Inorganic I - p1 Flashcards
Give an equation for the reaction of solid sodium bromide with concentrated sulfuric acid to form bromine.
State one observation made during this reaction.
M1 2H2SO4 + 2NaBr → Na2SO4 + SO2 + Br2 + 2H2O
allow ionic and equation forming NaHSO4
3H2SO4 + 2NaBr → 2NaHSO4 + SO2 + Br2 + 2H2O 2H+ + 2Br- + H2SO4 → SO2 + Br2 + 2H2O
not equation from HBr unless formation of HBr shown in separate equation
1
M2 orange/brown fumes/solution
A solution that is thought to contain chloride ions and iodide ions is tested.
- Dilute nitric acid is added to the solution.
- Aqueous silver nitrate is added to the solution.
- A pale yellow precipitate forms.
- Excess dilute aqueous ammonia is added to the mixture.
- Some of the precipitate dissolves and a darker yellow precipitate remains.
Give a reason for the use of each reagent.
Explain the observations.
Give ionic equations for any reactions.
HNO3 removes (hydroxide/carbonate) ions that may give other ppts with AgNO3
1
AgNO3 produces ppts with chloride/iodide/halide
not chlorine/iodine/halogen
1
Ag+(aq) + Cl−(aq) → AgCl(s) OR
Ag+(aq) + I−(aq) → AgI(s)
allow Ag+(aq) + X−(aq) → AgX(s)
state symbols not required but not if wrong
1
NH3 dissolves AgCl (leaving yellow AgI)
allow chloride/iodide salt/ppt
1
AgCl(s) + 2NH3(aq) → Ag(NH3)2+(aq) + Cl−(aq)
allow with Ag+(aq)
State what is observed when silver nitrate solution is added to sodium fluoride solution.
State one observation when solid sodium chloride reacts with concentrated sulfuric acid.
Give an equation for the reaction.
State the role of the chloride ions in the reaction.
M1 Misty or steamy or white fumes/gas
1
M2 NaCl + H2SO4 → NaHSO4 + HCl OR 2NaCl + H2SO4 → Na2SO4 + 2HCl
M3 Base OR proton acceptor
Give an equation for the redox reaction between solid sodium bromide and concentrated sulfuric acid.
Explain, using oxidation states, why this is a redox reaction.
M1 2NaBr + 2H2SO4 → Na2SO4 + Br2 + SO2 + 2 H2O OR
2Br- + 2H+ + H2SO4 → SO2 + Br2 + 2H2O
M1 Allow ionic equations
2Br – + 2H2SO4 → Br2 + SO42– + SO2 + 2H2O OR
2Br – + 4H+ + SO42- → Br2 + SO2 + 2H2O
1
Br changes oxidation state from −1 to 0 and is oxidised
1
S changes oxidation state from +6 to +4 and is reduced
State what is observed when aqueous chlorine is added to sodium bromide solution.
Give an ionic equation for the reaction.
M1 Yellow or orange solution
M1 Do not accept brown solution
1
M2 Cl2 + 2 Br – → 2 Cl – + Br2
Chlorine is used to treat water even though it is toxic to humans.
Give one reason why water is treated with chlorine.
Explain why chlorine is added to water even though it is toxic.
Give an equation for the reaction of chlorine with cold water.
Reason: sterilise water / disinfect water / kill bacteria / kill microorganisms / kill microbes
1
Explanation: health benefit outweighs risk / only used in small quantities/low concentrations
1
Equation:
Cl2 + H2O ⇌ HCl + HClO
Write the simplest ionic equation for the reaction between chlorine and aqueous potassium bromide.
State what is observed when this reaction occurs.
M1 Cl2 + 2Br−> 2Cl- + Br2
Accept a correct equation using ½ Cl2 but no other multiples
M2 solution goes orange / yellow ( from colourless)
Write an equation for the equilibrium reaction that occurs when chlorine gas reacts with cold water.
Give one reason why chlorine is used for the treatment of drinking water even though the gas is very toxic.
