Unit 8

Question 1

pH =

Answer 1

-log[H3O+]

Question 2

pOH =

Answer 2

-log[OH-]

Question 3

Kw = [H3O+][OH-] =

Answer 3

1.0 * 10^-14 at 25 degrees celsius

Question 4

In pure water

Answer 4

pH = pOH. This is a neutral solution

Question 5

Bronsted-Lowry acid is…

Answer 5

A proton donor

Question 6

Bronsted-Lowry base is…

Answer 6

A proton acceptor

Question 7

If you know [H3O+], you calculate the pH by…

Answer 7

pH = -log[H3O+]

Question 8

If you know pH, you calculate the value of [H3O+] by…

Answer 8

[H3O+] = 10^-pH

Question 9

If you know [OH-], you calculate pOH by…

Answer 9

pOH = -log[OH-]

Question 10

If you know pOH, you calculate the value of [OH-] by…

Answer 10

[OH-] = 10^-pOH

Question 11

At a temperature of 25 degrees celsius, the following relationships are true.

Answer 11

Kw = [H3O+][OH-] = 1.0*10^-14
pKw = pH + pOH = 14

Question 12

What is [H3O+] in a strong acid solution equal to?

Answer 12

Equal to the initial concentration of the strong acid, and thus the pH is easily calculated

Question 13

What is [OH-] in a strong base solution equal to?

Answer 13

Equal to the initial concentration of the strong base, and thus the pOH is easily calculated

Question 14

Strong Acids

Answer 14

HCl, HBr, HI, HClO4, HNO3, & H2SO4

Question 15

Strong Bases

Answer 15

NaOH, KOH, Ca(OH)2, & Sr(OH)2