Lecture 2 - Homeotic genes Flashcards

1
Q

What is the process of lineage tracing/fate mapping/clonal analysis?

A
  • X rays induce chromosome breaks to that homologous chromatids exchange parts in mitotic recombination
  • in an embryo heterologous for a visible marker mutation like mwh after mitosis, this results in one daugher cell becoming homozygous recessive for the phenotype and expressing that phenotype
  • all the progeny of this cell will also have this phenotype reuslting in a clone of genetically marked cells
  • marking a cell early in development can trace its lineage
  • however cannot test what the limits of the cell are
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2
Q

What was the result of the ‘minute technique’?

A
  • defined compartments which corresponded to parasegments

- indicated that the parasegemnt is the developmentally important unit

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3
Q

What is the minute technique?

A

Minute is a gene that regulates the speed of the cell cycle
1. A fly heterozygous for mwh+/- and minute +/- was generated, with mwh conjugated to minute. As it is heterozygous for the minute mutation, cells divide slowly compared to WT
2. As drosophila are diploid (2 copies of each chromosome), if cell is hit with x rays during mitosis (when cells divide and chromosomes are copied) crossing over occurs and this results in mitotic recombination
3. Chromosomes segregate, resulting in two diploid daughter cells whose genotype is different from the parental cell
-one daughter cell is homozygous recessive for minute -/-, this is lethal and the cell dies
-one daughter cell is homozygous recessive for mwh -/- and is therefore marked. It is also WT at the minute locus so it divides at a wt rate. Therefore in a heterozygous embryo, this cell divides faster than other cells, generating a large clone of descendants marked with multiple wing hairs
Results show a clear boundary of cell lineage restriction
-cells in the parasegment stay in the parasegment

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4
Q

What is the hierarchy of genes involved in the control of the identity of the parasegments?

A
  • Maternal genes control the gap genes and the primary pair rule genes
  • Gap genes control the primary pair rule genes and the selector genes (homeotic genes)
  • Primary pair rule genes control the secondary pair rule genes, the selector genes and the segment polarity genes
  • Secondary pair rule genes control the segment polarity genes and the selector genes
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5
Q

What do mutations in the bithorax complex normally result in?

A

Homeobotic transformation

  • where posterior identify is transformed into an anterior identity
    e. g.
  • In the normal adult, the wing and the haltere are made up of anterior and posterior compartments
  • In the bithorax mutant, the posterior compartment of T3 is transformed into into the anterior compartment of T2, so that it forms the anterior half of a wing
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6
Q

What experiments/phenotypes defined the parasegment as a compartment and the developmentally important unit?

A
  • bithorax mutant phenotype

- minute technique to show cell lineage restriction within strict boundaries

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7
Q

What genes is the parasegment set out and patterned by?

A
  • segmentation genes

- homeotic selector genes

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8
Q

What are the homeotic selector genes(Hom-C)?

A

The genes of the antennapaedia and bithorax complexes in drosophila

  • set the future developmental pathway of each compartment
  • clustered in the genome
  • code for transcription factors, regulate the activity of other genes
  • DNA binding domain (homeobox)
  • required to maintain correct patterning of cells
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9
Q

What are the three main features of the homeotic genes?

A
  • clustered (genetically linked)
  • colinearity of expression
  • conserved
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10
Q

What are the features of the colinearity of the homeotic genes?

A
  • order of the genes along the chromosome is the same as the order of temportal and special expression along the AP axis of the embryo
  • e.g. Ubx, which is more 3’ to AbdA is expressed more anteriorly and earlier than AbdA, which is more 3’ to AbdB and expressed more anteriorly and earlier than AbdB
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11
Q

How can the colinear expression of homeotic genes be viewed experimentally?

A

in situ hybridisation

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12
Q

What are the features of the expression of AbdB shown through insitu hybridisation?

A
  • can have very resticted boundry of expression

- reflect what had previously been shown by clonal analysis, cells do not cross parasegment boundaries

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13
Q

What is the structure of patterning of the bithorax complex?

