4- E2 Flashcards

(36 cards)

1
Q

what are elimination reactions

A
  • Elimination reactions consist of the removal of Hydrogen and Leaving Group from adjacent carbons to form π bond.
  • start with a sigma bond, end with a pi bond
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2
Q

what is needed for an E2 reaction

A

a base that will take away the proton, form a pi bond, kick the leaving group

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3
Q

what kind of a mechanism does E2 proceed through

A

concerted mechanism, bimolecular

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4
Q

what are the detailed steps for E2 reaction mechanisms

A
  • base that removes a proton from the beta carbon
  • pi bond forms between the alpha carbon and the beta carbon
  • because of the pi bond forming, the leaving group gets kicked off
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5
Q

what do strong bulky bases act as

A

weak nucleophiles, because steric congestion comes with them. with these bases, you cannot do SN2 (cannot act as good nucleophile)

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6
Q

what are examples of strong bulky bases

A

t-BuOK; LDA, DBU (11 atoms), DBN (9 atoms))

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7
Q

what do strong small bases act as

A

good nucleophile (can be SN2 or SN1)

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8
Q

what are examples of strong small bases

A

–OH, -OCH3, -OC2H5, -NH2, -H

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9
Q

why are -H (hydrides) special in E2

A

they are not nucleophiles, only act as bases (no SN2 possible)

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10
Q

what does an energy diagram for E2 look like

A
  • one transition state

- both reagents at the transition state (because both are involved in the RDS)

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11
Q

what is the rate reaction for E2, what order is the reaction

A

rate = k[Base][R-X]

second-order reaction

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12
Q

explain what happens what happens when there are different beta protons in the substrate

A
  • we will have a major and a minor
  • need to discuss regioselectivity when both carbon betas are different
  • size of the base is the criteria behind regioselectivity
  • if you have small base → one major product
  • if you have large base → two products, the opposite will be major
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13
Q

what do bulky bases prefer and what do small bases prefer

A

bulky bases prefer less steric hinderance (wherever it is easier to rip a proton off of)
small bases prefers the most stable product

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14
Q

what is the most stable alkene

A

Most stable alkene is the most substituted alkene (more alkyl substituents on π bond)

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15
Q

what is the Zaitsev product

A
  • two carbons attached to the pi bond (di-substituted)

- the major product for small bases

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16
Q

what is the Hofmann product

A
  • one carbon attached to the pi bond (mono-substituted alkene)
  • the major product for bulky bases
17
Q

why is the zaitsev’s product faster

A

More stable transition state with more substitution leads to faster reaction

18
Q

explain the energy diagram for E2: zaitsev’s rule

A
  • zaitsev’s product will have a lower transition state (indicating major product)
19
Q

explain how alkenes are stabilized via hyperconjugation

A
  • overlap between sigma orbitals and pi* orbitals = stabilizing pi orbital
  • electrons from the sigma orbital go into the empty pi* orbital (creates an extended molecular orbital between the sigma and the pi orbital)
  • the more substituted the pi bond, the more the sigma orbital and pi* orbital will overlap = more overall stability
  • more substituted alkenes = more stable
20
Q

explain how alkenes are stabilized via resonance

A
  • more delocalization = more stable alkene
21
Q

what is the reversal of selectivity, exception to zaitsev’s rule

A
  • Bulky bases favour the less substituted alkene (less stable)
  • Bulky bases can only reach the most accessible hydrogens.
    • the one that has the least carbons interfering with it
22
Q

what is the only stereochemistry in which E2 can proceed in acyclic newman projections?

A

E2 can only proceed if C─H and C─LG lie in an antiperiplanar conformation.

23
Q

what way do you represent acyclic substrates? what way do you represent cyclic substrates?

A
  • Newman projection is used for acyclic substrates.

- Chair conformation is used for cyclic substrates

24
Q

what product will be created when you have one reactive conformation? what product will be created when you have two reactive conformation?

A

one: you can have either E or Z major. it depends on the final conformation of your newman projection
two: you will always have E (major) and Z (minor)

25
what is the relationship between number of protons on the beta carbon and the number of products
one proton = one product | two protons = two products
26
what is the only stereochemistry in which E2 can proceed in cyclic chair conformations?
you need to put the C alpha-LG and C beta-H axial and anti (to get the anti-periplanar)
27
what should the pKa of a conjugate acid be for something to be considered a strong base?
strong base needs to have a conjugate acid with a pKa > 11
28
what are the three steps for differentiating between E2, SN2 and SN1
- To compare, start with determining if the substrate (electrophile) is primary, secondary or tertiary - 1) look at electrophile (1º, 2º, 3º) - 2) nucleophile / base comparison - 3) reaction conditions (solvent or temperature)
29
what are the steps for a primary substrate (SN2 vs E2)
- Major is SN2 product unless bulky base which is a weak Nucleophile was used - look at electrophile first, then move to the criteria of comparing the nucleophile and the base, then move to the criteria of the reaction conditions - SN2 will always predominate unless the reagent is a strong bulky base or a hydride base
30
what are the steps for a tertiary substrate (SN1 vs E2)
- It depends on the Nucleophile/Base used. - If weak base/strong Nucleophile, SN1 would be favoured. - If strong base/weak nucleophile used, E2 is favoured - if you have a reagent that only acts as a nucleophile → SN1 (pKa of CA is <11) - -CN, -N3, X-, RS-, ROH - if you have a reagent that is a strong bas (pKa CA > 11) → E2 - RO-, RNH-
31
what are the steps for a secondary substrate (SN1 vs SN2 vs E2)
- SN1 = weak nucleophile, less heat, polar protic solvent - SN2 = good nucleophile, less heat, polar aprotic solvent - E2 = more basic nucleophile, more heat, polar protic solvent - weak base/Nu= no SN2 and no E2 → has to be SN1 - strong base/Nu = SN1 is the option you can eliminate - SN2 vs E2: - if bulky base or hydride → E2 - if reagent only acts as strong nucleophile (X-, CN-, N3- RS-) - third criteria: what if my reagent is strong but it can react as a strong base and a strong nucleophile? - look at reaction conditions: temperature, solvent - if there is heating → E2 predominates - if the solvent is polar protic → E2 predominates - if the solvent is aprotic → SN2 predominates
32
what are the steps for a stabilized primary substrate (SN2 vs SN1 vs E2)
- if the nucleophile/base is weak → SN1 - if the nucleophile/base is strong → SN2 vs E2 - if the reagent is only a nucleophile → SN2 - if the reagent is only a base → E2 - if the reagent is a strong base/Nu → check temperature and solvent - if heating → E2 - if protic → E2 - if aprotic → SN2
33
list of only Nu
- X- (Br-, Cl-, I-) - -CN - -N3 - RS- - HS- - RNH2 (only in 1º and 2º. if 3º and heating→ E2, if no heating → SN1) - RCOO- - RSH (moderate nucleophile if 1º)
34
list of only base
- LDA - tBuO- - DBN - DBU - NaH - KH
35
list of strong Nu/base
- RO- - HO- - -C≡CR - -NR2 - -NH2
36
list of weak Nu/base
- ROH - water - carboxylic acid (RCOOH) - RSH (depends on the substrate → 2º, 3º)