Possible Q's To Look Out For Flashcards

1
Q

Role of Myosin in Cytokinesis

A
  • Starfish egg incubated with myosin antibody which inhibits cytokinesis
  • Mitosis continues in absence of cytokinesis
  • Experiment illustrates how you can separate mitosis from cytokinesis. Starfish egg has multiple mitotic events. Done by inhibiting myosin II. won’t progress to cytokines just keeps going through mitotic events.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

how to plants assemble a spindle fibre apparatus with the presents of a centrosome?’

A
  • centrosomes are unique to animals, none in plants. Different mechanisum, uses 2 headed motor proetins. Jumble of cspindle fibres but there’s these motor proteins present. M.Tubules have plus and minus end. When the proteins grab them they \d then start moving towards the minus end and as they move they pull the m.Tubules togtheretr like a drawstring. Create the equivalent of a centrosome.Plant cells set up the spindle apparatus without the centrosome.
  • SUMMARY: Use 2 headed minus directed motor proteins and associated micro tubules that move towards the minus end and [ ] the minus ends together at the pole of the cell.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Cell Cycle Regulation in Yeast

A

Two groups of cyclins Cdc2 kinase works with different classes of kinease. The first class of kinase is G1/S that promotes cell to go from G1 to S. Different cyclins can regulate kinase for what it targets, in this case the target is the ORC. Mitotic cyclase, will change the specificity of the enxyme. One target is lamin proteins which help form the nuclear membrane. Memebrane breaks down due to phosphorylation of the lamin. More than one type of cyclin.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

3 Regulation of cdks

A

Cyclin Concentration -Differential transcription of cyclins at stages of cell cycle

Controlled proteolysis -Cyclin concentration regulated by controlled synthesis and degradation -SCF and APC complexes link cyclins to polyubiquitin chain (degradation signal)

Cdk phosphorylation state -Kinases CAK and Wee1 Phosphatase Cdc25

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

cdk Phosphorylation State

A

1) cdc2K interacts with mitotic cyclin but remains inactive because phosphorylation of a tyrosine residue Tyr15 by Wee1.
2) CAK trasferì a phosphate to Thr161, needed for cdc2K activity. When cell reaches critical size, Cdc25 phosphatase enzyme active and removes inhibitory phosphate of Tye 15. Cdc2K active so drives cell into mitosis.
3) End of mtiosos. phosphate group removed from Thr161 by a phosphatase. Free cyclin degraded. Cell begins another cycle Cdc2K is effected by 2 kinases CAK and Wee1

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Yeast Cell Cycle Mutants

A
  • Wild Type: Cell through G2 grows and gets bigger then M divides into 2
  • Wee1- mutant: doesn’t become doubly phosphorylated so skips through and doesn’t grow. Very short G2 so very little time to grow. It divides early.
  • Cdc25- mutant: never switches from inactive to active. So continues to grow and will never divide. Turns into a giant cell that will never divide.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Eukaryotic Replication Fork comparison to PROkaryotes

A

PCNA = sliding clamp RFC = clamp loader (like gamma clamp loader in E.Coli) RPA = SSB proteins

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Meselson-Stahl Experiment

A

Meselson and Stahl found that DNA employs semi-conservative replication. They put the bacteria in an environment with a Nitrogen isotope. They first used N14. The bacteria then integrated this isotope into their DNA. Later they used an environment that contained N15. They then looked at which of the isotopes the bacterial DNA contained. They found that it contained both isotopes of nitrogen, which implies that conservative replication is not the correct conclusion. By having a closer look they could then also rule out disperse replication. Some helix strands were all N14. Other helix strands from the time in the N15 environment had N15.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Semiconservative Replication in Eukaryotes

A

•experiment where cells transferred from thymidine medium to BRdU and completed 2 rounds of replication. •resulted in one chromatid of each chromosome contains thymidine

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

descipbe 4 ways that miRNAs are involved with the lblocking of translation. Which structure in the cell does this occur?

A

Occurs in P Bodies

1) Deadenylation (followed by recapping and degradation)
2) Proteolysis (degradation of nascent peptide)
3) Initiation Block (repressed cap recognition or 60s joining)
4) Elongation Block (slow elongation or ribosome ‘drop -off’

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

4 alternative actions of Chromatin Remodeling Complex
SW1/SNF

A
  • remodelling complex remodel the nucleotide core so that it’s accessible to the RNA pol? -at step some RNApol can’t gain access to TATA because DNA is wound around Nucleosome core.
    1) Sliding exposes TATA site
    2) Reorganization of histone octamer provides access to promoter
    3) Histone variants exchanged for H2A/H2B
    4) Histone octamer disassembled
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Long Noncoding RNAs as Transcriptional Repressors

