains the properties you listed for each substance
Graphite - high MP, soft, slippery, shiny, conducts electricity.
Two-dimensional sheets of sp2 hybridized C atoms. The remaining p-orbitals overlap to form delocalized pi-orbitals that extend throughout the sheet.
draw hectogon (6 dots each) shape with 5 connected. Create 3 rows of that. flat sheets. Looks like honeycomb.
Graphite: Leftover p orbitals form a band of pi molecular orbitals that extend throughout the entire structure so electrons are free to move. Delocalized electrons allow graphite to conduct electricity. Sheets of graphite are 2D and are held together by LDFs (relatively weak). LDFs are easy to break so sheets can slip and bend. Graphite is soft because of the slipping of the sheets.
Draw a molecular level picture of Diamond and use it to describe the bonding present
explain how the model of bonding you discussed explains the properties you listed for each substance
3D network of sp3 hybridized C atoms with localized covalent bonds.
High MP because covalent bonds are strong. Electrons are localized in the bonds between the atoms and cannot move freely. Therefore, diamond cannot conduct electricity. Diamond is hard because the atoms are covalently bonded in 3D structure, which is hard to break apart.
define a covalent bond
two atoms interact by ve- of one atom being attracted to the nucleus of another, however each nucleus is attracting the ve- in a tug of war of attractive forces.
define bond length
most stable distance between the atoms - lowest potential energy
when bonds form….
energy is RELEASED into the surroundings!
What is the molecular orbital (MO) theory?
electrons are waves and can combine constructively and destructively. In MO Theory, n atomic orbitals combine and give n molecular orbitals.
There’s a drawing of seven valence electrons for each of 2CL atoms to make a CL2 mole it is drawn into a molecular or remember to start at the bottom and work your way to the top!