4.1.2 - Alkanes Flashcards

(63 cards)

1
Q

What type of hydrocarbons are alkanes and cycloalkanes?

A

Alkanes and Cycloalkanes are saturated hydrocarbons.

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2
Q

What is a sigma bond?

A

A sigma bond is a type of covalent bond which forms when atomic orbitals overlap head-on. Sigma
(σ) bonds can rotate freely.

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3
Q

What is a pi bond?

A

A pi bonds is a type of covalent bond which forms when adjacent p orbitals overlap sideways above and below the bonding C atoms. Pi bonds cannot be rotated.

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4
Q

What is the general formula of an alkane?

A

CnH2n+2

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4
Q

Why are alkenes more reactive than alkanes?

A

As pi bonds have low bond enthalpy, alkenes are more reactive than alkanes.

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4
Q

What is the shape around the carbon atom in saturated hydrocarbons?

A

Tetrahedral.

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4
Q

What is the bond angle around a carbon atom in a saturated hydrocarbon?

A

109.5°

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4
Q

Why is the shape around the carbon atom tetrahedral in saturated hydrocarbons?

A

Because there are four bond pairs of electrons which repel equally, arranging themselves as far apart as possible — forming a tetrahedral shape.

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4
Q

Why do boiling points increase down the alkane homologous series

A

Because larger alkanes have more electrons, leading to stronger induced dipole–dipole interactions (London forces) between molecules.

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4
Q

How does the shape of an alkane affect its boiling point?

A

Straight-chain (unbranched) alkanes have more surface area contact between molecules than branched alkanes, so they form stronger London forces and have higher boiling points.

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4
Q

Why do branched alkanes have lower boiling points than straight-chain alkanes?

A

Because they are more spherical and have less surface contact between molecules, resulting in weaker London forces.

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4
Q

What are the products of complete combustion of alkanes?

A

Carbon dioxide (CO₂) and water (H₂O).

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4
Q

What is a fuel?

A

A substance that releases heat energy when burned.

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4
Q

Why are alkanes used as fuels?

A

They burn readily in oxygen and release a large amount of heat energy because their combustion is highly exothermic.

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4
Q

Why are alkanes relatively unreactive?

A

Because C–C and C–H bonds have high bond enthalpies (they are strong), and the σ-bonds are non-polar or only very weakly polar.

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4
Q

What are the products of incomplete combustion of alkanes?

A

Carbon monoxide (CO) and/or carbon (soot).

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4
Q

What conditions are needed for complete combustion?

A

A plentiful (excess) supply of oxygen.

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4
Q

What happens if alkanes are burned with limited oxygen?

A

Incomplete combustion occurs.

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4
Q

Why does incomplete combustion produce less energy?

A

Because the fuel is not fully oxidised.

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4
Q

What is cracking?

A

The conversion of large hydrocarbon molecules into smaller, more useful ones by breaking single carbon–carbon (C–C) bonds.

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4
Q

How does carbon monoxide affect the body?

A

It binds strongly to haemoglobin in red blood cells, preventing oxygen from binding and being transported in the body.

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4
Q

What environmental problem can carbon (soot) contribute to?

A

Global dimming — it reflects sunlight back into space.

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4
Q

Why is carbon monoxide dangerous?

A

It is highly toxic and odourless. It can build up in enclosed spaces and cause death if heating systems are faulty.

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4
Q

What visual sign is often produced by incomplete combustion?

A

A sooty flame caused by carbon (soot).