A
  1. lncRNAs guide protein complexes to specific sites on chromatin
  2. HOTAir lncRNA transcribed from HOXC locus
  3. 3’ end of HOTAir interacts with CoREST complex -Demethylates H3 K4 residues
  4. 5’ end of HOTAir interacts with PRC2 complex -Methylates H3 K27 residues
  5. Results in transcriptional repression of HOXD locus
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

the 3 main classes of trasciption factor:

A
  1. zinc finger motif
  2. helix loop motif
  3. Leucine Zipper Motif
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Zinc Finger

A
largest class of TF -cis and histone form the finger -Zinc ion coordinated between two cysteine and two histidine residues -common to have multiple fingers
1
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Helix Loop Motif

A
  • Two alpha helical segments separated by an intervening loop. Domain is often preceded by a stretch of highly basic amino acids whose positively charged side chains contact the DNA and determine sequence specificity of the transcription factor. Always occur as dimers
  • 2 helices that form a loop.
  • 2 helix proefins dimerizing togehter to form an active TF
  • example is MyoD NB for differentiating into muscle cells
  • Myogenein is turned on my MyoD -Heterodimerization increases diversity of regulatory factors. -can either be homo or heterodimer
  • home = 2 identical proteins dimerizing together
  • hetero = 2 die pretiös dimerizing together
  • gert’s lots of diversity due to dif things dimerizing together
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Leucine Zipper Motif

A

Transcription factors bind to specific regions of DNA (gene) and also interact with other transcription factors.

  • 3 class: they have a leucine a.a even 7th residue made of alpha helix called zipper because alpha helix zip together (dimerize together)
  • each turn of an å-helix is 3.5 a.a so that the 7th is NB their all (luc) on the same side are hydrophobic, they help to zip them together.
17
Q

Specificity of Amino Acid Incorporation

A

Chemical modification of cysteine to alanine Anticodon part is bottom that means that as long as the anticodon is right, literaly any a.a could bind and it would not affect the specificity for the mRNA at all.

18
Q

Describe the steps by which eukaryotic mRNA is modified at the 5’ and the 3’ ends (one is 3 steps one is two steps)

A

Capping (Capping Enzyme)

1) 5’ end of nascent pre-mRNA binds to a capping enzyme removes phosphate RNA Triphosphatase)
2) adds guanine residue Guanylyltransferse
3) Methytransferases add methyl group to terminal guanosine cap and the ribose sugar RNA

Methyltransferase Polyadenylation
A) Endonuclease cleaves RNA strand generating new 3’ end
B) Poly A polymerase adds adenosine residues to the 3’ end (non-template driven)

19
Q

Spliceosomal Intron Mechanism

A

U1 snRNP attaches at 5’ branch site

  • U2 recruited by U2AF -binds to poly-pyrimidine tract
  • U2 snRNP attaches at Adenine branch site -Forces the adening to bulge outward which makes it more likley to do the nucleophilic attack
  • ESE is exon splicing enhancer (sequence within the exon)
  • Binding of U4/U6 and U5 snRNPs -U6 has catalytic (ribozyme) activity
  • U6 activity is inhibited as long as U4 is base pared to it -beginning of the formation of the lariat
  • Displacement of U1 by U6 -Dissociation of U4 from U6 -U6 + U5 have catalytic activity (helices) -pull close to each other, so you get nucleophilic attack
  • Cleavage of 5’ splice site and formation of lariat intron
  • 3’ exon intermediate -Exon 1 and 2 kept together by U5 SNRP
  • now 2nd rx where exon 1 nucleophilic attacks on exon 2 with aid of U5 SRP and the remnant lariat
  • Second cleavage reaction at 3’ splice site and simultaneous joining of exons.
20
Q

What are the components of a nucleosome

A

gc (granular component)-Ribosomal subunits in process of assembly

  • fc (fibrillar component) – DNA (genes) coding for rRNA
  • dfc (dense fibrillar component) – rRNA nascent transcripts
21
Q

Inducible Control

A

Example: Lactose -addition of lactose= increases β-galactosidase -Minimal conditions- no β-galactosidase expressed

22
Q

Repressible Control

A

Example: Tryptophan -Typ is a corepressor. -if Typ is present, it binds to the repressor and turns it on stopping synthesis of Typ

23
Q

Importing Proteins to Nucleus (5 Steps)

A

Step 1: NLS containing cargo protein binds to a heterodimeric soluble NLS receptor called importin å/ß Step 2: NlS transport receptor escorts the protein cargo to the outer surface of the nucleus where it docks with the cytoplasmic filaments that extend from the outer ring of the NPC
Step 3: Filaments bend toward the nucleus delivering the receptor-cargo complex to specific binding sites on the NPC. The protein is bound by the fillaments. The filaments weave a round and the protein is lodged into the nuclear pore
4) Ran-GTP binds to Importin/NLS and causes disassembly-Imported cargo released
5) Part of NLS receptor (importin β) shuttled back to cytoplasm with Ran-GTP . Ran-GTP hydrolyzed and released (Ran-GDP) and released