Properties of Aromatic Compounds (Acid/Base Chemistry) Flashcards

1
Q

What is pKₐ?

A

pKₐ describes how much of the acid has been deprotonated (and now exists in its conjugate base form)
It is a quantitative measure of acid strength in solution

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2
Q

What is a Bronsted acid

A

is a species with a tendency to lose a proton

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3
Q

What is a Bronsted base

A

is a species with a tendency to accept a proton

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4
Q

The lower the pKₐ….

A

the strong the acid

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5
Q

How do you work out the pKₐ from Ka

A
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6
Q

How can you work out Ka

A

Using the concentration of [H⁺]² in the solution over the concentration of the acid

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7
Q

What are the 3 main factors which affect the strength of an acid

A

1) The stability of the conjugate base A¯
2) The H-A bond strength
3) The solvent

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8
Q

What two factors effect th stability of the conjugate base A¯

A

1) how electronegative A is
2) inductively and mesomerically (resonance) electron-withdrawing substituents stabilise A¯ (making HA a stronger acid)

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9
Q

What factor effect the H-A bond strength?

A

H-A bond strength decreases down the periodic table
(size/energy mismatch of atomic orbitals) making it easier for the bond to break

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10
Q

How does the solvent effect the strength of an acid?

A

The better the solvent is at solvating/stabilising ions, the easier it is for the acid to be deprotonated

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11
Q

How is the strength of a base traditionally measured

A

pKₐₕ: the pKₐ of its conjugate acid

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12
Q

a lower pKₐₕ means

A

a stronger acid, hence a weaker base

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13
Q

How to you work out Kₐₕ

A

by dividing the concentration of the [base] over the concentration of [H⁺]²

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14
Q

Any factor that increases the strength of an acid usually decreases the strength of the corresponding conjugate base
Hence what are the main factors which affect the strength of a base?

A

Is the availability of its lone pair of electron
The stability of the conjugate acid (the more stable the conjuate acid, the stronger the base)

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15
Q

What two factors effect the availablity of a bases lone pair of electrons

A
  • How electronegative it is
  • Inductively and mesomerically electron-withdrawing substituents make B a weaker base
    Therefore the lone pair is less available for reaction with H⁺
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16
Q

Which is the weaker base and why?

A

Cyclohexylamine: pKₐₕ = 10.7
aniline: pKₐₕ = 4.6 (weaker base)
Lower basicity of aniline is due to the partial delocalisation (sp³) of the Nitrogen LP into armatic ring

17
Q

what are the pKₐₕ values of the para-substitueted anilines

A

the NO₂ is electron withdrawing, therefore LP is less available = lower pKₐₕ
Chlorine is highly electronegative, therefore LP is less available = lower pKₐₕ
Methoxy pushes electrons into the ring making it more electron rich, increasing availability of LP = higher pKₐₕ

18
Q

which out of cyclohexanol and phenol is more acidic

A

Cyclohexanol: pKₐ = 16
Phenol: pKₐ = 10
Higher acidicity of phenol is due to resonance stabilisation of the conjugate base

19
Q

What is the acidity of methane like, relative to toluene and diphenylmethane

A

methane: pKₐ = 50
toluene: pKₐ = 40
diphenylmethane: pKₐ = 33
the methyl anion is stabilised by delocalisation resulting in methyl groups attached to aromatic rings more acidic than simple aliphatic methyl groups

20
Q

What is the acidity of ethanoic acid like relative to benoic acid

A

ethanoic acid: pKₐ = 4.76
benzoic acid: pKₐ = 4.2 (only a little more acidic)
This is because it is not possible to stabilise the benozoic acid anion by conjugation into the ring

21
Q

How is it possible to affect the acidicity of benzoic acid

A

by adding subsituents
adding electron-withdrawing substituents will increase the acidicity (positive σ value)
adding electron-donating substituents will decrease the acidicity (negative σ value)

22
Q

What is the substituent constant (σ) realtive to benzoic acid

A

positive σ-values are more acidic (lower pKₐ than benzoic acid)
negative σ-values are less acidic (higher pKₐ than benzoic acid)

23
Q

Using the Hammett reationship, how would you work out the substituent constant-σ (e.g. for benzoic acid)

A
24
Q

What does the reaction constant ρ tell us

A

what effect electron-withdrawing or electron-donating substitents have on reaction rate
hence giving us an idea about the mechanism of the reaction

25
Q

you can work out the reaction constant (ρ) from the gradient of substituent constant-σ over rate constant
a positive ρ value would mean?

A

a positve ρ value means that electron-withdrawing substiuents increase the reaction rate
i.e. there is a build-up of negative charge in the transition state of the RDS which is stabilised by the electron-withdrawing group

26
Q

you can work out the reaction constant (ρ) from the gradient of substituent constant-σ over rate constant
a negative ρ value would mean?

A

a negative ρ value means that electron-donating substituents increase the reaction rate
i.e. there is a build-up of positive charge in the transition state of the rate determining step
which is stabilised by the electron-donating group

27
Q

What do the Hammett parameters describe?

A

how the structure of aromatic compounds affect their reactivity

28
Q

What is a flaw with the Hammett approach

A

The effect of the substituents is purely electronic
The Hammett appraoch does not work for orth-substitents due to steric effects