S1-L12: Organic Structure and Bonding Flashcards

1
Q

Describe S orbital (refer to figure 1)

A
  • spherical

- lower in energy than other orbitals in same shell

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2
Q

Outline what the P orbital is (refer to figure 2)

A
  • dumb bell shape
  • nodal plane passes through nucleus
  • higher in energy than S orbital
  • 3 p orbitals in same shell
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3
Q

How does bonding in organic molecules occur?

A
  • through linear combination of atomic orbitals (LCAO)

- orbitals combine to form hybrid atomic orbitals (sp, sp2, sp3) AND molecular orbitals (sigma, sigma, pi, pi)

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4
Q

Define the following type of orbitals:

1-Hybrid atomic orbital

2-Molecualr orbital

A

1-combination of atomic orbitals from same atom
2-combination of atomic OR hybrid atomic orbitals from different atoms
-second row of elements (like C/O/N) hybridise using their 2s AND 2p orbitals to form sp, sp2, sp3 HAO’s

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5
Q

What is hybridisation and it’s use? (refer to figure 3)

A
  • C electronic configuration: 1s2, 2s2, 2p2
  • ->2 unpaired e-‘s yet C forms 4 bonds
  • one of 2s e-‘s can be promoted into vacant p orbital
  • ->requires energy input
  • ->favourable as decreased e- -e- repulsion
  • 2s AND 2p orbital now mix to form various hybrid atomic orbitals
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6
Q

Explain sp^3 hybridisation

A
  • all 4 atomic orbitals combine to give same n. of new hybrid atomic orbitals
  • all 4 sp3 orbitals equivalent with same energy (degenerate)
  • orbitals point towards corners of tetrahedron
  • overlap produces sigma bonds
  • used for bonding in saturated compounds
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7
Q

What is sp^2 hybridisation?

A
  • S and two P orbitals combine to give 3 new hybrid atomic orbitals
  • 3rd orbital unchanged
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8
Q

How is the positioning of the different parts of this hybridisation significant?

A
  • sp2 orbital point towards corners of triangle
  • ->used for sigma bonding
  • p orbital perpendicular to them
  • ->used for pi bonding
  • sp2 hybridisation used for bonding in alkenes/ carbonyls AND aromatic rings
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9
Q

Outline sp hybridisation (figure 6)

A
  • s and one p orbital combine to give two new hybrid atomic orbitals
  • other two orbitals unchanged
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10
Q

How are the sp orbitals structured and what is the significance of this? (figure 7)

A
  • sp orbitals at 180 degrees to each other (linear molecule)
  • ->used for sigma bonding
  • p orbitals perpendicular to them
  • ->used for pi bonding
  • sp hybridisation used for bonding in alkynes AND nitriles
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11
Q

Outline the properties of hybrid orbitals

A
  • hold e-‘s closer to nucleus
  • bond becomes shorter AND so stronger
  • more directional SO have more effective bonding interactions
  • more s-character in orbital- the lower the energy
  • ->increased stability of e- in that orbital
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12
Q

Explain the formation of Sigma bonds and their structure (refer to figure 8)

A
  • sigma bonds formed by direct overlap
  • e- density is along line of bond- directly between atoms
  • symmetric wrt 180 degrees rotation about bond
  • bonds may be formed between s-s/ p-p/ s-p OR hybridised orbitals
  • bonding molecular orbital lower in energy than original atomic orbitals
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13
Q

Outline the sigma bonding in methane (figure 9)

A
  • 4 sp3 hybrid orbitals form tetrahedron
  • ->add 4 H atoms
  • ->combine sp3 AND 1s
  • ->each MO orbital same AND has sigma symmetry
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14
Q

Describe sigma bonding in ethane

A
  • each C uses sp3 orbitals to bond to H’s

- remaining sp3 orbital on each C overlaps to form C-C bond

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15
Q

How do pi bonds form?

A
  • formed by “parallel” overlap of p orbitals
  • e- density above AND below plane of bond
  • ->no e- density directly between bonded atoms
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16
Q

Describe the features of pi bonds

A
  • antisymmetric wrt 180 degrees rotation about bond
  • form after sigma bonds
  • higher in energy than sigma bonds
  • ->so weaker AND broken easier
17
Q

Briefly explain the bonding in ethene (refer to figure 13)

A
  • double bond (2 pairs of shared e-‘s) consists of sigma bond AND pi bond
  • triple bond (3 pairs of shared e-‘s) consist of sigma bond AND 2 pi bonds
18
Q

Bonding in ethyne (acetylene)

A
  • figure 14 shows the pi overlap in ethene (pi bonds)

- figure 15 shows the sigma bonds in ethyne

19
Q

Describe bonding in benzene with reference to figure 16

A
  • pi e-‘s delocalised around ring ABOVE and BELOW plane

- all bond lengths identical between single and double bonds

20
Q

What happens to bond strength as bond length increases? (refer to figure 17)

A
  • bond strength decreases
  • bond length in increasing order:
  • single
21
Q

Summary of key bonding parts of lecture:

N. of bonds to C–> hybridisation–> bond angle
–>bonding between carbons

A
  • 4–>sp3–>109.5–>one sigma bond/ sp3-sp3
  • 3–>sp3–>120–>one sigma bond (sp2-sp2)/one pi bond (p-p)
  • 2–>sp–>180–>one sigma bond (sp-sp)/ two pi bonds (p-p)