Week 7 Range Equation Flashcards

Range Equation

1
Q

The elapsed time from pulse creation to pulse reception is

A

go-return time or time of flight

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2
Q

How is time of flight and how deep a pulse travels related?

A

Directly

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3
Q

Greater distances…….

A

Prolong the time of flight

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4
Q

depth of a reflector formula

A

mm= 1.54mm/us x go-return time (us)/2

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5
Q

13 Microsecond rule

A

for every 13 Microseconds of go-return time, the object creating the reflection is 1 cm deeper in the body.

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6
Q

Total distance traveled

A

is twice the reflector depth

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7
Q

13 us time of flight is equal to…..

A

Reflector depth = 1 cm
Total distance traveled = 2 cm

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8
Q

26us time of flight is equal to

A

reflector depth = 2 cm
Total distance traveled = 4 cm

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9
Q

When a sonographer adjust a systems maximum imaging depth…..

A

PRP is altered

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10
Q

PRP is

A

Go return time of a sound pulse between the transducer and the bottom of the image.

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11
Q

Depth of view is shallow

A

PRP is short

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12
Q

Depth of view is deep

A

PRP is long

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13
Q

How are PRP and depth of view related?

A

Directly Related

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14
Q

PRP formula

A

PRP (us)= imaging depth (cm) x 13 us/cm

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15
Q

When depth of view is 10 cm, what is PRP ?

A

130 microseconds

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16
Q

How are PRF and maximum imaging depth related?

A

Inversely

17
Q

PRF formula

A

PRF (Hz)= 77,000cm/s / imaging depth (cm)

18
Q

When depth of view is shallow

A

PRF is High

19
Q

When depth of view is deep

A

PRF is low

20
Q

When depth of view is set to 7.7 cm PRF is what?

A

10,000 Hz
77,000/7.7

21
Q

When depth of view is set to 15.4 PRF is what

A

5,000 HZ
77,000/15.4

22
Q

A sound wave is created by a transducer, reflects off an object and returns to the transducer. The go-return time is 26 us. What is the depth of the reflector

A

2 cm

2cm x 13us =26us

23
Q

The maximum imaging depth during an ultrasound exam is 10 cm. The sonographer adjusts the imaging depth to 20 cm, what happens to the PRP?

A

it doubles