1 + 2 Flashcards

1
Q

Definition of statistical / mathematical model

A

Simplification of a real world situation.

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2
Q

Advantages of model (5)

A
  1. use to make predictions
  2. by analysing, improve understanding of the real situation
  3. help provide more control
  4. quick + easy
  5. simplify a more complex situation
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3
Q

Disadvantages of model (2)

A
  1. partial description of real situation

2. only work for restricted range of variables

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4
Q

definition of qualitative data

A

data that cannot be measured numerically (uncountable)

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5
Q

definition of discrete variable

A

a variable that can take only specific values in a given range (single values)

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6
Q

definition of continuous variable

A

a variable that can take any value in a given range (measured a different accuracies)

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7
Q

definition of quantitative data

A

data that can be measured numerically (countable)

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8
Q

equation for medium

frequency table, grouped data, discrete

A

frequency table= n + 1 / 2

grouped data (in classes) = n / 2 (+ use interpolation)

discrete = n / 2 (if not whole no, round up)

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9
Q

equation for mean

A

sum of x / number of values

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10
Q

equation for mean in frequency table

A

table headers: x / f / fx

mean = sum of fx / sum of f

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11
Q

equation for mean in grouped data

A

table headers: class / f / x (mid point) / fx

mean = sum of fx / sum of f

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12
Q

how to combine means

you know mean and no of values for each

A

mean = sum of x / no of values
sum of x = mean x no of values
add both ‘sum of x’ together
work out mean= total ‘sum of x’ / total no of values

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13
Q

what is interpolation used for

A

more specific medium in grouped data

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14
Q
there is grouped data: 
class   / f / cf
30-31 / 2 / 2
32-33 / 25 / 27
34-36 / 30 / 57

you figured out medium (n / 2) and now you know the medium term.

Interpolate

A
  1. 35th is between 27-57
    find fraction 35th term is between 27-57:
    35 - 27 / 57 -27 (remember smallest goes last)
    = 8 / 30
3. 27-57 is in class 34-36
find class boundaries 
you have class 34-36
so is 33.5-36.5
difference of 3 
  1. so medium is 8 / 30 x 3 = 8 / 10
  2. don’t forget to add lower boundary: 33.5
    so 33.5 + 8 /10 = 34.3 mm
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15
Q

what is usually coding used for

A

mean and makes large numbers easier to work with

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16
Q

on grouped data, how do you find the mean with coding involved:

class / f / x (which is the mid point) / code / fy

A

mean of coded data = sum of fy / sum of f

+ rearrange the code given so x is the subject + add values in (value of mean of coded data given above)

17
Q

what is x in grouped data

A

THE MID POINT

18
Q

mean of coded data

A

sum of fy / sum of f

19
Q

if there is no gaps in grouping

A

NO UPPER AND LOWER BOUNDARIES

20
Q

If given a mean and one person gave wrong ‘x’ or answer, if the new ‘x’ is higher what will happen to mean

A

Higher mean

21
Q

If given a mean and one person gave wrong ‘x’ or answer, if the new ‘x’ is lower what will happen to mean

A

lower mean

22
Q

If given a mean and one person gave wrong ‘x’ or answer, figure out new mean

A

mean = sum of x / n

figure of old sum of x by mean x n
add or subtract the difference of new ‘x’ and old ‘x’
redo calculate new mean

23
Q

you get a mean for 50 days, then a mean for 90 days, they ask for a mean for the extra 40 days, how?

A

you find out the sum of x for the 50 days

you fill in the equation for the mean for 90 days:
mean = ‘sum of x for 50 days’ + x / 90

rearrange to find out x

this x is your sum of x for the extra 40 days
fill in the equation for the mean for 40 days