1.7 Oxidation, reduction and redox Flashcards
Define term oxidation and reduction
Oxidation : Loss of electrons
Reduction : gain of electrons
Two reactions are shown. State which one is oxidation and which one is reduction
(i) F2 + 2e^- -> 2F^-
(ii) Cu^+ -> Cu^2+ + e^-
(i) Reduction
(ii) Oxidation
Define oxidising agent, reducing agent and redox reaction
Oxidising agent : A species gains electrons and it causes the other species to lose electrons (get oxidised) and so it is an electron acceptor
Reducing agent : A species loses electrons and causes the other species to gain electrons (get reduced) and so it is an electron donor
Redox reaction : Reaction involving oxidation of one species and reduction of the other
What order should you assign oxidation states and what is the acronym for it
Under My Face Heres Our Chin
Uncombined elements (0)
Metals
Fluorine (-1)
Hydrogen (+1)
Oxygen (-2)
Chlorine (-1)
What are the oxidation states of the following
(i) MgF2
(ii) SO3
(i) Mg : +2 F : -1
(ii) S : +6 O : -2
Use oxidation numbers to identify what has been oxidised and reduced for reaction
2Sr + O2 -> 2SrO
2Sr + O2 -> 2SrO
Ox states : 0 0 Sr :+2 O : -2
Sr is oxidised and Oxygen is reduced
Calculate the oxidation states for the metal in :
copper (i) oxide : Cu2O
copper (ii) oxide : CuO
Manganese (iv) oxide : MnO2
- The roman numerals gives a hint as to what the oxidation state will be
Copper (i) oxide : +1
Copper (ii) oxide : +2
Manganese (iv) oxide : +4
Give formula of chlorate (iii) ion and overall charge
Overall charge : -1
ClO2^-
State what gets oxidies and reduced in the equation : KMnO4 + HCl -> MnCl2 + Cl2 + H2O
Oxidised : Cl^-
* Its an ion because the chlorine in HCl is a negative ion
Reduced : KMnO4
* K and O dont get oxidised nore reduced but they are just spectator ions
Deduce half eqaution of chloride ions to chlorine 16H^+ + 2MnO4^- + 10Cl^- > 2Mn^2+ + 8H2O + 5Cl2
2CL^- -> Cl2 + 2e^-
The ionic equation for this redox reaction is 16H^+ + 2MnO4^− + 10Cl− -> 2Mn2^+ + 8H2O + 5Cl2
(i) Give the oxidation state of manganese in the MnO4^− ion
(ii) Deduce the half-equation for the reduction of the MnO4^−
ions in acidified solution to manganese(II) ions and water.
(i) +7
(ii) MnO4^ − + 8H^+ + 5e^−
-> Mn^2+ + 4H2O
Which of these is the best reducing agent
1. Cl2
2. I2
3. Cl^-
4. I^-
3 and 4 are better than 1 and 2 as they have a lower oxidation state
4 is better than 3 because it is a bigger atom as it has stronger forces etc.
4 has a larger atomic radius so it has a weaker attraction from nucleus to outer electrons and can be lost more easily
Deduce an equation for hydrogen iodide from its elements
0.5 H2 + 0.5 I2 -> HI
(a) Write a half-equation for the conversion of NO2^- in an acidic solution into NO
(b) Write a half-equation for the conversion of I^− into I2
(a) NO2^− + e^− + 2H^+
⟶ NO + H2O
(b) 2I− ⟶ I2 + 2e−
When chlorine is added to water, there is a redox reaction, as shown by the equation
Cl2 + H2O ⇌ HClO + HCl
Give two half-equations to show the oxidation and reduction processes that occur in this redox reaction.
Oxidation half-equation : Cl2 + 2H2O → 2HClO + 2H^+ + 2e^–
Reduction half-equation : Cl2 + 2H^+ + 2e^– → 2HCl