Lecture 5 Flashcards

1
Q

Non-Mendelian patterns include

A

allelic series where more than two alleles produce a traits (ex. ABO blood groups)

and maternal effect- determination of the phenotype by the genotype of the mother (ex. shell coiling)

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2
Q

Genetic maternal effect often arises because

A

the maternal parent produces a substance, encoded by her own genotype, that is deposited in the cytoplasm of the egg and that influences early development of the offspring.

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3
Q

shell coiling

A

in Lymnaea peregra species, most snails are dextral, but a few sinistral snails occur in some populations.

the phenotype of a snail was determined not by its own genotype but by the genotype of its mother

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4
Q

polygenetic inheritance

A

many traits are produced by more than one gene

and the genes at different loci often interact in peculiar ways to produce that phenotype

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5
Q

In the last 100 years we have learned that polygenetic determination (or inheritance) should be thought of as the rule rather than the exception for many traits such as ___

A

height, IQ, athletic ability, etc.

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6
Q

Locating and understanding the loci in polygenetic inheritance is extremely difficult because

A

1) the vast majority of loci have very little impact
2) the loci can interact with each other in many ways

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7
Q

case where a single locus that highly impacts an otherwise highly polygenic trait

A

one form of dwarfism (there are at least 300 types) results from the action of a single locus (see Achondroplasia).

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8
Q

One possible molecular mechanism for how a dominant allele, given the designation of “+” (for wild type) masks (or covers) the recessive allele.

A

while both alleles are transcribed and translated, the mutant produces a non-functional protein.

WT allele produces enough of the enzyme to complete the cellular process when heterozygous - complete dominance.

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9
Q

haplosufficient

A

is when dominate allele (in complete dominance) produce the phenotype

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10
Q

incomplete dominance produces an ____ heterozygote

A

intermediate

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11
Q

one way incomplete dominance producing an intermediate heterozygote can ocour is

A

the amount (or dosage) of a gene product (e.g. red pigment in snapdragons).

Two copies of one allele produces enough pigment to produce red color, only one produces pink. The alternative allele lacks pigment and produces white when homozygous.

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12
Q

Codominance

A

Both Alleles are Displayed ex. ABO blood group

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13
Q

Human ABO* blood groups vs locus

A

The gene product is a sugar on the surface of red blood cells.

Three possible alleles (but only two in any individual): A and B alleles are different forms of the sugar, the i allele produces no sugar.

4 possible groups

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14
Q

Rh is extremely important for preventing immune reactions between

A

mother and baby in utero.

A second pregnancy with an opposing Rh factor can cause significant immune reaction from the mother to the baby.

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15
Q

Rh+ is ____ to Rh-
Most people are ___

A

dominant
Rh+

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16
Q

Will all babies from the same couple have the same Rh factor?

A

No, consider 2 alleles for one trait

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17
Q

sickle cell where the ____ produces the affliction and strongly sickled cells.

But it is not ___ because

A

homozygous recessive

not complete dominance because hetero are slightly sickled thus, incomplete dominance. Also, in hetero both alleles produce a different form of hemoglobin. so, is co-dominace

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18
Q

William Cardozo

A

was African American
provided health care to many poor people including African Americans

established Sickle Cell as genetic trait that was passed down in via Mendelian inheritance, and that the affliction was most common in those of African descent

(also researched other childhood pathologies such a Hodgkin’s disease)

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19
Q

Two models of a dominant mutants

A

haploinsufficiency & dominant negative

20
Q

haploinsufficiency

A

where one does in insuffienct to produce the phenotype

21
Q

dominate negative

A

where the product of mutant allele is “antagonistic” to the WT product

one way for this to occur is for the mutant to form a dimer with the WT, rendering it non-functional

appears to be the case in several forms of cancer

22
Q

genetics of mice are of great interest because

A

they are much more similar to humans than many other models

23
Q

The ____ yellow coat color mutant allele in mice, also acts as a lethal when _____.

When heterozygotes are crossed the resulting ratio is ___ of iving progeny.

A

dominant
homozygous

2:1 (not 1:2:1)

24
Q

2 schools of thought on multi-locus genetic interactions/ multi-step pathways

A

1) because a mutation in a previous step will block all further steps this can be considered an interaction

2) others genes are not really interacting so much as depending on each other.

25
Q

Understanding multi-locus genetic interactions is complicated by the fact that

A

different sources define an “interaction” in different ways.

26
Q

for pepper color in the genus Capsicum

genes at two different loci interact to produce ____

A

phenotypes not seen in either homozygous parent or the F1.

note - the F1 consists of a single phenotype (Red)

27
Q

when the F1’s are crossed we observe two additional phenotypes. this is inconsistent with our expectations of ___

Because we observe a very different result ___ we have confidence that ___

A

a single locus

(if single locus F2 would be 3:1 red: cream)

9:3:3:1 (Not like before where looking at 2 diff traits (same loci for one trait). Now, 1 trait but many loci), and two novel phenotypes

there is another loci involved (i.e. C locus) and polygenetic inheritance.

28
Q

epistasis

A

One of the most common types of genetic interactions

a kind of multiple locus dominance where one locus covers or masks another locus.

