Exam 3 Practice test Flashcards

(42 cards)

1
Q

SN2 mechanism/product

A

Inverted, nucleophile replaced

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2
Q

SN1 mechanism/product

A

Retention and inverstion, nucleophile replaced

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3
Q

HX

A

Halo at mark, syn and anti

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4
Q

HBr ONLY, ROOR

A

Br at anti mark, syn and anti

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5
Q

Br2 or Cl2

A

Anti addn across DB

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6
Q

Br2 or Cl2 and H2O

A

Anti- OH at mark, halo at anti mark

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7
Q

H3O+ or H2O

A

OH at mark, syn and anti

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8
Q
  1. Hg(OAc)2, H2O
  2. NaBH4
A

OH at mark

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9
Q
  1. BH3, THF
  2. HOOH, NaOH
A

OH at anti mark across DB, syn

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10
Q
  1. Hg(OAc)2, MeOH
  2. NaBH4
A

MeO at mark

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11
Q

CHX3, KOH

A

Both ends of DB bind to C, 2X bonded to C, syn

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12
Q

CH2I2, ZnCu

A

Both ends of DB bind to C, 2X bonded to C, syn

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13
Q

H2, Pd/C or H2, PtO2

A

Erases DB

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14
Q

RCO3H

A

DB erase, just bonded to O on both sides (epoxide)

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15
Q

H3O+, H2O (epoxide)

A

Anti addn of OH across DB

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16
Q

OH, H2O (Epoxide)

A

Anti addn of OH across DB

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17
Q
  1. OSO4
  2. NaHSO3, H2O, (Or H2O2)
A

Syn OH across DB

18
Q

KMnO4 (cold, dilute), OH, H2O

A

Syn OH across DB

19
Q

HIO4, H2O

A

OH double bonds to C on both ends, cutting cyclowhatever

20
Q
  1. O3
  2. Zn (H3O+) or (CH3)2S
A

OH double bonds to C on both ends, cutting cyclowhatever

21
Q
  1. O3
  2. H2O2
A

Adds double bonded O across DB, cutting cyclowhatever. OH added at one end

22
Q

Hot concentrated KMnO4, H3O+, H2O

A

Adds double bonded O across DB, cutting cyclowhatever. OH added at one endf

23
Q

Bredt’s rule

A

Can’t have a double bond at a bridgehead carbon if the ring has less than 8 carbons

24
Q

E1 mechanism and product

A

Leaving group removed, stable products

25
E2 mechanism and product
Leaving group left, stable product plus enantiomer
26
Vinyl
Radical over double bond
27
Allyl
Radical across from double bond
28
Homolytic cleavage
X-X --> 2.X
29
Addition to pi bond
X. + = --> X/\.
30
Hydrogen abstraction
X. H-R --> X-H + R.
31
Halogen abstraction
R. X-X --> R-X + X.
32
Elimination
X/\. --> X. =
33
Coupling
2X. --> X-X
34
Chlorination of methane
UV light causes homolytic cleavage of Cl2, H bonds to one radical, radical carbon grabs Cl radical, radicals react with each other
35
Where does Br attach to with peroxide?
End of DB
36
Relative reactivity
% yield/#Hs
37
Strongest CH bond
Connected to 2x bond, then 2C away, then 1c
38
NBS
Adds br at mark, forms low concentration of Br2
39
Bromination of DB
NBr broken, radical formed. Br and H form bond, leaving rad on cyclohexane. Then Br2 breaks, adding br to cyclohexane
40
Br2 and HV
BR added to mark
41
KOT HOT
Removes Br, creates db
42
PLEASE KNOW (PAGE 20)