The 1st and 2nd Derivatives & Applications of Derivatives Flashcards

1
Q

What is f’(x)

A

Instantaneous rate of change - The gradient of the tangent to the curve at a point

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2
Q

if f’(x) >0

A

gradient is increasing

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3
Q

if f’(x) <0

A

gradient is decreasing

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4
Q

if f’(x) =0

A

gradient is stationary

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5
Q

Stationary point

A

gradient of the tangent to the curve at the point is horizontal

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6
Q

Maximum turning point

A

gradient goes from-ve –>0–>+ve

i.e /-\

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7
Q

Minimum turning point

A

gradient goes from +ve –> 0 –> +ve

i.e _/

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8
Q

point of inflection

A

point on curve where tangent crosses the line

i.e the concavity changes

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9
Q

local maximum

A
Given point (a, f(a))
if f(x) is less than or equal to f(a)
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10
Q

local minimum

A
given the point (a, f(a))
if f(x) is greater than or equal to f(a)
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11
Q

how to find stationary points

A

Let the first derivative =0

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12
Q

global maximum

A

the highest point at the endpoint of a given domain

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13
Q

global minimum

A

lowest point at the other endpoint of a given domain

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14
Q

how to find max and min value of a function in a given domain

A

sub each value of x in the domain into the function

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15
Q

Second derivative

A

the rate of change of the first derivative (the rate of change of the gradient)

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16
Q

if f’‘(a)>0

A

concave upwards and there is a minimum turning point there

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17
Q

if f’‘(a)<0

A

concave downwards and there is a maximum turning point there

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18
Q

if y’‘=0

A

there is an inflection point at a point on the curve AND concavity changes at this point

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19
Q

max turning point…

A

y’=0 and y’‘<0

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20
Q

min turning point…

A

y’=0 and y’‘>0

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21
Q

horizontal point of inflection…

A

y’=0, y’‘=0 and concavity changes

22
Q

when y’‘(a)=0

A

more work is needed to decide the nature of the point

23
Q

what table to use with f(x)

A

table of signs –> to find where the function is positive or negative

24
Q

what table to use with f’(x)

A

table of slopes –> to determine the nature of stationary points

25
Q

what table to use with f’‘(x)

A

table of concavity –> to find any points of inflection and the concavity of the function

26
Q

point of inflection

A

concavity changes

27
Q

how to find stationary points

A

let y’=0

28
Q

how to find global max and min

A

examine and compare the: turning points, boundaries of the domain (or behaviour for large x) and any discontinuities of f’(x) (when y=0/0)

29
Q

steps to find the nature of stationary points

A

derive, solve y’=0
if stationary points exist –> sub into original to find coords
easy to differentiate–> second derive –> sign of y’’
- zero –> table of concavities
- positive –> min turning point
- negative –> max turning point
not easy to differentiate –> table of slopes with y’
_/ –> min turning point
/-\ –> max turning point
— –> horizontal point of inflection

30
Q

how to solve max/min qs

A

the three cs

construct: draw a diagram, assign pronumerals/form equations, note restrictions
calculus: differentiate, find T.Ps then find nature
conclude: evaluate and compare T.Ps with endpoints/discontinuities, state final answer

31
Q

Displacement

A

Relative position to starting point

32
Q

when displacement is negative

A

particle is left of origin

33
Q

when displacement is positive

A

particle is right of origin

34
Q

velocity

A

rate of change of position with respect to time

35
Q

when velocity is negative

A

particle is travelling left

36
Q

when velocity is positive

A

particle is travelling right

37
Q

speed=

A

the absolute value of velocity

38
Q

acceleration

A

rate of change of velocity with respect to time

39
Q

when acceleration is negative

A

acting to the left

40
Q

when acceleration is positive

A

acting to the right

41
Q

speeding up=

A

velocity and acceleration acting in the same direction

42
Q

slowing down=

A

velocity and acceleration acting in opposite direction

43
Q

“constant velocity”=

A

when a=0

44
Q

“at rest”=

A

when v=0

45
Q

“at the origin”=

A

when x=0

46
Q

First derivative of displacement (x dot)

A

velocity

47
Q

Second derivative of displacements (x double dot)

A

acceleration

48
Q

second derivative shows the…

A

concavity

49
Q

To find max/min of displacement

A

solve f’(t)=0 (velocity=0)

50
Q

To find max/min of velocity

A

solve f’‘(t)=0 (acceleration=0)