trig identities Flashcards by Gem Krasniqi | Brainscape

Q

sin(a+b)

A

sinacosb + cosasinb

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

sin(a-b)

A

sinacosb - cosasinb

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

cos(a+b)

A

cosacosb - sinasinb

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

cos(a-b)

A

cosacosb + sinasinb

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

tg(a+b)

A

tga+tgb/1-tga*tgb

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

tg(a-b)

A

tga-tgb/1+tga*tgb

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

ctg(a+b)

A

ctga*ctgb - 1/ctga+ctgb

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

ctg(a-b)

A

ctga*ctgb + 1/ctga-ctgb

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

sin2a

A

2sina*cosa

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

cos2a

A

cos^2-sin^2

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

tg2a

A

2*tga/1-tg^2a

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

ctg2a

A

ctg^2-1/2*ctga

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

cos a/2

A

+- sqrt(1+cosa/2)

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

sin a/2

A

+- sqrt(1-cosa/2)

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

tg a/2

A

+- sqrt(1-cosa/1+cosa)

How well did you know this?

1

Not at all

2

3

4

5

Perfectly

Q

ctg a/2

A

+- sqrt(1+cosa/1-cosa)

Q

sina*cosb

A

1/2[sin(a+b)*sin(a-b)]

Q

cosa*sinb

A

1/2[sin(a+b)-sin(a-b)]

Q

cosa*cosb

A

1/2[cos(a+b)+cos(a-b)]

Q

sina*sinb

A

1/2[cos(a+b)-cos(a-b)]

Q

sina+sinb

A

2sin a+b/2 * cos a-b/2

Q

sina-sinb

A

2sin a-b/2 * cos a+b/2

Q

cosa+cosb

A

2cos a+b * cos a-b/2

Q

cosa-cosb

A

-2sin a+b/2 * sin a-b/2