Magnetic fields (unit 4) Flashcards

1
Q

Number of times proton moves between a gap in a cyclotron?

A

ev divided by pd

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2
Q

How to work out where the force acts ON the wire?

A

-Fleming’s left hand rule

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3
Q

How to work out force acting on the current carrying wire?

A

-BIL sin theta

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4
Q

How to work out force for individually charged particles?

A

-BQV sin theta

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5
Q

Unit for magnetic field?

A

-Tesla (T)

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6
Q

How does Hall Voltage work?

A

-When a current flows at 90° through a magnetic field, there
will be a force on the electrons
-forcing them to one surface of the conductor.
-causing one surface to become negative and the other positive.
This creates an electrical field between the surfaces and cause
a force on the electrons in the opposite direction.
-the magnetic force and the electrical force will balance and an equilibrium is
reached.
-Hall voltage is the pd between surfaces at this equilibrium

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7
Q

How to work out Hall Voltage?

A

Hall Voltage =Bvd

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8
Q

What does the magnetic field look like in a straight wire?

A
  • circles going around wire ( use right hand grip rule to determine direction of field)
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9
Q

What does the magnetic field look like in a solenoid?

A
  • looks like a bar magnet (direction is the same as direction of current)
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10
Q

How to work out B in a wire?

A
  • B = π µ 0 I/ 2 pi a

a is the distance from wire (radius for where you want field)

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11
Q

How to work out B in a solenoid?

A

-B = μo nI

n is number of turns per meter
n= number of turns/ length

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12
Q

How to increase field strength in a solenoid?

A

-adding an iron core

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13
Q

How do parallel current carrying wires exert a force on eachother?

A
  • When a current passes through a wire it creates a magnetic field.
    -the top wire will have a magnetic FIELD towards the bottom one (right hand grip rule)
    -As current perpendicular to this field, due to LHR bottom wire there is a force on top wire from bottom
    -due to Newton’s third law , there will be an equal force emitted by both wires on each other
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14
Q

What happens when putting a charged particle in a uniform magnetic field?

A

-Magnetic forces always act perpendicular to the motion. Therefore,
the magnetic force acts as a centripetal force and makes the charges
move in a circular path.

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15
Q

How to work out B field in uniform magnetic field?

A

BQV= mv^2/r

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16
Q

What happens when putting a charged particle in a uniform electric field?

A

-The electrical force between two parallel plates is constant due to the uniform electric field.
- the force acting on the electron here, will cause a vertical acceleration but not
change its horizontal velocity.

17
Q

How do particle accelerators work?

A

-when the force and motion are in the same direction, the particle will gain kinetic energy as it is accelerated by the electric field
- use an alternating p.d. to accelerate the particles in the gaps between electrodes.

18
Q

How to work out increase in KE in a particle accelerator?

A

-q x PD

19
Q

How to work out acceleration in uniform electric field?

A
  • F=ma
    -qv/d = ma
20
Q

Linear particle accelerator?

A
  • path - straight line
  • magnetic field - none
    -alternating PD - Constant, increasing length of tube ensuresthe p.d. changes in time
21
Q

Cyclotron particle accelerator?

A
  • path - Circular but with increasing radius
    -magnetic field - Constant, to ensure circular motion
    -alternating PD - Constant, increasing path length ensures the p.d. changes
    in time
22
Q

Synchotron particle accelerator?

A

-path - Circular, constant radius
-magnetic field - Increasing to ensure circular motion with constant r
-alternating PD - Increasing

23
Q

How to work out frequency for a CYCLOTRON and SYNCHOTRON?

A

F = BQ/2piM

24
Q

How to derive equation for frequency for CYCLOTRON and SYNCHOTRON?

A

BQV= mv^2/r
v=ωr and ω=2πf

25
Q

What direction does conventional current flow?

A

-opposite flow of electrons

26
Q

INVESTIGATION OF MAGNETIC FLUX DENSITY USING A HALL PROBE practical ?

A

-Place the Hall probe into a known magnetic field, B1 and note the Hall potential difference, V1
-Then place the Hall probe in the centre of a solenoid
-Ensure, in both cases, the probe is at 90o to the magnetic field
- Again measure the Hall potential difference, V2 when the probe
is in the solenoid
The unknown magnetic field of the solenoid, B2, can be found using
𝐵2 =(B1 V1) /V2