Topic 3 Redox reactions Flashcards

1
Q

Oxidation number

A

The charge that an ion has or the charge that it would have if the species were fully ionic.

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2
Q

Oxidation (in terms of oxidation number)

A

Oxidation results in an increase in oxidation number.

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3
Q

Reduction (in terms of oxidation number)

A

Reduction results in a decrease in oxidation number.

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4
Q

Oxidation number rules: element

A

An element in its elemental form is always zero (O2, N2, Fe, Na).

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5
Q

Oxidation number rules: compound

A

The sum of the oxidation numbers is a neutral compound must equal zero (NH3).

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6
Q

Oxidation number rules: ion

A

The sum of the oxidation numbers in an ion must equal the charge on the ion.

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7
Q

Oxidation number rules: electronegativity

A

The more electronegative element is given the negative oxidation number (NH3, CH4).

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8
Q

Oxidation number rules: hydrogen

A

The oxidation number of hydrogen is nearly always +1 except in hydrides when it -1

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9
Q

Oxidation number rules: oxygen

A

The oxidation number of oxygen is nearly always -2 except in peroxides when its -1 and when in a compound with fluorine its positive.

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10
Q

Oxidation number rules: fluorine

A

The oxidation number of fluorine is always -1

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11
Q

Oxidation equation example

A

Mg —> Mg2+ + 2e

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12
Q

Reduction equation example

A

Cl2 + 2e —> 2Cl-

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13
Q

Disproportiation

A

A simultaneous occurrence of oxidation and reduction of the same element in a single reaction.

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14
Q

Oxidising agent

A

A species that oxidises another species by removing one or more (of their) electrons. When an oxidising agent reacts it gains electrons and is therefore reduced.

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15
Q

Reducing agent

A

A species that reduces another species by adding one or more electrons. When a reducing agent reacts it loses electrons and is therefore oxidised.

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16
Q

Systemic names

A

When an element has more than one oxidation state, the name often includes the oxidation number of the element written as a Roman numeral in brackets.

17
Q

Balancing with oxidation numbers

A
  1. Use oxidation numbers to balance
  2. Now balance the H and O atoms
  3. Lastly balance the charges
    (WHE on the equation)

The equation is now balanced.