Hyperbolic Functions Flashcards

1
Q

sinh(x)

A

“shine(x)”
(e^x - e^-x) /2

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2
Q

cosh(x)

A

“cosh(x)”
(e^x + e^-x) /2

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3
Q

tanh(x)

A

(e^2x - 1)/(e^2x + 1)

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4
Q

What are the reciprocal hyperbolics and draw the graphs.

A

cosech(x)
sech(x)
coth(x)
1/the original like in trig

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5
Q

Proving inverse hyperbolic formulae

A
  1. Use the hyperbolic on both sides to write in terms of x
  2. Replace with the hyperbolic formula
  3. Form a hidden quadratic by multiplying by e^y
  4. ln both sides, only use the positive case
  5. Replace y with the inverse hyperbolic
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6
Q

What are the graphs of all the inverse hyperbolic functions?

A
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7
Q

Hyperbolic pythagorean identities

A

cosh^2x - sinh^2x = 1
sech^2x = 1 - tanh^2x
cosech^2x = coth^2x - 1

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8
Q

sinh(A+/-B)

A

sinhAcoshB +/- coshA/sinhB

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9
Q

cosh(A+/-B)

A

coshAcoshB +/- sinhAsinhB

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10
Q

tanh(A+/-B)

A

tanhA -/+ tanhB / 1 +/- tanhAtanhB

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11
Q

Osborn’s rule

A

Replace sin with sinh and cos with cosh
Put a - in front of any multiplication of sinhx (including tanh^2) (sinh^4 cancels out)

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12
Q

d/dx(coth(x))

A

-cosech^2(x)

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13
Q

d/dx(sinh(x))

A

cosh(x)

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14
Q

d/dx(cosh(x))

A

sinh(x)

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15
Q

d/dx(tanh(x))

A

sech^2(x)

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16
Q

Proving regular differentials

A

Put it into exponential form and differentiate

17
Q

Proving inverse derivatives

A
  1. x = sinh/cosh/tanh y
  2. Do dx/dy
  3. Use identities to substitute in terms of x
  4. Find the reciprocal for dy/dx
18
Q

∫sinh(x) dx

A

cosh(x) + c

19
Q

∫cosh(x) dx

A

sinh(x) + c

20
Q

∫tanh(x) dx

A

sech^2(x) + c

21
Q

∫cosech^2(x) dx

A

-coth(x) + c

22
Q

∫sech^2(x) dx

A

tanh(x) + c

23
Q

∫sech(x)tanh(x) dx

A

-sech(x) + c

24
Q

∫cosech(x)coth(x) dx

A

-cosech(x) + c

25
Q

Multiple terms in the numerator

A

Split and use standard integrals/reverse chain

26
Q

Proving ∫tanh(x)

A

use sinh(x)/cosh(x) and use reverse chain rule to ln|cosh(x)|

27
Q

Small odd powers of cosh/sinh

A

Factor out (cosh/sinh)^power-1 and use identity

28
Q

When to use the exponential definition

A

When there is an exponential term or no simpler way to integrate

29
Q

∫sech(x) or ∫cosech(x) method

A

Use exponential form, multiply by e^x and use substitution with e^x

30
Q

∫1/sqrt(a^2 + x^2) substitution

A

x = asinh(u)

31
Q

∫1/sqrt(x^2 - a^2) substitution

A

x = acosh(u)

32
Q

Completing the square

A

With a/quadratic or a/sqrt(quadratic), complete the square and use substitution with u as the thing that is squared

33
Q

cosh^2(x) substitution

A

1/2 + 1/2 cosh(2x)

34
Q

sinh^2(x) substitution

A

1/2 cosh(2x) - 1/2

35
Q

Hyperbolics to R formula

A

Use cosh^2 - sinh^2 = 1 for R rather than +