2018/2019 Flashcards

1
Q

Define yield stress in context of material deformation

A

Stress applied which causes a transition from linear elastic performance to non linear plastic deformation

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2
Q

Define true and engineering stress, differences?

A

True stress accounts for reduced CSA during deformation. Reduction is significant at point of necking. Necking is from localised deformation in tensile specimen after max load. With necking, engineering stress decreases but true stress continues to rise.

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3
Q

Define alloy:

A

Mixture of metal with one or more other metals or non metals

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4
Q

Define component:

A

An element in an alloy

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5
Q

Define phase:

A

A region of material having uniform physical and chemical characteristics

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6
Q

Define phase diagram:

A

The equilibrium constitution of all combinations of temperature and composition

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7
Q

What is complete solid solubility?

A

The solute atoms are completely soluble in solvent atoms for any composition of solute and solvent. Thus, a second phase doesn’t form in this case.

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8
Q

What is limited solid solubility?

A

Not all solute atoms are soluble and they will precipitate out as a solid

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9
Q

Describe pearlite structure

A

Eutectoid. An equilibrium structure of ferrite and cementite layers or lamellar. A eutectoid alloy will transform to pearlite when cooled from Y phase under equilibrium conditions.

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10
Q

How does cold working/strain gardening a material affect it’s mechanical properties and how does this change come about?

A

It increases its tensile strength BUT at the cost of reduced ductility. This is from mechanical deformation which increases dislocation density. Dislocations get closer together and interact making further deformation harder.

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11
Q

Describe precipitation hardening:

1st treatment

A

First a solution heat treatment where solute atoms are dissolved to form a single phase solid solution. Then rapidly cooled to a 2 phase region of the phase diagram but rapid cooling means diffusion can’t occur and 2nd phase isn’t achieved.

Thus non equilibrium structure of A with supersaturated B is achieved.

Weak and soft material.

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12
Q

Describe precipitation hardening:

2nd treatment

A

Precipitation heat treatment:
Supersaturated solid heated to 2 phase region. This accelerates diffusion rate allowing B phase to separate and form precipitates. Temp is held to grow B phase, size defines properties.

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13
Q

How does solid solution hardening strengthen a material?

A

Alloying a metal with an impurity introduces a lattice strain which hinders the movement of dislocations.

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14
Q

Why are stress/strain properties of ceramics not done by tensile tests?

A

1) hard to prepare samples of right shape
2) hard to grip materials without fracturing
3) need to be aligned perfectly since they fail after ≈0.1% strain

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15
Q

What is crystallisation in context of glasses?

A

Process whereby glass material is caused to transform into a crystalline solid, usually by heat treatment.

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16
Q

Give 2 properties that can be improved by crystallisation of glasses:

A

1) lower coefficient of thermal expansion

2) higher strengths

17
Q

Solid solution strengthening, small atoms:

A

Interstitial e.g. carbon, sits between other atoms in the structure

18
Q

Solid solution strengthening, larger atoms:

A

Substitutional: sits in place of another atom

19
Q

What is precipitation hardening used for?

A

Non ferrous metals e.g. aluminium

Also some steel alloys

20
Q

Oxidation and reduction?

A

Oxidation removes 1+ electrons from atom/ion

Reduction adds

21
Q

What is pitting?

A

Type of corrosion where small holes form from surface vertically down. Causes little material loss until failure. Oxidation occurs inside the pit with reduction at the surface. They happen from scratches/composition variations.

22
Q

What is galvanic corrosion?

A

Occurs when 2 metals/alloys with different compositions are electrically coupled when exposed to an electrolyte. More reactive will corrode first and protect other

23
Q

What defines galvanic corrosion rates?

A

Rate is related to anode/cathode SA exposed to electrolyte

For a cathode, a smaller anode will corrode faster than larger one

Depends on current density not just current

24
Q

How can galvanic corrosion be reduced?

A

1) coupling of dissimilar metals, choose two close ones on galvanic series
2) chose good anode/cathode ratio (large anode area)
3) electrically insulate dissimilar metals
4) electrically connect 3rd anodic metal (cathodic protection)

25
Q

Name 3 main polymers

A

Thermoplastics
Thermoses
Elastomers

26
Q

Thermoplastic properties

A
  • linear/branched chains
  • covalent bonds along chains
  • van Der Waals between chains
  • VDW break at lower temp to COV
  • soften upon heating
27
Q

Properties of thermosets

A
  • highly crosslinked
  • formed by reaction of 2 chemicals
  • rigid
  • don’t soften with heat or melt
  • can’t be reformed
  • amorphous polymers
28
Q

Properties of elastomers:

A
  • a few cross links
  • more crosslinks = stiffer/brittle
  • don’t soften with heating
29
Q

How are tensile properties of polymers and metals different?

A

Metal- largely defined by dislocation movements and resistance to this
Polymer- chain entanglement

30
Q

How does Young’s modulus of semicrystalline polymer change as it is strained more?

A

Low YM to begin, force to maintain shape is from weak VDW forces/chain slippage. After, higher YM since now due to strength of c-c covalent bonds

31
Q

What is glass transition temperature?

A

Temp where polymer changes mechanical properties from glassy to viscoelastic. Much softer/ductile after temp reached. Dictated by VDW between polymer chains.

32
Q

Why is polymer less likely to crystallise as molecular weight increases?

A

Chains become longer so harder for all regions along adjacent chains to align so as to produce the ordered atomic array