Chapter 17 Concepts Flashcards

1
Q

Explain the relative speed of reaction of each step in an Electrophilic Aromatic Substitution reaction.

A

the first step, formation of the carbocation (sigma complex) is slow because aromaticity is lost. The second step, deprotonation is fast because aromaticity is restored.

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2
Q

Which substituents are activating, and o/p directing?

A

-O, -N-R-R, -OH, -OR, -NH-CH=O. All are electron-donating.

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3
Q

Why are activating substituents o/p directing (except for halogens)?

A

Reaction will occur where there is a partial negative charge (increased electron density) which is at the ortho and para positions due to delocalization of the electrons on the substituent. o/p are also more stable carbocations - have one with a full octet.

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4
Q

Why are halogens deactivators, and also o/p directing?

A

The electronegative halogen draws electon desity from the ring, but it also provides a stable carbocation in which the postitive charge resides on the halogen, and is a carbocat. with filled octets.

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5
Q

Why are deactivating substituents meta directing?

A

deactivators delocalize partial positive charge on the o/p carbons. This leaves the meta carbons with the highest electron density, so they are more reactive.

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6
Q

Which substituents are deactivating and meta- directing?

A

groups with positive charge on the atom bonded to the ring: -SO3H, -NO2, -CN, -COR, -COOR, -NR3

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7
Q

When there is a conflict between substituents, which ones take precedent?

A

activating groups. if two of the same class; whichever is stronger/mix of products.

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8
Q

What are the three limitations of the Fridel-Crafts Alkylation reaction?

A
  1. Fails with deactivating systems.
  2. Susceptible to carbocation rearrangements.
  3. Susceptable to polyalkylation, which can be minimized by adding excess benzene.
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9
Q

What is the only limitation of Fridel-Crafts Acylation?

How does it pass rearrangement and polyacylation?

A

fails with strongly deactivating systems.

no rearrangement issues b/c resonance stabilized acylium ion. no polyacylation b/c product is deactivated by acyl group.

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10
Q

What is used to turn nitrobenzene into aniline?

A

A reducing agent like LiAlH4.

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11
Q

What about an activator makes it stronger?

A

Resonance - has greater effect than induction on activation strength.

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12
Q

What is the product expected from a reaction with nitro benzene and acyl chloride in AlCl4

A

No reaction - nitrobenzene is too deactivated

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13
Q

What different compounds can be used in Fidel crafts reactions?

A

An alkene and HF, Cl2-R+AlCl3, an alcohol and BF3

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14
Q

What is the second thing you need in acylation besides AlCl3?

A

H2O for removal of aluminum salt.

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15
Q

What is the second way of achieving acylation?

A

Using CO and HCl, AlCl and CuCl

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16
Q

When does a molecule undergo the benzyne mechanism?

A

When a cyclic molecule is not activated towards NAS, but it is treated with a strong base (like NH2) for a nucleophile.

17
Q

What is the mixture of m/p products after benzyne mechanism a result of?

A

the nucleophile attacks at either end of the triple bond.

18
Q

what is the product of an alkyl benzene treated with KMnO4/OH or Na2Cr2O7/H2SO4?

A

benzoic acid (alkyl side chains become carboxylic acids.)

19
Q

What is the product of a substituted benzene ring treated with Br2, or NBS and light?

A

Bromobenzene, with the Br adding to the benzylic carbon.

20
Q

Why is the benzylic position activated?

A

This H is more likely to leave b/c doing so allows the radial to be resonance-stabilized by the ring.

21
Q

What is the mechanism for NAS?

A

nucleophile attacks at the halogenated carbon, causing the electrons of the double bond to delocalize. halogen leaves, and electrons replace the double bond.

22
Q

Where must electron-withdrawing groups be for NAS?

A

o/p to the leaving group. This activates the ring.

23
Q

what is the product and mechanism of benzyl halide reacted with a weak nuc like EtOH and heat?

A

benzylic ether, SN1

24
Q

Why are benzylic halides so much more reactive than primary halides via SN2?

A

the transition state is stabilized by the ring, as the p-orbitals of the nuc and halide overlap with those of the ring.