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4
What is the formula to work out the equation for complete combustion?
CxHy + (x+y/4)O2 --> (x)CO2 + (y/2)H2O
4
Question: Write out the formula for the incomplete combustion of pentane, to produce carbon monoxide.
2C5H10 + 11O2  10CO + 12H2O
4
Question: Write out the formula for the complete combustion of pentane.
C5H10 + 8O2  5CO2 + 6H2O
4
What is catalytic cracking?
A form of cracking that uses a catalyst to convert straight-chain alkanes into branched and cyclic alkanes, alkenes, and aromatic hydrocarbons.
4
Why is cracking necessary?
Because there is a higher demand for shorter-chain hydrocarbons like petrol and naphtha than for longer-chain ones.
4
Why does cracking require high temperatures?
Because strong covalent bonds need to be broken, which requires a significant amount of energy.
4
What are the typical products of cracking?
Smaller alkanes, alkenes, and sometimes hydrogen gas.
4
Question: Write out the formula for the incomplete combustion of pentane, to produce carbon.
C5H10 + 3O2  5C + 6H2O
4
What are the economic reasons for cracking? (3)
* Converts excess long-chain hydrocarbons into more useful short-chain ones. * Increases yield of high-demand products like petrol. * Produces valuable products such as ethene (for plastics) and branched alkanes (for fuels).
4
What conditions are required for catalytic cracking?
Slight pressure, high temperature (about 450°C), and a zeolite catalyst.
4
What are the main products of catalytic cracking?
Branched alkanes, cyclic alkanes, alkenes, and aromatic hydrocarbons.
4
Why are branched and cyclic hydrocarbons useful?
They burn more efficiently and increase the octane number of fuels.
4
What is the catalyst used in catalytic cracking?
A zeolite catalyst.
4
What is a practical use of products from catalytic cracking?
They are used to produce high-octane motor fuels and chemicals like ethene for making polyethene.
4
What conditions are needed for alkanes to react with halogens?
Ultraviolet (UV) light is required to initiate the reaction.
4
What is the overall reaction of methane with chlorine?
CH₄ + Cl₂ → CH₃Cl + HCl
4
What is substitution in the context of alkanes?
A reaction where hydrogen atoms in an alkane are replaced by halogen atoms (e.g., Cl or Br).
4
What is the name of the mechanism for alkane-halogen substitution?
Free radical substitution.
4
What are the three steps in a free radical substitution mechanism?
1. Initiation 2. Propagation 3. Termination.
4
What happens during initiation?
The halogen molecule (e.g., Cl₂) is split into two radicals using UV light.
4
What type of bond breaking occurs in initiation?
Homolytic fission — each atom gets one electron.
4
Write the initiation step for chlorine.
Cl₂ → 2Cl*
4
What is a free radical?
A reactive species with an unpaired electron. It is neutral and represented with a dot (*).
4
Why is UV light essential in initiation?
It provides the energy to break the Cl–Cl bond, which is the weakest and breaks most easily.
4
What happens in the first and second propagation step of methane and chlorine?
CH₄ + Cl* → HCl + CH₃* CH₃* + Cl₂ → CH₃Cl + Cl*
4
Why is propogation a chain reaction?
Because the chlorine radical is regenerated and can continue reacting with more alkanes.
4
What do all propagation steps have in common?
Each has a free radical on both sides of the reaction.
4
What happens during termination?
Two radicals combine to form a stable product, ending the chain reaction.
4
Give examples of termination steps.
CH₃* + Cl* → CH₃Cl CH₃* + CH₃* → CH₃CH₃ (ethane)
4
Why do termination steps stop the chain reaction?
They remove free radicals, preventing further propagation.
4
Write the initiation step for propane with bromine.
Br₂ → 2Br*
4
Give the example propagation steps for propane and bromine.
CH₃CH₂CH₃ + Br* → HBr + CH₃CH₂CH₂* CH₃CH₂CH₂* + Br₂ → CH₃CH₂CH₂Br + Br*
4
What is the overall reaction from CH₄ to CCl₄?
CH₄ + 4Cl₂ → CCl₄ + 4HCl
4
Give a termination steps for propane and bromine.
CH₃CH₂CH₂* + Br* → CH₃CH₂CH₂Br CH₃CH₂CH₂* + CH₃CH₂CH₂* → CH₃CH₂CH₂CH₂CH₂CH₃
4
What is the overall reaction from CH₃F to CFCl₃?
CH₃F + 3Cl₂ → CFCl₃ + 3HCl
4
What happens if excess chlorine is present in a substitution reaction?
Further substitution occurs, forming products like CH₂Cl₂, CHCl₃, and CCl₄.
4
Write the propagation step from CH₃Cl to CH₂Cl₂.
CH₃Cl + Cl* → HCl + CH₂Cl* CH₂Cl* + Cl₂ → CH₂Cl₂ + Cl*
4
What is always the side product of halogen substitution in alkanes?
HCl (hydrogen chloride). Never H₂.
4
What does it mean to have a polar bond?
A covalent bond that has a permanent dipole due to different electronegativities of the atoms that make up the bond.