M Cl2 + H2O EQ ARROW HClO + HCl
(HOCl)
Equilibrium symbol required in M1
Accept ionic RHS
M2
The (health) benefit outweighs the risk or wtte
OR
a clear statement that once it has done its job, little of it remains
OR
used in (very) dilute concentrations / small amounts / low doses
Sodium bromide reacts with concentrated sulfuric acid in a different way from sodium chloride.
Write an equation for this reaction of sodium bromide and explain why bromide ions react differently from chloride ions.
2NaBr + 2H2SO4 -> Na2SO4 + Br2 + SO2 + 2H2O
Allow ionic equation
2Br– + 2H2SO4 Br2 + SO42– + SO2 + 2H2O
1
Br– ions are bigger than Cl– ions
1
Therefore Br– ions more easily oxidised / lose an electron more easily (than Cl– ions)
A colourless solution contains a mixture of sodium chloride and sodium bromide.
Using aqueous silver nitrate and any other reagents of your choice, develop a procedure to prepare a pure sample of silver bromide from this mixture. Explain each step in the procedure and illustrate your explanations with equations, where appropriate.
Indicative chemistry content
Stage 1: formation of precipitates
- Add silver nitrate * to form precipitates of AgCl and AgBr * AgNO3 + NaCl → AgCl + NaNO3 * AgNO3 + NaBr → AgBr + NaNO3
Stage 2: selective dissolving of AgCl
- Add excess of dilute ammonia to the mixture of precipitates * the silver chloride precipitate dissolves * AgCl + 2NH3 → Ag(NH3)2+ + Cl−
Stage 3: separation and purification of AgBr
- Filter off the remaining silver bromide precipitate * Wash to remove soluble compounds * Dry to remove water
Does atomic radius increase/decrease down group 2
Increases
Does atomic radius increase/decrease down group 2
Increases
Do the reactions with water in group 2 increase or decrease down the group
Decrease
Group 2 reaction with liquid water - Mg
Mg (s) + H2O (l) —> Mg(OH)2 (aq) + H2 (g)
Group 2 reaction with steam - Mg
Mg(s) + H2O(g) –> MgO(s) + H2(g)
Observations with Mg and steam
white solid - MgO
bright light
Extraction of Ti from TiCl4
TiCl4 + 2Mg 2MgCl2 + Ti
Solubility of group 2 hydroxides ….. down the group
Increases
Mg and OH- reaction
Mg2+(aq) + OH−(aq) à Mg(OH)2(s)
Observation with Mg and OH-
white precipitate forms
How to test for the presence of Mg2+ in a solution
NaOH (aq)
How to test for the presence of OH- in a solution
Mg(NO3)2 (aq)
Use of MgOH
Indigestion relief
Use of barium sulphate
Taking x-rays of the stomach
Barium meal
How to test for the presence of Ba2+ in a solution
H2SO4
How to test for the presence of SO42- in a solution
BaCl2
Observation with barium and sulfates
white precipitate
Ba2+ and SO42- equation
Ba2+(aq) + SO42−(aq) à BaSO4(s)
Solubility of group 2 sulphate …. down the group
Decreases
Melting point ….. down group 2
Decreases
Flue gas removal
Ca(OH)2 use
Neutralise soil
State an observation when Mg reacts with steam
Give the equation, including state symbols
Bright light / white light / white powder/ash/solid
1
Mg(s) + H2O(g) → MgO(s) + H2(g)
Describe the bonding in Mg
M1: Attraction between (lattice of) Mg2+ ions
M1 attraction between nucleus and delocalised
electrons or between + ions and delocalised
electrons
1
M2: And delocalised electrons
Explain, in terms of bonding and structure why MgCl has a high melting point
(Giant) ionic lattice / lots of Mg2+ and Cl–
ions
1
Strong (electrostatic) forces of attraction
1
Between Mg2+ and Cl–
ions
Allow oppositely charged ions
Give a medical use of MgOH
Indigestion relief / laxative / neutralise (excess stomach) acid
Allow milk of magnesia
Use of barium sulphate
In medicine to produce an X-ray image
Explain why the melting point of Mg is higher than the melting point of Na
Mg2+ has a higher charge than Na+
/ Mg2+ ions are smaller / Mg2+ has a
greater charge density / Mg atoms smaller than Na atoms / Mg has more
delocalised electrons than Na
Allow
Mg has a higher nuclear charge
1
