aromatics Flashcards

1
Q

why is c6h5ch2nh2 stronger than a benzene with no2 at the top and ch2 at the bottom

A

the lone pair of electrons on the n for the second one is more equally spread out which means the electron density at the n will be reduced so less electrons available (for protonation or donation) so it is less basic

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2
Q

one use of phenyl amines is making dyes, give 3 other uses

A

making cationic surfactants
making hair conditioner
making fabric softener

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3
Q

bond angle in benzene and cyclohexane

A

120 degrees in benzene, and 109 in cyclohexane

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4
Q

explain the bonding in benzene and the shape of benzene. compare its stability with that of the hypothetical cyclohexa-1,3,5-triene. use data in your answer. (6 marks)

A

each carbon has 3 covalent bonds, lone electrons in the p orbitals overlap and this leads to delocalisation. This forms a ring of delocalised electrons which helps making benzene stable
benzene is a planar hexagon and the c-c bonds are equall in length.

stability-
expected for cyclohexa is -360 but hydrog for benzene is -208 which is 152kjmol-1 less exothermic and because benzene is lower in energy than cyclo therefore it is more stable.

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5
Q

the enthalpy of hydrogen of cyclo hexa 1,3 di ene is not exactly double that of cyclohexene, suggest a value for it and justify your value

A

range of -239 to -121.

the double bonds are separated by one single bond, it allows some delocalisation or the overlap of p orbitals.

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6
Q

why the crude oil product was dissolved in the minimum quantity of hot water

why was the solution filtered

why was the flask left to cool at room temp

why was a clean cork used to compress the crystals in the funnel

why did they add a little cold water (poured) through the crystals

A

hot water- to ensure that crystals would form upon cooling

filtered- to remove any insoluble impurities

flask left to cool- as the yield would be lower if warm

compress crystals- so air passes through the sample not just around it

cold water- to wash away soluble impurities

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7
Q

the melting point of this sample was found to have a slightly lower mp than a data book- suggest the most likely impurity to have caused this low value and suggest an improvement to the method so a more accurate value for the mp can be obtained

A

water (excess water)

press the sample of crystals between filter papers

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8
Q

simply, in terms of bonding state why benzene is more stable than cyclo hexa 1,3,5 tri ene

A

due to delocalised electrons

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9
Q

bond lengths in benzene and shape and stability

A

all roughly 140 in benzene so its not a distorted hexagon but kekules would be as the double bond c=c and single bond c-c is different
All of the carbon-carbon bonds have exactly the samelengths - somewhere between single and double bonds because there are delocalized electrons above and below the plane of the ring, which makesbenzene particularly stable

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10
Q

comparing bond lengths for benzene and kekules structure

A

benzene= 140 all bonds
cyclohexa blah c-c= a54
cyclohexa c=c =134

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11
Q

The hydrocarbons benzene and cyclohexene are both unsaturated compounds.
Benzene normally undergoes substitution reactions, but cyclohexene normally
undergoes addition reactions.
(a) The molecule cyclohexatriene does not exist and is described as hypothetical.
Use the following data to state and explain the stability of benzene compared with
the hypothetical cyclohexatriene

A

benzene is more stable than cyclohexa
expected hydrogenation of benzene is -360 but its actually -208 which is +152 kjmol-1 more stable= less exothermic. Because of delocalisation

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12
Q

Explain why amine U is a weaker base than amine W.

A

Lone or electron pair on N
No marks if reference to “lone pair on N” missing
1
Delocalised or spread into ring in U
1
Less available (to accept protons) or less able to donate (to H+
)

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13
Q

predicting a value for cycohexa 1,3 di ene where the double bonds are closer than 1.4 di ene. why is the enthalpy of hydrogenation of it lower

A

if lower enthalpy of hydrogenation= more stable more energy used to break bonds
as, the proximity for 1,3 has c=c closer together delocalisation for 1,3 which provides some extra stability for 1,3

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14
Q

when writing a equation for the reaction of a di nitro to make a di phenyl amine

A

make sure you do [12H] bc theres 2 nitros to reduce and this also forms 4h2o not 2h2o

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15
Q

bond angle in benzene and cyclohexane

A
benzene= 120
cyclohexane= 109
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