Topic 1 - Quantum - Additional specification information Flashcards

1
Q

3.2.2.2 - Collisions of electrons with atoms - additional information - ABOUT measuring ionisation energy.

A
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2
Q

What is measuring ionisation energy about?

A

Measuring the energy needed to ionise a gas atom.

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3
Q

What does the investigation of measuring the energy needed to ionise a gas atom include?

A

High speed electrons colliding with gas atoms in a sealed tube.

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4
Q

How is the high speed electron movement for collision created?

A

electrons are emitted from heated filament, and are attracted positive anode plate.

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5
Q

In the investigation of measuring ionisation energy of gas atoms, why does the gas need to be at sufficiently low pressure?

A
  • Prevent too many atoms being present.
  • As too many atoms would stop electrons from reaching anode side.
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6
Q

How would we increase the speed of the electrons?

A

By increasing the p.d. between the anode and filament.

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7
Q

When does the ammeter in the external circuit of the investigation get a current reading?

A

When the electrons from the filament reach the anode, and produce a charge flow in the external circuit.

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8
Q

When does ionisation occur, given that the electrons have been emitted from the heated filament in the tube?

A
  • Electrons need to reach certain speed.
  • As the electron arrives at anode to ionise gas atoms with enough KE.
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9
Q

What is the equation to calculate the ionisation of a gas atom in this experiment, given the p.d.

A

Ionisation energy of a gas atom = eV.

e = charge of electron.
V = p.d. between filament and anode when the current begins to increase, in the external circuit.

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10
Q

Why does the anode need to be positive relative to the filament?

A

To attract negatively charged electrons from the filament.

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11
Q

3.2.2.2 - Collisions of electrons with atoms - additional information - ABOUT deriving the equation for ionisation energy.

A

Electron-volt = energy gained by an electron when it has moved through a p.d. of 1 volt.

work done on charge = qV.

charge = q = e.

Therefore, the work done = qV = eV = electron-volt.

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