Hardy Weinberg in Human population and forensic genetics Flashcards

1
Q

HWE

A

no human population can meet all the requirements of HW law but can still use to calculate genotype proportions

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2
Q

significant deviation

A

Various tests have been carried out on population data comparing predicted genotype frequencies under HWE and measuring if there is significant deviation

Significant deviations have not been detected in the vast majority of population

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3
Q

forensic DNA analysis

A

the HWE is used along with allele frequency databases to calculate genotype frequencies

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4
Q

recessively inherited disorders

A

HW law can be used to calculate the frequencies of harmful recessive alleles

Homozygote recessive disorder such as cystic fibrosis

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5
Q

what do AA, Aa and aa represent

A

AA=normal phenotype
Aa=carrier
aa=disease phenotype

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6
Q

what does p+q equal

A

1

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7
Q

A + a is the same as what

A

p+q

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8
Q

what are AA, Aa and aa in p and q terms

A
AA = p squared
Aa = 2pq
aa = q squared
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9
Q

what is the frequency of heterozygous carriers

A

2pq

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10
Q

e.g 1 in 1000 children has cystic fibrosis, what is q squared, q, p and 2pq

A

q squared = 0.001
q = 0.03
p = 0.97
2pq = 0.0582

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11
Q

allele frequency databases

A

constructed by measuring the occurrence of alleles within a defined population

It has been recommended that a sample of at least 200 alleles per locus (100 individuals) is used

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12
Q

frequencies of STR profiles

A

The genotype proportions for each locus are calculates using p2 for homozygotes and 2pq for heterozygotes

The overall profile frequency is calculated by multiplying the genotype frequency at each locus

This is called the product rule

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13
Q

the product rule

A

Multiplication of individual genotype frequencies at different loci to give the overall profile frequency

Population must be in linkage equilibrium

This is true for the standard STRs

All on different chromosomes & are inherited independently

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14
Q

see powerpoint for

A

calculation of STR profile frequency

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