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CfE Advanced Higher Chemistry Unit 1 > Kinetics > Flashcards

Flashcards in Kinetics Deck (11)
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1

What is meant by the order of a reaction?

The number of species/molecules/ particles/ions/ moles of reactant(s) involved in the rate determining step/slowest step

2

How is the order of reaction determined?

The order of a reaction can only be determined from experimental data.

3

What is meant by a reaction being zero/first/second order with respect to a particular reactant?

Doubling concentration has no effect on the rate (zero)
Doubling concentration doubles the rate (first)
Doubling concentration quadruples rate (second)

4

What would be the overall order of reaction for these rate equations?

  1. rate = k [A]0
  2. rate = k [A]
  3. rate = k [A]
  4. rate = k [A][B]
  5. rate = k [A][B]
  6. rate = k [A][B][C]1

  1. 0
  2. 1
  3. 2
  4. 2
  5. 2
  6. 4

5

What rate equation does this data fit?

Rate = k [X][Y]

6

What would be the rate equation?

Rate = k [H2O2][I-]

or

Rate = k [H2O2][I-][H+]0

7

If the rate equation is = k [H2O2][I-], calculate the rate constant.

k = rate/[H2O2][I-]

Substitute any of the experimental data

k = 9.2x10-6 / (0.02x0.02)

0.023 mol-1 l s-1

8

What are the units of k for a zero-order reaction if the rate is in mol l-1 s-1 and concentration is mol l-1?

rate = k [A]0

k = rate / [A]0

k = mol l-1 s-1

9

What are the units of k for a first-order reaction if the rate is in mol l-1 s-1 and concentration is mol l-1?

rate = k [A]1

k = rate / [A]1

k = mol l-1 s-1 / mol l-1

k = s-1

 

10

What are the units of k for a second-order reaction if the rate is in mol l-1 s-1 and concentration is mol l-1?

rate = k [A]2

k = rate / [A]2

k = mol l-1 s-1 / (mol l-1)2

k = mol l-1 s-1 / mol2 l-2

k = mol l-1 s-1 / mol2 l-2

k = mol-1 l s-1

11

What are the units of k for a third-order reaction if the rate is in mol l-1 s-1 and concentration is mol l-1?

rate = k [A]3

k = rate / [A]3

k = mol l-1 s-1 / (mol l-1)3

k = mol l-1 s-1 / mol3 l-3

k = mol-2 l2 s-1