5.3 - .... Flashcards

1
Q

which nephron segments comprise the distal nephron

A
  • Distal convloluted tubule
    (-Cortical collecting tubule
  • medullary collecting tubule
  • papillary cllecting duct)
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2
Q

what fraction of the filtered load of water and sodium remain by the time the tubular fluid arrived at the distal nephron

A

10% of the filtered load of water

10% of the filtered load of NaCl (180 L)

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3
Q

what two hormones regulate water and sodium re-absorption in the distal nephron

A
  • antiduiretic hormone (ADH)

- Aldasterone

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4
Q

how does ADH make a collecting tubule cell permeable to water

A

promotes water reabsorption therby generating a small colume of concentreated Urea

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5
Q

in the absence of ADH, why does tubular fluid become even more dilute from the beginning to the end of the distal nephron

A

Reabsorption of some NaCl in the distaal nephron contunues to dilute the tubular fuid resulting in excretion of a large volume of hypotonic urin. (Diuresis)

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6
Q

how does ADH make a collecting tubule cell permeable to water

A

ADH stimulates insertion of pre-existing AQP-2 channels into the luminal membrane.

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7
Q

what is the signaling process associated with ADH making a collecting tubule cell permeable to water

A

Increase AMP —> increase translocation of channel-containing sesicle to luminal membrane—> increase fusion and insertion—-> increase water permeability

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8
Q

where do the water channels reside in low ADH state?

A

sd

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9
Q

what type of Aquporin are located in the luminal and basolateral membrane of collecting tubule cells

A

AQP3, (at least 3 different isoforms)

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10
Q

where is the only place aldosterone receptors are found

A

cortical collecting tubule cells

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11
Q

what is countercurent multiplication

A

maxiamal NaCl concentreation differenc afross ascending limb ~ 100 mM/mOsm/L

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12
Q

what is essential for the depostion of NaCl in the medullary interstitium

A

if only isotonic fluid flowed into the ascending limb, it would be impossible to maintain interstitial NaCl concentrations above 150 mM

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13
Q

3 conceptual steps of contercurrent multiplication

A

1 reabsorption of NaCl by the ascending limb (ASC) retention in interstitium
2 reabsorption of H2O by the descending limb(DES) removeal by the vasa recta
3 isotonic fluid from proximal tubule into loop

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14
Q

How do the eura transport characteristics of the subsection of the collecting tubule differ

A

with ADH, TF urea concentrations increase (increase ADH —> increase H2O reabsorption—-> increase TF urea)

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15
Q

why is ADH so criticle for urea reabsorption

A

causes urea to be re-concentrated and reabsorbed

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16
Q

make note cards on section 5.7 and 5.8, 6.1

A

17
Q

what class of hormone is ADH

A

arginine vasopressin (neurohormone)

18
Q

where is ADH synthesized stored and secreted

A

made is Hypothalamous,
stored in posterior petuitary
secreted from posteriof petuitary

19
Q

what are the two principle mechanisms that regulate ADH secretion

A

hypothalamic osmoreceptores (linear relationship) small changes have large effects

  • volume receptors (much less sensitive)
20
Q

are large changes in plasma ADH required to elicit changes in urine volume and osmolatlity

A

NO, relatively small changes in ADH elicit large changes in urine osmolality (Set point of 278)

21
Q

in a state of water deficit, with an increase in ADH and thus increased water reaborption alone restore normal fluid volume

A

NO, increase of ADH will only minimize furthr losses of water

22
Q

How is thirst controlled

A

ADH regulates thirst (

23
Q

what is SIADH (Syndrome of inappropriate ADH secretion), what are the posslbe causes

A

head trauma, encephilitis, meningitis
ADH secreting tumors
drug induced

24
Q

what are the potential effects of SIADH

A

hyponatrema

Coma

25
Q

what are the two principle forms of diabetes insipudus

A

Hypothalamic D.I - defective production of ADH

Nephrogenic D.I - renal unresponsiveness to ADH

26
Q

how can D.I be treated

A

27
Q

standard formula used to measure free water clearance

A

free water clearence = V - C(osm)

(V=total urin flow

28
Q

when is free water clearence Zero

A

when putting out equal amounts of urin and salt concentrations