19 - Equilibrium Flashcards

1
Q

Homogenous equilibria

A

contains equilibrium species that all have same state/phase.

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2
Q

Heterogenous equilibria

A

contains species that have different states or phases.

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3
Q

what do you not include in kc expression

A

any species that are solid or liquid

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4
Q

what do you include in kc expression

A

species that are (g) or (aq)

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5
Q

how to find kc

A

1 - make a race table to find equilibrium moles
2 - use n=cv to find equilibrium CONCENTRATION
3 - then use Kc formula

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6
Q

how to get Kc experimentally - whole method

A
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7
Q

mole fraction

A

fraction of the total number of moles that each chemical in a reaction is responsible for

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8
Q

write kc expression for N2 + 3H2 -> 2NH3 (reversible)

A
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9
Q
A
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10
Q

what is partial pressure

A

contribution that the gas makes towards the total pressure

the pressure that would be exerted by a gas in a mixture of gases if it occupied the same volume on its own at the same temperature

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11
Q

sum of partial pressures

A
  • Sum of partial pressures of each gas equals total pressure.
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12
Q

sum of mole fractions

A

1

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13
Q

how to find partial pressure

A

total pressure X mole fraction

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14
Q

what is kp

A
  • like Kc but partial pressure replace concentration
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15
Q

units of partial pressure

A

kPa / Pa / atm

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16
Q
A
17
Q
A
18
Q

how to calculate kp from heterogeneous equilibrium

A

only use gaseous species

19
Q

effect on kc / kp if you increase temp on an exothermic reaction, in forward direction

A
  • if temp increases kp decreases
  • kp expression / ratio of products : reactants is now greater then kp
  • so we need to lower the fraction
  • decrease numerator - decrease products + increase denominator - increase reactants
  • shifts towards left
  • equilibrium reached is now equal to new kp
20
Q

effect on kc if increase temp on an endothermic reaction, in forward direction

A
  • if temp increases kp increases
  • kp expression / ratio of products : reactants is now less then kp
  • so we need to increase the fraction
  • increase numerator - increase products + decrease denominator - decrease reactants
  • shifts towards right
  • equilibrium reached is now equal to new kp
21
Q

changes in conc and pressure on kc

A
  • Value of equilibrium constant K is unaffected by changes in concentration/pressure.
  • Equilibrium shift changes and results from the fact that equilibrium constant doesn’t change.
22
Q

what happens if increase conc of reactants (LHS)

A
  • denominator of kc / kp expression larger
  • kc / kp itself does not change
  • ratio of products: reactants is less than kc
  • to return back to normal - increase fraction
  • increase numerator - increase products + decrease denominator - decrease reactants
  • shifts to right
23
Q

effect of catalyst on equilibrium

A

speeds up both forward and reverse reactions in equilibrium by same factor

Equilibrium is reached quicker but position is not changed.

24
Q

how would you work out the units of kp

A

the same way you work out the units of kp

25
Q

how could the amount of iodine be determined in this reaction

2HI (g) -> H2 (g) + I2 (g)

A

A colorimeter could be calibrated using known concentrations of iodine vapour.

The concentration of iodine in the equilibrium mixture could then be determined

26
Q

where do you put the ‘p’ in the kp formula

A

inside the bracket - check mark schemes

27
Q

how would you calculate the total pressure of a system using kp

A

calculate the amount of moles of each component at equilibrium

calculate mole fractions

calculate partial pressures of each component in term os total pressure (P)

substitute into kp formulla