PR Physics Flashcards
Newton’s third law
Objects exerting forces on each other will have forces w the same magnitude but opposite directions = action-reaction pair; remember this pair refers to forces put on DIFFERENT OBJECTS, so gravitational vs normal force CANNOT APPLY
Pushing an object on earth and on the moon = different forces needed?
no – F = ma (specific for exerting force on an object, not gravitational pull) does not depend on weight, only mass
Inverse square law for gravitation
gravitational force proportional to 1/r^2 (inversely proportional to radius squared
When drawing out force diagrams for gravitation
always draw out the normal counterforce
differences between kinetic friction and static friction
Kinetic friction: friction when there is motion
- Ff = µk*Fn (frictional force = coefficient of kinetic friction * normal force)
Static friction: friction when there is no motion
- uses maximum coefficient of static friction (bc its always greater than coefficient of kinetic friction) = this is the amount of force it takes to initiate movement. “force of static friction” is just the force exerted on an object (object doesn’t need to be moving)
- Ff, max = µs*Fn
When net force is zero
opposite forces are equal
e.g. when an object isn’t being lifted, the total upward force is equal to the total downward force (so if there’s an Fy but object is not being lifted, Fg = Fn + Fy, or normal force is not equal to gravitational force
since ya don’t wanna memorize the big 5 equations, what do you need to know to derive the answers?
a = (vf-v0)/t; Remember v0 is often zero.
AND
vf-v0/2 = d/t; because v is average v, which is calculated using vf-v0/2.
sqrt(3)/2 – value and why relevant
0.85, value for sin 60 and cos 30
applied force F on an object from rest to start going up an incline requires which forces to be overcome?
both static force and gravitational force
Will the centripetal force of an object increase or decrease with an increase in radius
Although acceleration = velocity^2/radius, velocity in this case refers to terminal velocity
terminal velocity = r*ω, where ω is the constant rotational velocity.
therefore, acceleration is proportional to r^2/r, or acceleration is proportional to r