Strengthening of crystals Flashcards

1
Q

What is the underlying principle for how materials can be strengthened and hardened?

A

By impeding dislocation movement.

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2
Q

Based on shear stress, when does slip occur?

A

When the resolved shear stress on a favourable slip plane exceeds the critical resolved shear stress.

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2
Q

What are the methods that hinder dislocation motion and strengthen the crystal material (increase yield strength, ultimate tensile strength, and hardness)?

A

Grain size reduction; solid solution strengthening; work hardening.

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2
Q

What is the relationship between grain size and yield strength and which equation demonstrates that relationship?

A

According to the Hall-Petch equation, a material’s yield strength increases as the grain size decreases.

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2
Q

Why must grain boundaries impede dislocation motion?

A
  1. Dislocations must change directions due to grain misorientation
  2. Atomic disorder at grain boundary causes discontinuity of slip planes
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3
Q

What types of solute can be used for the solid-solution strengthening method?

A

Substitutional solute and interstitial solute.

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3
Q

What is the substitutional solute?

A

A solute where the alloy atom has a similar size as host atom, and
replaces them in the crystal structure

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3
Q

What is the interstitial solute?

A

Alloy atom is smaller than the host atom, and fits into
spaces (interstices) between host atoms

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4
Q

What do substitutional atoms impose that impede dislocation motion?

A

Lattice strain

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5
Q

What are the differences between a smaller substitutional atom and a large substitutional atom?

A

Smaller substitutional atom:
* Tensile stresses in lattice
* Alloy atoms are attracted to
the upper side of the dislocation

Larger substitutional atom:
Compressive stresses in lattice
* Alloy atoms are attracted to
lower side of dislocation

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6
Q

What are the two types of interaction between the substitutional atom and dislocation?

A
  1. Alloy atoms diffuse to dislocation to pin it down
  2. Strain field interactions between a moving
    dislocation and substitutional atom
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7
Q

When is the work-hardening equation applicable?

A

From the onset of yielding up to necking.

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8
Q

What happens to the strength and hardness of a ductile metal during work hardening?

A

A ductile metal becomes stronger and harder as it is plastically deformed (work hardened), as
evidenced by increase in true stress beyond yield point

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9
Q

What is work hardening also referred to and why?

A

Work hardening is also called cold hardening because it occurs below a material’s melting
temperature; often at room temperature

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10
Q

How does work hardening impact dislocation density and dislocation-dislocation interaction?

A

Work hardening involves an increase in dislocation
density and dislocation-dislocation interaction with plastic deformation.

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11
Q

What are examples of dislocation formation sites?

A

Existing dislocations
* Internal defects
* Surface defects (scratches and nicks)

12
Q

How do dislocation-dislocation strain interactions impact dislocation motion?

A

Dislocation-dislocation strain
interactions make dislocation
motion more difficult

13
Q

According to the Hall-Petch equation,
what is the relationship between a
material’s yield strength and its grain size?

A

Yield strength increases as grain size
decreases

14
Q

What is the relationship between grain size, grain boundary area, and the impediment to dislocation motion?

A

Decreased grain size results in increase in grain
boundary area, which increases the impediment
to dislocation motion

15
Q

Why are pure metals weaker and softer than their alloys? (Written Response)

A
  • Because impurity atoms in solid
    solution impose lattice strains on the surrounding host atoms.
  • Lattice strain field interactions between dislocations and these impurity atoms result and dislocation movement is restricted.
16
Q

Why do alloy atoms diffuse to dislocation to pin it down and what is required for this to happen?

A
  • Alloy atom diffuses to a location to reduce
    strain imposed by dislocation
  • Energy is required to dissociate from low-strain regions