6A.2 Radial Electric Fields Flashcards
radical fields in a positively charged sphere are
pointing outwards in all directions from the centre of the sphere with the lines moving further apart indicating a weaker field strength, as well as the equipotentials, moving further apart,
as the field lines from a positively charged particle move further away
the potential changes happen less quickly
a charged particle in a charged field would experience
no resultant force so no electric field, the overall effector charges on the sphere cancel within the sphere itself
The equation for radical field strength is?
E = Q/4piEor^2 9 ( this is only correct for a field produced in a vacuum)
why is the equation of radical field strength only correct in a vacuum
because the permittivity of free space is a constant that relates to the ability of the fabric of the universe to support the electric field strength, if the electric field isn’t in a vacuum the ability to support the field strength might be better or worse so we need to account to that to get the radical field strength
what is the expression of V using E = dV/dx and the radical field strength at distance r
V = Q/4piE0r
V = Q/4piE0r this equation shows that
the position of zero potentail can be considered to infinity
what is the exprension for k (coulombs constant)
1/4pie0
when there is more than one charged object, what happens to the overall field
the overall field at any point is the vector sum of all the contributions from each field, the sum of all of these individual force effects is the overall electric field
what are the charged particle interactions look like
page 34
how do lighting spikes protect buildings
teh concentrated charge of lighting is more attracted to the oppositely charged conductor, so it will more likely hit the lighting spike instead of the buildings, as well as the field around the lighting spikes is so strong that it can cause a current leakage when building enough current to cause lighting, stopping lighting from occurring at all