29
Q

In epistasis: the dominant loci (covering) is termed ______, and the masked loci is termed ________.

A

epistatic (on top of)

hypostatic (underneath)

30
Q

Labrador retrievers occur in three color morphs___

Coat color is determined by ____

A

Black, Brown and Yellow

two interacting loci.

1st loci determines the pigment color produced in the hair shaft. (two alleles B and b, where B is dominant and produces black, and b produces brown)

2d loci (e) is epistatic to the “B” loci and determines if any pigment is put into the shaft

phenotype 9:3:4

this example (labrador) is recessive epistasis

31
Q

often a challenge to determine if a case is actually an interaction of two loci on a single trait (Capsicum), or two loci each impacting a separate trait such as Mendel’s peas.

How can we determine the genetic basis for these differences and if there is any interaction?

A

Crosses.
- o+/ ; b+/ _ is wild type orange and black (a)
- o/o; b+/
individual is black (b)
- o+/_; b/b individual is orange (c)
- o/o; b/b is albino (d)

Cross WT(a) to no color (d) get all F1 (o+/o; b+/b )
Cross F1, WT to F1, WT get 9:3:3:1 ratio of phenotypes (a,b,c,d)

indicates that black vs. orange color production are in two different (loci) and non-interfering (interacting) pathways.

two separate traits - border vs fill (that do not mix)

32
Q

general method for detecting epistatic interactions is to

A

examine the results of a F1 x F1 cross

general expectation is: if there is no epistatic interaction then the ratio should be: a 9:3:3:1

33
Q

multi-step pathway Recessive Epistasis

A

9:3:4 phenotype

Example: Collinsia flowers

two loci each (color) producing an enzyme
WT - both of the loci need at least one of the functional alleles (each act as a dominant).

either loci is homozygous for the mutant form a non-wild type flower is produced

If the homozygous mutant is at the m locus then the first step can proceed and pink results

34
Q

If the homozygous mutant is at the m locus then the first step can proceed and pink results.

Thus the w loci is said to be _____

A

epistatic (covering) the second loci (m) that is termed hypostatic

35
Q

This is “recessive” epistasis because the

A

double heterozygote remains the wild type.

36
Q

Dominant Epistasis

A

12:3:1 phenotype

example: Foxglove

W/w D/d x W/w D/d

W allele at this locus (W/W or W/w) does not allow the deposition of color (red) by a second gene (D).

only when the alternative allele (w) is homozygous that the action of the second locus (red) is uncovered in the phenotype

37
Q

double recessive epistasis

(or Interaction, Same Pathway)

A

example: blue & white flowers

ratio in the F2 of 9:7

discover two different color morphs of a flower: blue and white. Preliminary crosses indicate that the double wild type homozygote and the double heterozygote produce blue flowers but when two heterozygotes are crossed they produce a ratio of 9:7 blue to white.

The 3:3:1 produce only one phenotype.

38
Q

How can double recessive epistasis (or Interaction, Same Pathway) have 3:3:1 produce only one phenotype?

A

a regulatory gene (r) that acts to control the transcription of a second loci (a).

the wild type alleles at both loci are dominant (thus the 9)

39
Q

of haploid individuals showing a mutant non-lethal phenotype cross these to a mutagen and examine WT progeny.

What happened?

How tell what hapended?

A

1) a revertant - a mutation in the same gene that produced the initial mutant

2) suppression - a mutation in a second gene that suppresses the first mutant.

progeny x wild-type a+ (or a+/s+)

= all a+ phenotypes then - revertant
= 3 (WT):1 (OJ mutant) ratio in a haploid then - suppression

40
Q

Diploid Suppressors

A

example: Drosophila Purple Eye Mutant

F2 produce a 13:3 ratio of red to purple

Locus 1:
pd+ = WT/red dominant.
pd = mutant/purple

Locus 2:
su+ =WT/no effect
su = mutant/red. if homozygous suppresses pd (but not pd+)

F2’s: 13:3
9 pd+/ ; su+/ (red)
3 pd+/; su/su (red)
1 pd/pd; su/su (red)
3 pd/pd; su+/
(purple)

suppression there are 2 phenotypes (like double recessive epistasis)

41
Q

A modifier locus

A

changes the degree or amount of expression of second locus.

42
Q

modifier

functional a+ allele, and a mutant allele (a)

A second loci (b) regulates how much of the product (a+) is produced.

type (b+) -full production,
mutant (b) - greatly reduces the product.

what are Genotype & Phenotype for haploid

A

a+ * b+
“wildtype” (functional protein, full transcription level)
a+ * b
“defective” (low transcription of a functional protein)
a * b+
“defective” (defective protein present, but at a full level)
a * b
“extremely defective” (low transcription of a defective protein)

43
Q

Penetrance

A

yes or no (for having trait)
percent of individuals displaying the trait

44
Q

Expressivity

A

varying level (intensity) of a phenotype

45
Q

phenotype often deviates because of

A

the environment or interaction with other genes

46
Q

other important non-Mendelian phenomena that produce changes from expectations

A

Chart plus:

Epigenetics - heritable traits that cannot be explained by changes in DNA sequence.

Environmental effects