PAG 01.1 Comparing Methods Of Determining g Flashcards

1
Q

What is meant by free-fall?

A

An object is said to be falling in free fall if the only forces acting on it is gravity. This means that no resistive forces are acting (or in practice they are considered negligible)

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2
Q

What is g?

A

Gravitational Field Strength (in our case, on the surface of Earth)

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3
Q

Why can the SUVAT equations be used in this experiment?

A

The object will fall with uniform acceleration. This is because the force of gravity is constant at the Earth’s surface

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4
Q

When plotting a graph of t^2 against h, how is g determined?

A

The gradient will be t^2/h
Acceleration=g=2/gradient
From equation s=ut+1/2at^2

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5
Q

When plotting a graph of v^2 against h, how is g determined?

A

Gradient is v^2/h
Acceleration=g=1/2 gradient
v^2=u^2-2as

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6
Q

Describe how an electromagnet system can be used to determine g

A

A magnetic ball bearing can be released by an electromagnet clamped at a known height. The timing system starts when the electromagnet is switched off, and the timer is stopped when the ball lands on the finish

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7
Q

When using a clamp stand in this experiment, what safety precaution should be taken?

A

The clamp stand should have a counterweight or G-clamp attached to its base to provide a moment to prevent is toppling over

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8
Q

What safety precaution should be taken when using an electromagnet?

A

Electromagnets heat up over time. To reduce this heating effect, you should switch it off when not in use

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9
Q

Suggest how light-gates could be positioned to ensure that the ball or dowel falls directly through them.

A

A plumb line could be used to demonstrate the expected path of the object. This allows the light-gates to be positioned in appropriate places so that the ball will fall through them.

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10
Q

Why is it advantageous to use a small ball-bearing over a larger ball?

A

The smaller the ball, the smaller the effects of air resistance. In the case of a small ball-bearing these effects can be considered negligible

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11
Q

Why should there be a gap between the release position and the first light gate?

A

There should be a gap to ensure that the time over which the ball is passing through the light gate it negligible (the ball is moving sufficiently quick enough)

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12
Q

Explain why this experiment would not be valid if the air resistance acting on the ball wasn’t negligible

A

The ball wouldn’t be in free-fall since the acceleration would not be purely due to the force of gravity. The acceleration would also be variable since air resistance increases its speed, and so the uniform acceleration equations couldn’t be used

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13
Q

Suggest why your obtained value of g may not be the same as the accepted value

A

Delays with timing equipment (stopwatch; human reaction time)
Resistive forces are acting
Errors in height measurements, such as measuring from different positions on the ball each time

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14
Q

What is the advantage of using light gates over a stop clock in this experiment?

A

Using light gates should result in a lower uncertainty in your time measurements. A stop clock will involve human reaction times

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15
Q

How could your results be improved?

A

Take repeat readings at each height then calculate the mean time taken. Ensure that height measurements are taken from the same position each time

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16
Q

How should you calculate the uncertainty in your time readings?

A

The uncertainty in time will be equal to half the range of the time readings. This can then be converted into a percentage uncertainty

17
Q

How do you determine the percentage uncertainty in t^2?

A

To calculate the percentage uncertainty for a variable that is squared, you double the percentage uncertainty of the variable itself. The percentage uncertainty in t^2 is double the percentage uncertainty in t

18
Q

What is the minimum number of repeat readings you should take in this experiment?

A

At least 3 repeat readings at each height
This allows for anomalous results to be more easily identified

19
Q

What is the equation used to convert an uncertainty into a percentage uncertainty?

A

(Uncertainty/mean value)x100

20
Q

How can the percentage difference between your value of g and the accepted value be calculated?

A

(Your value-9.81)/9.81x100

21
Q

Would you expect your value of g to be greater or lower than the accepted value?

A

Lower, due to air resistance reducing the downwards resultant force acting on the object