exam 4 Flashcards
IUPAC priority
alcohol, alkene, alkyne, haloalkane
numbering if both alkene and alkyne
- number to give the first multiple bond the lowest number
- if tie, give alkene the lower number
- name as #-en-#-yne
radical
- species that contain unpaired e-
- single e- takes place of H (no 4 substituted)
sp2, stereoisomers will form
radical stability
- increases with substitution
- vinylic, methyl, 1, 2, 3, allylic (next to =, but not touching), benzylic (next to benzene, but not touching)
- most stable radical comes from breaking the easiest C-H bond
bond dissociation energy (BDE)
increase radical stability, decrease BDE/bond strength
homolytic bond cleavage
one bonding e- stays with each half of the molecule
R-R -> R. + .R
initation
- radical formation via homolytic bond cleavage of weakest/lowest BDE bond
- requires energy, heat or light
propogation
- nonradical reacts with radical -> atom abstraction
- forms new radical and new nonradical
- radicals formed continue on in the reaction
- product usually formed
termination
- not included in reaction mechanism
- 2 radicals recombine to form nonradical
- not common or product forming
radical chlorination
- proceeds unselectively, forms enantiomer mixtures based on radical selectivity (not good for retrosynthesis)
- ratio of products depends on how many of each kind of H and relative rate of forming each radical intermediate
- put Cl on every unique sp3 C
radical bromination
- proceeds selectively, one product forms
- Br only adds to more substituted C
- if equal substitution, multiple products
- endothermic, so more radical character in ts, so radical stability is more important
alkene radical bromination
- H202 or peroxides (ROOR) initiates radical
- antimarkovnikov, Br on less sub C
- creates alkane with Br on less sub C
alkyne radical bromination
- H202 or peroxides (ROOR) initiates radical
- antimarkovnikov, Br on less sub C
- creates trans alkene with Br on less sub C
alkyne + H2, metal ammonia/dissolving metal (Na(s), NH3(l), -78C)
- reduce alkyne to trans alkene
- radical mechanism makes more stable product
hydrohalogenation: alkene + HX
- alkene attacks H+ and X leaves, X- attacks carbocation from both sides
- markovnikov, X on more sub C
- creates alkane with X on more sub C, with enantiomers
halogenation: alkene + X2, H2O
- alkene attacks X which attacks back, other X leaves
- H2O backside attack of halonium ion intermediate’s most sub C, stereochemistry inverted only here
- base deprotonates H2O+
- creates alkane with trans/anti addition of an X and an OH, with OH at most sub C
hydrohalogenation: alkyne + HX
- alkyne attacks H+ and X leaves, another X- attacks more sub C
- markovnikov, X on more sub C
- trans/anti addition of H and X
- concerted bc vinyllic (+ on =) carbocation is unstable
- 1 eq: alkene with X on more sub C
- 2 eq: alkane with 2 X on more sub C
halogenation: alkene + X2
- alkene attacks X which attacks back, other X leaves
- X backside attack of halonium ion intermediate’s most sub C, stereochemistry inverted only here
- creates alkane with trans/anti addition of an X at each C of the double bond
halogenation: alkene + X2, CH3OH
- alkene attacks X which attacks back, other X leaves
- CH3OH backside attack of halonium ion intermediate’s most sub C, stereochemistry inverted only here
- base deprotonates CH3OH+
- creates alkane with trans/anti addition of an X and an CH3O, with CH3O at most sub C
halogenation: alkyne + X2
- alkyne attacks X which attacks back, other X leaves
- X backside attack of halonium ion intermediate’s most sub C
- 1 eq: alkene with trans/anti addition of X
- 2 eq: alkane with 2 X on each C
hydroboration oxidation: alkene + BH3, THF, NaOH, H2O2
- alkene attacks BH2, H-BH2 bond attacks alkene
- creates alkane with BH2 on less sub C (both enantiomers)
- NaOH, H2O2 replaces BH2 with OH
- antimakovnikov, BH2 is bulky
- syn addition of H and BH2
- creates alkane with OH on less sub C (with enantiomer)
hydroboration oxidation: alkyne + BH3, THF, NaOH, H2O2
- alkyne attacks BH2, H-BH2 bond attacks alkyne
- creates alkene with BH2 on less sub C
- NaOH, H2O2 replaces BH2 with OH (enol)
- enol undergoes tautomerization to form ketone
- syn addition of H and BH2
- internal alkyne makes ketone, terminal makes aldehyde
- carbonyl on less sub C
hydrogenation/reduction: Alkene + H2, Pd/C
- syn addition of H2 to less bulky face
- less sub alkene reacts faster
- creates alkane
hydrogenation/reduction: Alkyne + H2, Pd/C
- creates alkane