A

-compromises three genes, ubx, adbA and abdB
-expressed in a combinatorial manner (combined activity of these genes define the character of each parasegment)
-required for the correct patterning of parasegments 5-13
-initial patterning is set up by the gap genes and pair rule genes, also some cross talk between the genes:
AbdB represses Ubx (expression and/or activity)
=> repressive activity called the posterior prevelence or posterior dominance

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14
Q

What is posterior prevelence/dominance?

A

-where posteriorly expressed genes in the complex repress the activity and/or expression of the more anteriorly expressed genes

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15
Q

What do mutations in homeotic genes cause?

A

transformations in parasegment identity
-e.g. in the absence of AbdB the parasegmetns 10-13 are transformed into parasegment 9 (ie. all segments A3p/A4a)
-shows posterior prevelence
-in the absense of AbdA and AbdB, parasegments 7-13 are all transformed into parasegment 6 (ie. all segments T3p/A1a)
-expression again spreads posteriorly due to postierior prevelnce (AbdB normally represses Ubx)
-in the absence of the entire Bx-c, parasegments 5 -13 are all transformed into parasegment 4 (ie all semgnets pT1/aT2)
-under the control of the antennipedia complex
-

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16
Q

How does the mutant phenotype of AbdB show posterior prevelence?

A

In the absence of AbdB, AbdA expression spreads posteriorly

17
Q

How do Hox genes show consevation?

A
  • hom-C genes in drosophila found to be conserved across the animal kingdom
  • 4 clusters of hox genes in mice and humans
  • play a role in the AP specification in all animals
  • genes are also always clustered in the same order along the chromosome and the expression on the AP axis corresponds to where it lies within the cluster along the 3’ to 5’length of the chromosome
  • the more 3’ the cluster, the earlier and more anteriorly it is expressed
18
Q

Are vertebrates segmented? How does this reflect Hox gene expression?

A
  • some obvious signs that vertbrates are segmented:
  • somites that go on to form the skeletal muscle and vertbrae
  • hindbrain is segmented into rhombomeres

Hox genes are expressed in the somites and paraial mesoderm, the CNS and the neural crest

19
Q

What is a parasegment?

A

defined unit of cellular expression under the control of the hox genes

20
Q

What experiment was done to show that compartments in the vertbrate hindbrain are segmented into rhombomeres?

A

Fate mapping

  • inject dye into a small group of cells in the early neural plate. No boundaries at this stage
  • when the rhombomeres are forming the clones (cells) will respect boundaries between rhombomeres [ the boundaries separate compartments of cell lineage restirction]
  • if the cells are marked after the boundries form , cells don’t cross boundaires
21
Q

What is the expression of Hox genes at rhombomere boundaries?

A

The expression of hox genes show sharp anterior boarders at rhombomere boundaries

  • shown through in situ hybridisation
  • different combinations and concentrations of hox genes dictate which rhombomere will form (like homeotic selector did for parasegments in flies)
22
Q

What is necessity of functional data to show where the hox genes act?

A
  • previously just shown where the hox genes were expression
  • required a level of assumption
  • need functional data from knock outs via gene targeting
23
Q

What is the process in DNA manipulation in gene targeting knock outs?

A
  1. Generate a construct containing regions that are homologous to the gene of interest so that is appropriate for double drug selection.
    - insert a neoR/G418 drug to select for insertion, and a TK/glancylovir outside of the homologous region to select for random insertion
  2. Insert the construct into pluripotent cells derived from the inner cell mass a mouse embryos
  3. Select for sucess via the double drug strategy
  4. Use a breeding strategy to creat chimeric mice by injecting double drug selected ES cells derived from a brown mouse into the host blastocyst of a black mouse
  5. Then breed these to homozygosity

-can disrupt an endogenous gene (e.g. a homeobox gene) with a target vector made in the lab

24
Q

What were the results from the gene targeting knock out mice to identify the function of hox genes?

A

Hox genes before the knock out are funtional

  • skeletal prep shows a homeotic transformation of C2 bone segment to C1
  • isn’t very dramatic as other hox genes, A4, C4 and D4 can make B4 partially redundant
  • all homologs of the fly equivilent
25
Q

Where is engrailed expressed?

A

In the anterior most cell of the parasegment where Ftz or eve is highest