Chapter 5&6 Flashcards

0
Q

Law of Conservation of Atoms

A

Number of atoms o each type of element must be the same on each side of the equation.

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1
Q

Law of Conservation of Matter

A

Matter can be neither created not destroyed. Amounts of reactants and products must be equal.

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2
Q

Decomposition Reactions

A

One substance is broken down Ito two or more simpler substances.
Ax➡A+x

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3
Q

Synthesis/ Combination/ Precipitation Reactions

A

Two or more substances react to form a single substance.

A+x➡AX

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4
Q

Acid base reactions

A

Reaction in which an acid and base makes a salt and water.

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5
Q

Single replacement reactions

A

Takes place when one element reacts with a compound to displace an element from the compound.
A+bx➡ax+b

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6
Q

What are the diatomic molecules

A

N2,h2,o2, and x2

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7
Q

Double placement reaction

A

Two dissolve compound react and exchange partners to form two new compounds. Take place between substances dissolved in water.
Ax+by➡ay+bx

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8
Q

Solvation

A

Water breaks the + and - charged pieces apart and surrounds them.

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9
Q

What are electrolytes? What are the types?

A

Dissolved substance in water.
Strong- conduct current efficiently
Weak- conduct small current
Non electrolytes- no current flows

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10
Q

What is oxidation agent and reducing agent

A

Reduction- oxidizing agent
Gains electrons, lose oxygen, gain h

Oxidation- reducing agent
Lose electrons, gain oxygen, lose h

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11
Q

What is a mole?

A

Unit of measure for an amount of a chemical substance

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12
Q

Stoichiometry

A

Refers to the relative quantities of moles and calculations that make use of mole ratios

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13
Q

Limiting reactant

A

Reactant will run out first. Determines amount of product that can be produced.

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14
Q

Solvent

A

Substance present in the largest amount in the solution

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15
Q

Solute

A

Substance present in smaller amount in a solution. May contain more than one solute

16
Q

Avogrados number

A

6.022 x 10^23 particles/ 1 mol

Vice versa

17
Q

Mole percent formula

A

Ex. Mole percent of chlorine
Total number of atoms in CCl4
1 carbon+ 4 chlorine= 5 atoms
4/5 x 100= 80% Cl

18
Q

Mass percent formula

A

Ex. Mass of Cl in CCl4
Find MW of CCl4
12.01+4(35.45)=153.81

4(35.45)/153.81x100

19
Q

Empirical formula and molecular formula

A

.

20
Q

Percent yield

A

Actual yield/ theoretical yield x100