Chapter 5 Flashcards
Resonant Electric Circuits
Differential Equation
LI’’ + RI’ + (1/C)I = E’
Resonant Electric Circuits
Attenuation Factor
α = R/2L
Resonant Electric Circuits
Resonant Frequency
ω0 = 1 / √(LC)
Resonant Electric Circuits
Complimentary Function
Icf = e^(-αt) (C1cos(tωd) + C2sin(tωd))
Resonant Electric Circuits
Damped Resonant Frequency
ωd = √(ω0² - α²)
Resonant Electric Circuits
Particular Integral
-to calculate the particular integral you need to know the form of E(t)
-if Ipi is trigonometric
-Ipi = Acosωt + Bsinωt
can also be written as
Ipi = sin(ωt + arctan(A/B)) * √(A² + B²)
Resonant Electric Circuits
General Solution
I = Icf + Ipi
- but Icf tends to 0 as t tends to ∞
- so only Ipi remains after Icf has decayed away
Resonant Electric Circuits
Amplitude of Particular Integral
Amplitude = √(A² + B²)
= E0/L * ω / (√[(ω² - ω0²)² + 4α²ω²])
-amplitude is maximum when ω = ω0