Passive Renal reabsorption and renal clearance Flashcards

1
Q

What affects the passive reabsorption of substances?

A

1.Electrochemical gradient force (helps with diffusion across a membrane)
2. Permeability of the membrane
3. Time (how long a substance stays in tubules)

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2
Q

Water reabsorption

A

-passive in the kidneys
-due to high intercellular concentration of solutes and high permeability of cells

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3
Q

Where does water reabsorption occur?

A

-through cells transcellularly and through tight junctions paracellularly

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4
Q

Solvent drag

A

-mechanism for the reabsorption of some solutes along water osmosis transfer. Basically water drags solutes in with it

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5
Q

Water permeability

A

-variable in distal tubules, collecting tubules, and collecting ducts due to ADH

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6
Q

Chloride Reabsorption methods

A

1.Na reabsorption causes a positive electrical charge gradient between the lumen and intercellular space. Leads to passive diffusion of Cl though paracellular pathway
2. Reabsorption of water after Na causes the Cl concentration gradient to increase and allows for passive Cl diffusion
3. Cl reabsorption also occurs by secondary active mechanism (co-transport with Na)

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7
Q

Urea reabsorption

A

-some reabsorption can occur due to concentration gradient but cells are not very permeable to urea
-water reabsorption causes an increase in luminal urea concentration which results in some passive reabsorption of urea

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8
Q

Na reabsorption and gradient-time transport pattern reasons

A

1.High capacity of Na/K pumps
-keeps low Na inside the cells, creating favorable concentration gradient
2.Leak of Na back into tubules because interstitial fluid Na levels is high due to ATP pump so Na wants to return back.

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9
Q

Renal clearance

A

-rate of clearing substance from plasma
-expressed as the volume of plasma that is completely cleared of a substance per time (mL/min)

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10
Q

What is renal clearance used to assess?

A

-assessment of excretory function of the kidney

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11
Q

Renal clearance example

A

-Have 60mL of plasma running through kidney. Every 10mL has 1mg of substance X
-Only 30mL of plasma is cleared of substance X in 10 minutes. Therefore 3mg of substance X is cleared, and the other 3mg of substance X continues in renal vein

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12
Q

How can we determine the concentration of substance X within the renal vein?

A

-Cannot take blood sample from renal vein to calculate substance X or renal clearance
-Need to take urine sample and calculate the amount of substance X present

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13
Q

Excretion rate

A

-how much substance X is excreted per time
-determined though flow rate and concentration of substance X in urine

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14
Q

Clearance Rate equation

A

Clearance rate=(urine concentration of substance)(urine flow rate)/ Plasma concentration of substance

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15
Q

Substance is freely filtered, none reabsorbed

A

-all substance in the filtrate is excreted
-since all plasma is reabsorbed clear from substance, the clearance rate=GFR

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16
Q

What substances are freely filtered?

A

-inulin (a plant polysaccharide)
-can be injected intravenously and then measured in urine to calculate clearance rate
-can also be used to calculate GFR

17
Q

Creatinine

A

-produced by body and can be used to estimate GFR

18
Q

Substance is freely filtered and all is reabsorbed

A

-none of the substance in the filtrate is excreted
-since almost all plasma is reabsorbed, there is no volume of plasma cleared from that substance and its clearance rate is 0

19
Q

Example of a substance that is freely filtered and all is reabsorbed

A

glucose

20
Q

Substance is freely filtered, none reabsorbed, and excess is secreted

A

-amount excreted is filtered amount plus secreted amount of that substance
-Therefore clearance of the substance is more than the GFR
-Example: H+

21
Q

Para-aminohippuric acid, PAH

A

-almost completely cleared (90%) from the blood that enters the kidney (filtration, no reabsorption, high secretion)
-Therefore clearance is similar to renal plasma flow (more than GFR) and its clearance can be used as an estimate of renal/blood flow

22
Q

Pressure natriuresis

A

-increase in Na excretion due to increases in arterial pressure

23
Q

Pressure diuresis

A

-increase in water excretion due to increases in arterial pressure

24
Q

Why do changes in arterial pressure between 80-170 mm Hg not significantly affect renal blood flow and GFR?

A

-Because when arterial blood pressure increases, there will be increased water and Na excretion to bring blood pressure back to normal.

25
Q

Autoregulatory mechanisms

A

-maintains GFR
- pressure natriuresis and pressure diuresis can both help if autoregulatory mechanisms are impaired

26
Q

Impaired GFR autoregulation leads to:

A

1.Significant increase in GFR and urine output
2.Reduced reabsorption of Na and water
3.Reduced Ang II formation (important for enhancing Na reabsorption and if reduced, more Na and water is excreted)

27
Q

Factors needed to reduce reabsorption of Na and Water occurs (pressure natriuresis and pressure diuresis)

A

1.renal arterial pressure increases
2.hydrostatic pressure of peritubular capillaries increases
3.hydrostatic pressure of renal interstitial fluid increases
4.Increases leak of Na and water back into tubules (instead of going to capillaries)