modern analytical techniques I Flashcards

1
Q

“How can you determine the relative atomic mass of an element using a mass spectrum?”

A

“By analyzing the relative isotopic abundances shown in the spectrum.”

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2
Q

“What process occurs in a mass spectrometer to produce a mass spectrum?

A

The molecules in the sample are bombarded with electrons, forming molecular ions (M+).”

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3
Q

“What peak in a mass spectrum represents the molecular ion?”

A

“The peak with the highest m/z value, known as the M peak.”

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4
Q

“How do you find the relative molecular mass of a compound using a mass spectrum?

A

“By looking at the mass/charge value of the molecular ion peak (M peak).”

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5
Q

“What does the y-axis represent in a mass spectrum?”

A

“The abundance of ions, often expressed as a percentag

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6
Q

“How are the units on the x-axis typically denoted in a mass spectrum?”

A

“As ‘mass/charge’ ratio.”

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7
Q

“What effect do bombarding electrons have on some molecular ions in a mass spectrometer?”

A

“They cause some molecular ions to break up into fragments.”

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8
Q

“What is a fragmentation pattern in a mass spectrum?”

A

“It is the pattern formed by the fragments of molecular ions, which helps in identifying molecules and their structure.”

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9
Q

“What components are visible on a mass spectrum?”

A

“Only the ions are visible, while the free radicals are ‘lost’.”

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10
Q

“What process is involved in determining the structural formula from a mass spectrum?”

A

“Identifying the ions responsible for each peak based on their m/z values.”

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11
Q

“What assumption is made when determining the ions responsible for peaks in a mass spectrum?”

A

“That the m/z value of a peak matches the mass of the ion that produced it.”

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12
Q

“Why can you differentiate between two different compounds containing the same atoms using mass spectrometry?”

A

“Because they won’t produce exactly the same set of fragments in the mass spectrum.”

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13
Q

“How does each compound contribute to the uniqueness of its mass spectrum?”

A

“By producing a different set of peaks, making the spectrum act as a fingerprint for the compound.”

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14
Q

“How are large computer databases of mass spectra utilized in identifying compounds?”

A

“They can be used to match the spectrum of an unknown compound with those in the database, aiding in compound identification.”

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15
Q

“What happens when a beam of infrared (IR) radiation is passed through a sample of a chemical in IR spectroscopy?”

A

“The IR radiation is absorbed by the covalent bonds in the molecules, increasing their vibrational energy.”

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16
Q

“How do bonds between different atoms behave in terms of absorbing IR radiation?”

A

“Bonds between different atoms absorb different frequencies of IR radiation.”

17
Q

“Why do bonds in different locations within a molecule absorb different frequencies of IR radiation?”,

A

“Because bonds in different places in a molecule have different vibrational frequencies.

18
Q

“What does an infrared spectrometer graph show?”

A

“It shows the frequencies of radiation absorbed by the molecules, aiding in identifying the functional groups in a molecule.”

19
Q

“How are peaks represented on an IR spectrum?”

A

“The peaks are represented as pointing downwards.”

20
Q

“What is plotted on the y-axis and x-axis of an IR spectrum graph?”

A

“Transmittance is plotted on the y-axis, and wavenumber (frequency) is plotted on the x-axis.”

21
Q

“How is infrared spectroscopy useful in determining changes in functional groups during a reaction?”

A

“It can detect changes such as the disappearance of certain absorption peaks, like the O-H absorption when oxidizing an alcohol to an aldehyde, and the appearance of new absorption peaks, like the C=O absorption.”

22
Q

“What changes would you observe in the IR spectrum when oxidizing an alcohol to an aldehyde?”

A

“The O-H absorption peak would disappear, and a C=O absorption peak would appear.”

23
Q

“What additional changes occur in the IR spectrum when further oxidizing an aldehyde to a carboxylic acid?”

A

“An O-H peak at a slightly lower frequency than before would appear alongside the C=O peak.”