The 1st and 2nd Derivatives & Applications of Derivatives Flashcards

(50 cards)

1
Q

What is f’(x)

A

Instantaneous rate of change - The gradient of the tangent to the curve at a point

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2
Q

if f’(x) >0

A

gradient is increasing

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3
Q

if f’(x) <0

A

gradient is decreasing

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4
Q

if f’(x) =0

A

gradient is stationary

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5
Q

Stationary point

A

gradient of the tangent to the curve at the point is horizontal

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6
Q

Maximum turning point

A

gradient goes from-ve –>0–>+ve

i.e /-\

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7
Q

Minimum turning point

A

gradient goes from +ve –> 0 –> +ve

i.e _/

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8
Q

point of inflection

A

point on curve where tangent crosses the line

i.e the concavity changes

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9
Q

local maximum

A
Given point (a, f(a))
if f(x) is less than or equal to f(a)
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10
Q

local minimum

A
given the point (a, f(a))
if f(x) is greater than or equal to f(a)
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11
Q

how to find stationary points

A

Let the first derivative =0

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12
Q

global maximum

A

the highest point at the endpoint of a given domain

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13
Q

global minimum

A

lowest point at the other endpoint of a given domain

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14
Q

how to find max and min value of a function in a given domain

A

sub each value of x in the domain into the function

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15
Q

Second derivative

A

the rate of change of the first derivative (the rate of change of the gradient)

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16
Q

if f’‘(a)>0

A

concave upwards and there is a minimum turning point there

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17
Q

if f’‘(a)<0

A

concave downwards and there is a maximum turning point there

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18
Q

if y’‘=0

A

there is an inflection point at a point on the curve AND concavity changes at this point

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19
Q

max turning point…

A

y’=0 and y’‘<0

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20
Q

min turning point…

A

y’=0 and y’‘>0

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21
Q

horizontal point of inflection…

A

y’=0, y’‘=0 and concavity changes

22
Q

when y’‘(a)=0

A

more work is needed to decide the nature of the point

23
Q

what table to use with f(x)

A

table of signs –> to find where the function is positive or negative

24
Q

what table to use with f’(x)

A

table of slopes –> to determine the nature of stationary points

25
what table to use with f''(x)
table of concavity --> to find any points of inflection and the concavity of the function
26
point of inflection
concavity changes
27
how to find stationary points
let y'=0
28
how to find global max and min
examine and compare the: turning points, boundaries of the domain (or behaviour for large x) and any discontinuities of f'(x) (when y=0/0)
29
steps to find the nature of stationary points
derive, solve y'=0 if stationary points exist --> sub into original to find coords easy to differentiate--> second derive --> sign of y'' - zero --> table of concavities - positive --> min turning point - negative --> max turning point not easy to differentiate --> table of slopes with y' \_/ --> min turning point /-\ --> max turning point --- --> horizontal point of inflection
30
how to solve max/min qs
the three cs construct: draw a diagram, assign pronumerals/form equations, note restrictions calculus: differentiate, find T.Ps then find nature conclude: evaluate and compare T.Ps with endpoints/discontinuities, state final answer
31
Displacement
Relative position to starting point
32
when displacement is negative
particle is left of origin
33
when displacement is positive
particle is right of origin
34
velocity
rate of change of position with respect to time
35
when velocity is negative
particle is travelling left
36
when velocity is positive
particle is travelling right
37
speed=
the absolute value of velocity
38
acceleration
rate of change of velocity with respect to time
39
when acceleration is negative
acting to the left
40
when acceleration is positive
acting to the right
41
speeding up=
velocity and acceleration acting in the same direction
42
slowing down=
velocity and acceleration acting in opposite direction
43
"constant velocity"=
when a=0
44
"at rest"=
when v=0
45
"at the origin"=
when x=0
46
First derivative of displacement (x dot)
velocity
47
Second derivative of displacements (x double dot)
acceleration
48
second derivative shows the...
concavity
49
To find max/min of displacement
solve f'(t)=0 (velocity=0)
50
To find max/min of velocity
solve f''(t)=0 (acceleration=0)