Stronger attraction to delocalised sea of electrons / stronger metallic
bonding
Give an equation to show how Mg is used as a reducing agent in the extraction of titanium
Explain, in terms of oxidation states why Mg is the reducing agent
2Mg + TiCl4 → 2MgCl2 + Ti
Allow multiples
1
Mg changes oxidation state from 0 to +2 so electrons are lost / Ti changes
oxidation state from +4 to 0 , so gains electrons
Allow
Oxidation state of Mg increases so it is a reducing
agent
Give the observation why dilute, aq NaOH is added to separate solutions of MgCl2 and BaCl2
MgCl- white ppt
BaCl2- no visible change/ colourless solution/ no reaction
Give an eqaution for the reaction between titanium chloride and magnesium
state the role of magnesium in this reaction
Equation: 2 Mg + TiCl4 → Ti + 2 MgCl2
Allow multiples / ignore ss
1
Role: Reducing agent
Give the full electronic configuration of Ca2+
Explain why the second ionisation of calcium is lower than the second ionisation energy of potassium
M1 In Ca(+) (outer) electron(s) is further from nucleus
Or Ca(+) loses electron from a higher (energy) orbital
AQA Chemistry A-Level - Group 2 Metals MS PhysicsAndMathsTutor.com
Page 4 of 8
Or Ca(+) loses electron from a 4(s) orbital or 4th energy level or 4th
energy shell and K(+) loses electron from a 3(p) orbital or 3rd energy
level or 3rd energy shell
Must be comparative
Allow converse arguments
1
M2 More shielding (in Ca+
)
Identify the s-block metal with the highest first ionisation energy
Be
Give the formula of the hydroxide of the element in group 2, from Mg to Ba that is the least soluble in water
Mg(OH)2
Give an equation and two observations made for the reaction that occurs when sodium is heated in oxygen.
4Na + O2 → 2Na2O
Yellow/orange flame/light AND
white solid/powder/smoke/fumes/ash
Give an equation and one observation made for the reaction that occurs when phosphorus is heated in oxygen.
Equation 4P + 5O2 → P4O10 / P4 + 5O2 → P4O10
white flame/light OR white fumes/smoke/solid/powder/ash
Explain the increase in melting point from sodium oxide to magnesium oxide.
Greater/increased charge/charge density on magnesium ion/Mg2+ (specific mention of ion(s) can be scored from M2)
Ignore atomic radius
If mention of molecules, intermolecular forces, metallic bonding then CE=0
Stronger attraction for anions/oxide ion / stronger attraction between oppositely charged ions/ stronger attraction between Mg2+ and O2– / stronger ionic bonding
Explain why the melting point of the oxide of silicon is much higher than that of the highest oxide of phosphorus.
(SiO2) giant covalent / macromolecular
(P4O10) (simple) molecular
(Covalent) bonds (throughout structure) of SiO2 much stronger than the forces between molecules/intermolecular forces in P4O1
A sample of the highest oxide of phosphorus was prepared in a laboratory.
Describe a method for determining the melting point of the sample.
State how the result obtained could be used to evaluate its purity.
M1 Sample in suitable melting point apparatus (e.g. capillary in oil bath/Thiele tube / melting point apparatus)
M2 Heat slowly/gradually/gently (to establish melting point range)
M3 Lower melting point / (broad) range of melting point indicates presence of impurities
OR melting point agrees with/close to data book value / melts sharply/over narrow range / melting point exactly 573K indicates purity
Write an equation for the reaction of phosphorus with an excess of oxygen.
P4 + 5 O2 → P4O10
Describe a test you could carry out in a test tube to distinguish between sodium oxide and the product of the reaction in part
React with water / add water / solution (of substances in question)
Add litmus paper / universal indicator / measure pH (with pH meter)
pH meter or Universal Indicator: sodium (hydr)oxide (solution) has a higher pH (than phosphorus oxide (solution))
sodium (hydr)oxide pH (12 to 14) and phosphorus oxide (solution) pH (-1 to 2)