Module 3 - Chapter 3 - Motion Flashcards

1
Q

State the equation to find speed

A

speed = distance / time
v = x/t

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2
Q

On a distance-time graph, what does the gradient represent

A

The gradient represents the speed of the object

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3
Q

How would you find the instantaneous speed of an object with a changing speed at a given point?

A

Draw a tangent on the graph and then use the gradient to find the speed

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4
Q

What is a vector quantity

A

A vector quantity has both magnitude and direction

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5
Q

State the equation to find average velocity

A

velocity = change in displacement / time
v = Δs/t

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6
Q

What does the gradient in a displacement-time graph represent

A

The gradient represents the velocity of the object. (the difference between velocity and speed is that velocity has a direction)

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7
Q

State the equation for acceleration

A

acceleration = change in velocity / time
a = Δv/t

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8
Q

What does the gradient of a velocity-time graph represent

A

The gradient of a velocity-time graph represents the acceleration

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9
Q

What does the area under the velocity-time graph represent

A

The area under a velocity time graph represents the displacement

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10
Q

What is the equation to find the stopping distance of a car

A

stopping distance = thinking distance + braking distance

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11
Q

What is the equation to find the thinking distance

A

Thinking distance = speed x reaction time in seconds

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12
Q

What is the value you should use for g in physics

A

9.81 m/s²

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13
Q

What are the suvat equations

A

v = u + at
s = ut + ½at²
v² = u² + 2as
s = ((v + u) / 2)t
s = vt - ½at²

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14
Q

What does each letter represent in the suvat equations

A

s = displacement
u = initial velocity
v = final velocity
a = acceleration
t = time taken

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15
Q

What happens to a projectile in the air assuming air resistance is negligible

A

The vertical velocity will change due to acceleration due to gravity, the horizontal velocity will remain constant and the horizontal displacement will change as well as the vertical displacement as long as the projectile doesn’t land at the same vertical height as when it was launched

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16
Q

How would you find the velocity of a projectile using the vertical and horizontal velocities

A

v = √vh² + vv²
actual velocity = the square root of the horizontal velocity squared + the vertical velocity squared