Kinematic Relationships Flashcards

1
Q

Velocity is the rate of change of

A

Displacement with time

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2
Q

Acceleration is the rate of change of

A

Velocity with time

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3
Q

Acceleration is the second differential of

A

Displacement with time

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4
Q

v = u + at

A

velocity = initial velocity + accelerationn x time

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5
Q

v= ds/dt

A

velocity is the rate of change of displacement with time

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6
Q

a = dv/dt = d^2s/dt^2

A

Acceleration is the rate of change of velocity with time and is the second differential of displacement with time

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7
Q

s = ut + 1/2at^2

A

displacement = initial velocity x time + 1/2 x acceleration x time^2

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8
Q

v^2 = u + 2as

A

velocity^2 = initial velocity + 2 x acceleration x displacement

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9
Q

the area under a line on a graph can be found by

A

integration

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10
Q

the gradient of a curve or a straight line on a DISPLACEMENT-TIME graph is the

A

instantaneous velocity

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11
Q

the gradient of a curve or straight line on a VELOCITY-TIME graph is the

A

instantaneous acceleration

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12
Q

the gradient of a curve or straight line on a MOTION-TIME graph represents

A

instantaneous rate of change and this can be found by differentiation

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13
Q

the area under an ACCELERATION-TIME graph between limits is the

A

change in velocity

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14
Q

the area under a VELOCITY-TIME graph between limits is the

A

displacement

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15
Q

Derive v = u + at starting with a = dv/dt

A
integrate with respect to time
ds/dt = at + k
at t = 0 ds/dt = u so k = 0
at t = t  ds/dt = v
thus v = u + at
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16
Q

Derive s = ut + 1/2at^2 starting at ds/dt = v = u + at

A

integrate with respect to time
s = ut + 1/2at^2 + c
at t = 0, s = 0 so c = 0
s = ut + 1/2at^2

17
Q

Derive v^2 = u^2 + 2as starting at v = u + at

A
Square both sides
v^2 = (u+at)(u+at)
v^2 = u^2 + 2uat + a^2t^2
v^2 = u^2 + 2a(ut + 1/2at^2)
s = ut + 1/2at^2
v^2 = 2as
18
Q

differentiate symbol

integrate symbol

A

dy/dx or dā€™

āˆ«

19
Q

after integration, you must always add what

A

a constant +c

and then show what c is equal to.