Mechanics Flashcards

1
Q

Momentum? equation

A

mass x velocity

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2
Q

Impulse? equation

A

= Force x time
= Change in Momentum

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3
Q

Restitution (e)? equation

A

Separation/Approach

v2-v1/u1-u2

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4
Q

What does it mean if Restitution (e) is 1?

A

No loss of energy

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5
Q

What does it mean if Restitution (e) is 0?

A

Stuck together

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6
Q

Work done? equation

A

Force x Distance

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7
Q

Work done if force is horizontal over a distance?

A

Force x cos(theta) x distance

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8
Q

Total work done? equal to?

A

Total Work Done= Change in Kinetic Energy

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9
Q

Gravitational Potential Energy? equation

A

-Mass x 9.8 x distance
-work done against gravity (object is raised)

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10
Q

Hooke’s law? Equation

A

Tension (T)= Lamda (λ) x Extension (x) / Natural Length (L)

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11
Q

Elastic Potential Energy? equation

A

EPE= (λ x X^2) / 2 L

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12
Q

Increase in Elastic Potential Energy?

A

Final EPE-Initial EPE

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13
Q

What is Elastic Potential Energy the same as? (EPE)

A

EPE= Work Done stretching a string

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14
Q

Power? equation

A

Power= Work Done (J) / Time (s)
= Driving Force x Velocity

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14
Q

Angular Velocity (w)? units

A

rad/s

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15
Q

rad/s to rev/s conversion?

A

2π rad/ sec = 1 rev/sec
1 rad / sec= 1/2π rev/sec

16
Q

Linear speed (v)? equation

A

Linear Speed (V)= Radius (r) x Angular Speed (w)

17
Q

Acceleration in circular motion? equation

A

Acceleration (a)= radius (r) x Angular Speed (w) ^2 a=r x w^2
= Linear Speed (v)^2 / Radius (r) a= v^2/r

18
Q

Tension for string in circle? equation

A

T = Mass (m) x Velocity (v^2) / radius (r) T = m x v^2 / r

19
Q

What is EPE lost equal to?

A

KE gained

20
Q

EPE lost?

A

Initial EPE - Final EPE

21
Q

When a string is stretched what happens to EPE?

A

-Increases , Increase in EPE = loss in KE or if dropped loss in PE (mgh)

22
Q

When a string is squashed what happens to EPE?

A

-Decreases, loss in EPE= Increase in KE

23
Q

Circular motion when does it cease? (when no more force exerted by sphere)

A

When T = 0

24
Q

What angle does circular motion complete circle

A

Theta equals 180 degrees
- Tension > 0

25
Q

Complete circle rod

A

Velocity Constant V>0 Theta is 180 degrees (no tension in a rod)

26
Q

Closest approach?

A
  • AB
  • d^2 of vector calculated
    -differentiate for t = 0
  • sub t back into d^2 to find closest distance
27
Q

Collisions vector?

A
  • AB
    -AB = 0
    -find t then sub into rA to find position of collision