chem eqb

Question 1

The value of KC is changed by change in temperature because

Answer 1

Equilibrium position shift without any substance being added or removed
In a reversible reaction, change in temperature, change the equilibrium position. So KC depend upon temperature.

Question 2

Which sparingly soluble salt solution will be unsaturated?

Answer 2

Ksp > ionic product

Question 3

A beaker contains a saturated solution of potassium Perchlorate. When potassium chloride (KCl) is added to this solution, some of the potassium Perchlorate is precipitated. It means that

Answer 3

KCl is a stronger electrolyte as compared with KClO4
Strong electrolyte (KCl) will suppress the ionization of weak electrolyte (KClO4)

Question 4

Solubility product of BaCl2 is 4×10-9. Its solubility would be

Answer 4

BaCl­2 ⇌ Ba+2 + 2Cl–
Ksp = [Ba+2][Cl–]2 = (S)(2S)2 = 4S3
4 × 10-9 = 4S3
S3 = 1×10‑9
S = 1×10-3

Question 5

The relationship between Kp and Kc is given by

Answer 5

Kp = Kc (RT)∆n
∆n = np – nR
delta n is an exponent

Question 6

human blood maintains its pH between

Answer 6

7.3 -7.4

Question 7

theoretical yeild is calculated using

Answer 7

mass of limiting reactant

Question 8

if Qc is greater than Kc, this implies

Answer 8

reaction will reverse to achieve eqb

Question 9

Relationship bw Qp and Qv

Answer 9

Qp = Qv + nRT

Question 10

the value of ionic product of water at 25 C is

Answer 10

1 x 10^-14 mol2 dm-6

Question 11

Two electrons cannot occupy a single orbital when degenerate orbitals are available is a statement of:

Answer 11

Hund’s rule