3.3- mechanisms of halogenoalkanes Flashcards
(34 cards)
what are free radicals (2)
-a reaction intermediate (made during a reaction then are destroyed)
-highly reactive species with one or more unpaired electrons
how do free radicals form (2)
-through homolytic fission of a covalent bond
-the bond is broken through a source of high energy eg. UV light/ high temps
what is the initiation step in free radical substitution
-creates 2 free radicals
X₂ ->2X⋅
what is the dot next to an element/compound in free radical susbtitution
a single, unpaired electron
what are the propagation steps in free radical substitution (2)
show the 2 propagation steps from a chlorine radical and methane
-when a free radical has formed, the unpaired electron is transferred to other molecules to create a series of new products
-halogenoalkanes are produced in the second equation/part
1. CH4 + Cl⋅ -> HCl + ⋅CH3
(starting molecule- CH4- reacts with one free chlorine radical to form methyl free radical)
2. ⋅CH3 + Cl₂ -> CH3Cl + Cl⋅
(methyl free radical reacts with diatomic halogen- Cl2- to produce a halogenoalkane and a free radical)
what is the termination step in free radical substitution
show 2 possible termination steps
-2 free radicals combine and the reaction ends
-goes from 2 free radicals to no free radicals
1. ⋅CH3 + ⋅CH3 -> C2H6
2. ⋅CH3 + Cl⋅ -> CH3Cl
what is the overall equation for the reaction between methane and chlorine
CH4 + Cl₂ -> CH3Cl +HCl
what is ozone and why is it bad (3)
protects us from UV radiation (can cause skin cancer)
-when they rise to the atmosphere, the initiation step occurs
-UV light causes the C-Cl bond to break
what are chloroflurorocarbons (2)
-hydrocarbons where all H atoms are substituted by Cl and F
-very unreactive due to C-F and C-Cl bonds
2 equations to show how ozone is formed
O2 –> 2O⋅
⋅O(g) + O2(g) –> 03(g)
why is it beneficial that ozone reduces the amount of UV reaching earth
reduces risk of skin cancer as UV damages DNA
what is a nucleophile (2)
an electron pair donor- they have a lone pair
-they attack electron-defficient species
what are the 3 nucleophiles
hydroxide ions, cyanide ions, ammonia
reagent for hydroxide ion in nucleophilic substitution
aqueous sodium/potassium hydroxide
(NaOH or KOH)
conditions for hydroxide ion in nucleophilic substitution(2)
heated under reflux
aqueous reagent
reagent for cyanide ion in nucelophilic substitution
potassium/sodium cyanide dissolved in ethanol
(NaCN or KCN)
conditions for cyanide ion in nucleophilic subsitution
heated under reflux
reagent for ammonia in nucleophilic substitution
excess concentrated solution of ammonia in ethanol (ethanolic ammonia solution)
conditions for ammonia in nucleophilic substitution
heated under pressure
what is the new functional group formed in hydroxide ions nucleophilic substitution
alcohol
what is the new functional group formed in cyanide ions nucleophilic substitution
nitrile
what is the new functional group formed in ammnia nucleophilic substitution
amine
what happens in nucleophilic substitution (3 stages)
- nucleophile donates a pair of electrons to the partially positively charged carbon in the halogenoalkane
- the C-H bond breaks heterolitically, with both electrons going to the halide ion
- a new bond forms between the carbon atom and the nucleophile- the halogen has been replaced by another functional group
why must the reaction cyanide ions in nucleophilic substitution have to take place under reflux conditions and in ethanol, not water
Water in an aqueous solution would act as a nucleophile and undergo nucleophilic substitution with the halogenoalkane, forming an alcohol instead.