Organics Flashcards

1
Q

CO + NO ->

A

CO2 + 1/2N2

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2
Q

Substitution

A

Can be free radical, or nucleophilic

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3
Q

Free radical substitution

A

Cl• regenerated

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4
Q

Electrophile

A

Electron pair acceptor

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5
Q

Remember that when counting carbon chains

A

Count the longest chain, and then identify methyl groups

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6
Q

Incineration

A
  • toxic products

* can use energy released

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7
Q

Polymer melts over different temperature because it is

A

A mixture of chains of different lengths

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8
Q

OH- base

A

Accepts H+

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9
Q

Halogenoalkane + OH - ->

A

Alkene + halide + water

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10
Q

Bulky methyl groups

A

Prevent access to C

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11
Q

What is the nucleophile?

A

Is it H2O?

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12
Q

Short bonds

A

require more energy to break

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13
Q

Halogenoalkane + ammonia

A

Amine + halide + ammonium

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14
Q

Propanol

A

1 or 2

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15
Q

Alcohol oxidation

A

Produces water

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16
Q

If there are more products than you were expecting

A

Is there E/Z isomerism?

17
Q

Alcohol solubility

A
  • both involve breaking hydrogen bonds between alcohol molecules and between water molecules
  • miscible if it forms as many hydrogen bonds as are broken
  • immiscible is alkyl chains cause many more hydrogen bonds to be broken between water molecules that are formed between alcohol and water
18
Q

free radical

A

species with an unpaired electron

19
Q

Why does H2 not form in free radical substitution?

A
  • C-H bond is too strong

- H* does not form (which would be needed to make H2)

20
Q

Why is yield of free radical substitution low, even if there is only one substitution

A

has it made an isomer? functional group occurs in different places?

21
Q

alkene + acidified potassium manganate eqn

A

alkane + [OH] + H2O -> diol (on each alkene carbon)

22
Q

uses for polymers

A

feedstock for cracking

23
Q

if there are more products than you’re expecting

A

have they made more stereoisomers?

24
Q

alkene halogen substitution

A

one bromine adds to each alkene carbon (don’t add both to one)

25
Q

alcohol substitution with bromine

A
  • 50% conc. H2SO4

- KBr

26
Q

alcohol + PCl5 ->

A

halogenoalkane + POCl3 + HCl

27
Q

to show different enantiomers

A

swap longer carbon chains

28
Q

acyl chloride + amine ->

A
  • keep acyl chloride R structure and carbonyl group, then attach amine where chlorine was
  • attach amine R group instead of one H on the amine group