2 - Derivatives Flashcards
Define differentiability at a point.
For f: (a, b)→R, We say that f is differentiable at c ∈ (a, b) if lim{h→0}[f(c + h) − f(c)]/h
exists.
Define differentiability on an interval (a,b).
lim{h→0}[f(c + h) − f(c)]/h
exists for all c ∈ (a, b).
What is the product rule?
(fg)′ = f’g + fg’
What is the quotient rule?
(f/g)′ = (f’g - fg’) / (g^2)
What is the chain rule?
(f◦g)′(c) = f′(g(c))g′(c)
Define minimum, maximum, and extremum points.
For f: I→R and p, q ∈ I, then,
p is a maximum point of f in I if f(x) ≤ f(p), ∀x ∈ I.
q is a minimum point of f in I if f(x) ≥ f(q), ∀x ∈ I.
An extremum point is either a minimum or maximum point.
If f: (a, b)→(α, β) is bijective and differentiable at c ∈
(a, b), f′(c) =/= 0 and f^{−1} is continuous at f(c), what is the conclusion?
f^{-1} is differentiable at c, and (f^{-1})’(f(c)) = 1 / f’(c)
Define local maximum of a function f.
If there exists δ > 0 such that
f(x) ≤ f(p), ∀x ∈ (p − δ, p + δ) ∩ I, then p is a local maximum of f.
Define local minimum of a function f.
If there exists δ > 0 such that
f(x) ≥ f(q), ∀x ∈ (p − δ, p + δ) ∩ I, then q is a local minimum of f.
If c is a local minimum or maximum of f, what is f’(c)?
f’(c) = 0
Define critical point of f
If for f: I→R
1. c is in the interior of I
2. f is differentiable at c
3. f′(c) = 0.
then c is a critical point of f
State Rolle’s Theorem
Let f: [a, b]→R be continuous on [a, b] and differentiable on (a, b). If f(a) = f(b), then there exists c ∈ (a, b) such that f′(c) = 0.
State the Mean Value Theorem.
Let f: [a, b]→R be continuous in [a, b] and differentiable on (a, b). Then, there exists c ∈ (a, b) such that
f′(c) = (f(b) − f(a)) / (b − a)
State the Cauchy mean value theorem.
Let f, g: [a, b]→R be continuous on [a, b] and differentiable on (a, b). Then there exists c ∈ (a, b)
such that
(f(b) − f(a)) g′(c) = (g(b) − g(a)) f′(c).
In particular, if g′(x)=/= 0,
(f(b) − f(a)) / (g(b) − g(a)) = f’(c) / g’(c)
State L’Hopital’s Rule and its 3 conditions for it to hold.
Let f, g : (a, b) → R be differentiable in (a, b). Assume that
(a) lim{x→a+}f(x) = 0 and lim{x→a+}g(x) = 0
(b) g′(x)=/= 0 for all x ∈ (a, b),
(c) lim{x→a+}[f′(x)/g′(x)] exists.
Then: lim{x→a+}[f(x)/g(x)]
= lim{x→a+}[f′(x)/g′(x)].