4.4 Aldehydes and Ketones Flashcards
Type of rctn alcohols undergo to for aldehydes and ketones
Oxidation
How can you tell whether the oxidation of an alcohol will produce an aldehyde or ketone?
Primary alcohol will form an aldehyde when oxidised
Secondary alcohol will form a ketone when oxidised
Why is immediate distillation req for the oxidation of an alcohol to an aldehyde
Aldehyde must be distilled off immediately as it will undergo further oxidation producing a carboxylic acid
Common oxidising agent in oxidation of alcohols
Acidified Potassium dichromate (VI)
Observations when alcohol udergoes oxidation by acidified potassium dichromate (VI)
Orange dichromate(VI) ion Cr2O72- is reduced to green chromium(III) ion Cr3+
Observation when acidified potassium dichromate is added to a tertiary alcohol?
Solution will remain orange as acidified potassium dichromate (VI) does not react with tertiary alcohols as they can not be oxidised
Chemical eqn for the oxidation of porpan-2-ol to propanone
CH3CH(OH)CH3 + [O] -> CH3COCH3 + H2O
Chemical eqn for the oxidation of ethanol to ethanal
CH3CH2OH + [O] -> CH3CHO + H2O
Two reagents used to distinguish between aldheydes and ketones
Tollen’s reagent
Fehling’s reagent
How can Tollen’s reagent be used to determine whether you have an aldehyde or a ketone?
Tollen’s reagent forms a silver mirror on test tude only when warmed with an aldehyde not a ketone
How can Fehling’s reagent be used to determine whether you have an aldehyde or a ketone?
Fehling’s reagent is blue, if added to an aldehyde the blue solution will for a brick red ppt, if added to a ketone remains blue
Type of reaction aldehydes and ketones undergo to form alcohols
Reduction
Classification of the alcohols formed by reduction of aldehydes and ketones
aldehydes will be reduced to a primary alcohol
ketones will be reduced to a secondary alcohol
Common reducing agent used in reduction of aldehydes and ketones to alcohols
NaBH4 dissolved in water with methanol
Chemical eqn for the reduction of butanone to butan2ol
CH3COCH2CH3 + 2[H] -> CH3C(OH)HCH2CH3