Fires 3 Flashcards

1
Q

White Phosphorus

A
  • Produces a very hot fire, loads of smoke
  • P4 = oxidation state of 0
  • When a dish is placed over the phosphorus, part of the fire triangle is lost (oxygen), and the flame is extinguished
  • As soon as the dish is removed the oxygen returns and the species can set on fire again right away
  • it is a pyrophoric species
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2
Q

What is a pyrophoric species?

A

A species which has a low ignition energy
* Ignites spontaneously in air

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3
Q

White phosphorus smoke grenades

A
  • Can obscure the ability for targeting
  • Because you get a burst of light, it can be used as a tracer fire to see where things are going
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4
Q

Why is it forbidden to use white phosphorus smoke grenades on people?

A
  • It will stick to peoples skin
  • Very hot
  • It self-ignites at 32 C and our body temps are 37 C so it will continue to burn
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5
Q

What should you do if you are exposed to white phosphorus and on fire?

A
  • Use copper sulphate solution (aq)
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6
Q

How does aqueous copper sulfate quench white phosphorus?
P4 + CuSO4 –> H3PO4 + Cu + H2SO4

A
  • P4 –> PO4 (oxidised)
  • CuSO4 –> Cu + SO4 (reduced)
  • Balance the equations: P4 + 16 H2O –> 4 H3PO4 | 10 CUSO4 –> 10 Cu + 10 H2SO4
  • Final equation: 𝑃4 + 10𝐶𝑢𝑆𝑂4 + 16𝐻2𝑂 → 4𝐻3𝑃𝑂4 + 10𝐶𝑢 + 10𝐻2𝑆𝑂4
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7
Q

What is required to get to the transition state?

A

activation energy

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8
Q

What is the heat of combustion?

A

energy released during combustion

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9
Q

What does ∆𝐻 mean?

A

change in enthalpy

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10
Q

What does the f and c mean when it is next to ∆𝐻?

A
  • f = change in enthalpy of formation
  • c = change in enthalpy of combustion
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11
Q

What does ∆𝐻𝑐∘ mean?

A
  • the enthalpy change of combustion measured under standard conditions
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12
Q

Why is ∆𝐻𝑐∘ negative?

A

because heat is given out - energy is lost from the system

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13
Q

What are the products of combustion?

A

CO2 and H2O

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14
Q

How do you work out ∆𝐻𝑐∘?

A

from the values of standard enthalpies of formation using Hess’s law

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15
Q

What is enthalpy of formation?

A

the change of heat in a system to form that material from its basic elements
* if they are already in their basic form then they dont require any energy to stay in that form

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16
Q

What is Hess’s law?

A

the enthalpy change for a reaction is independent of the route by which the reaction is achieved but depends only on the initial and final stages

17
Q

What is the equation for Hess’s law?

A

∆𝐻=[∑∆𝐻𝑓∘(𝑝𝑟𝑜𝑑𝑢𝑐𝑡𝑠)] − [∑∆𝐻𝑓∘(𝑟𝑒𝑎𝑐𝑡𝑎𝑛𝑡𝑠)]

18
Q

What are the enthalpy of formation of elements in their standard states?

A

zero

19
Q

Is the enthalpy of formation of the products +ve or -ve?

A

+ve

20
Q

Is the enthalpy of formation of the reactants +ve or -ve?

A

-ve

21
Q

What are some basic elements?

A
  • C(s)
  • N2 (g)
  • O2 (g)
  • H2 (g)
22
Q

What is the enthalpy of combustion for this:
𝐶𝐻4 (𝑔) + 2O2 (𝑔) → 𝐶𝑂2 (𝑔) + 2𝐻2𝑂 (𝑙)
∆𝐻𝑓∘ = -75 | 0 | -394 | -286 kJmol-1

A

∆𝐻c∘ = [(-394) + 2(-286)] - [(-75) + 2(0)]
∆𝐻c∘ = -891 kJmol-1

23
Q

Why is ∆𝐻c∘ in a real world combustion slightly lower?

A

due to thr evaporation of water - energy needed to break the hydrogen bonding in water

24
Q

What is the equation for the standard enthalpy of combustion?

A

(energy to break bonds) + (-energy to form bonds)

25
Q

What happens when a bond is broken and formed?

A
  • broken: energy is required (+ve)
  • formed: energy is released (-ve)
26
Q

What does it mean if the energy of combustion is negative?

A

exothermic - releases heat

26
Q

What does it mean if the energy of combustion is positive?

A

endothermic - absorbes heat

27
Q

Which is more reliable and why? ethalpy of combustion from bond enthalpies or from heats of formation?

A

heats of combustion - bond enthalpies are not constant from compound to compound

28
Q

Does oxidation reactions release energy when their ∆𝐻 is positive or negative?

A

negative