Week 4 Flashcards

1
Q

2 goal equations of electrostatics

A
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2
Q

Harmonic functions

A

Solutions to laplaces equation

(Not only examples)

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3
Q

form integral form of Gauss’s law for a region of zero net charge in terms of φ

A

where we use E = grad*phi

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4
Q

Greene’s second identity

A
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5
Q

Apply greens second identity and laplaces equation to a region V which is a ball radius R and for f = 1/r g = φ

A
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6
Q

Key insight of harmonic functions

A

They are averaging functions and have no local extrema across V. Any extrema must occur at boundary of V

If φ satisfies Laplace’s equation in a region V and in addition is constant on boundary of V then φ must be equal to the same value across the entire region as the boundary

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7
Q

Dirichlet boundary conditions

A

Values of a function itself on a boundary (for PDE)

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8
Q

Neumann boundary conditions

A

Values of normal derivative of function along a boundary (for PDE)

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9
Q

Showing uniqueness of solution to Laplace’s equation in some volume V

A

1) let there be 2 solutions
2) construct a difference solution
3) on boundary all solutions must be equal
4) therefore both solutions equal

If Φ is specified on the boundary of V, S

Then below:

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10
Q

Integration by parts

A
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11
Q

Taking inner product for sin(nx)

A
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12
Q

Requirements for stable equilibrium

A
  • force in a positive test charge Q is zero at the equilibrium point r0 (E(r0) = 0)
  • when displaced from the equilibrium point forces act so as to return the test charge Q to r0
    (Field lines all point towards r0)
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13
Q

For a charge q located at the origin ρ(r) = ?

A

q * δ3(r) which of course spikes at origin

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14
Q

In spherical coordinates, how to ‘remove’ laplacians from equation

A

Also grad(1/r) = 1/r * er

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15
Q

Relate Laplace’s equation to Poisson’s

A

Laplace’s equation is a special cause of Poisson’s used in regions where ρ = 0

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16
Q

How to go from E to Φ

A

You may need to split the problem

Take line integral

17
Q

Uniformly charged sphere has charge inside? Outside ?

A

Inside: zero it’s a closed surface therefore there is no net flux and the charges are distributed symmetrically around the surface

Outside: as the sphere act like a point charge at its centre use the expression for a point charge

18
Q

What is grounding

A

Potential is zero on the surface

19
Q

Method of images: why? How?

A

Used in problems where we’re looking for field or potential but conductors make it difficult to do so

Additional Charges are chosen to mimic conductors zero potential

20
Q

Separation of variables

A

Generally:
1) boundary conditions of potential
2) define variable separated potential
3) sub into Laplace’s eq and divide by variable separated Φ
4) solve individual equations with boundaries
5) determine which functions it must be

21
Q

Green’s function

A
22
Q

Using green’s function to solve Poisson’s equation

A
23
Q

Use the Heaviside to construct a finite length between -d/2 and d/2

A