PR Physics Flashcards

1
Q

Newton’s third law

A

Objects exerting forces on each other will have forces w the same magnitude but opposite directions = action-reaction pair; remember this pair refers to forces put on DIFFERENT OBJECTS, so gravitational vs normal force CANNOT APPLY

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2
Q

Pushing an object on earth and on the moon = different forces needed?

A

no – F = ma (specific for exerting force on an object, not gravitational pull) does not depend on weight, only mass

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3
Q

Inverse square law for gravitation

A

gravitational force proportional to 1/r^2 (inversely proportional to radius squared

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4
Q

When drawing out force diagrams for gravitation

A

always draw out the normal counterforce

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5
Q

differences between kinetic friction and static friction

A

Kinetic friction: friction when there is motion
- Ff = µk*Fn (frictional force = coefficient of kinetic friction * normal force)

Static friction: friction when there is no motion

  • uses maximum coefficient of static friction (bc its always greater than coefficient of kinetic friction) = this is the amount of force it takes to initiate movement. “force of static friction” is just the force exerted on an object (object doesn’t need to be moving)
  • Ff, max = µs*Fn
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6
Q

When net force is zero

A

opposite forces are equal

e.g. when an object isn’t being lifted, the total upward force is equal to the total downward force (so if there’s an Fy but object is not being lifted, Fg = Fn + Fy, or normal force is not equal to gravitational force

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7
Q

since ya don’t wanna memorize the big 5 equations, what do you need to know to derive the answers?

A

a = (vf-v0)/t; Remember v0 is often zero.
AND
vf-v0/2 = d/t; because v is average v, which is calculated using vf-v0/2.

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8
Q

sqrt(3)/2 – value and why relevant

A

0.85, value for sin 60 and cos 30

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9
Q

applied force F on an object from rest to start going up an incline requires which forces to be overcome?

A

both static force and gravitational force

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10
Q

Will the centripetal force of an object increase or decrease with an increase in radius

A

Although acceleration = velocity^2/radius, velocity in this case refers to terminal velocity

terminal velocity = r*ω, where ω is the constant rotational velocity.

therefore, acceleration is proportional to r^2/r, or acceleration is proportional to r

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