Magnetism and Circuits Flashcards

1
Q

What will the direction of the magnetic force be?

A

Right hand rule

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2
Q

Describe the right hand rule for determining the direction of a magnetic field (B) generated by a current flowing through a wire.

A

Current in the flow of positive charge. Point your thumb in the direction of the current and whichever direction your hands wrap, thats it.

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3
Q

How do you calculate a magnetic field generated by a current flowing through a wire?

A
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4
Q

What is a Tesla?

A

Tesla is the measure of the magnetic field. It is how many newtons a 1c charge experiences at 1 m/s

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5
Q

True or false: A fast-moving particle will generate a stronger magnetic field than a slow moving particle of equal charge.

A

This statement is true. The strength of a magnetic field generated by a moving charge is proportional to the velocity and charge of that particle. A faster moving particle will generate a stronger magnetic field than a slower moving particle, given equal charge. Two particles of equal velocity will produce magnetic fields whose relative strength depends on their charge.

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6
Q

How do you calculate magnetic force?

A
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7
Q

True or False: Magentic fields only exert a force on particles in motion

A
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8
Q

What is current measure in?

A

Amperes (C/s)

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9
Q

How do you calculate magnetic force for a current carrying wire?

A
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10
Q

Describe the right hand rule for determining the direction force generated by magnetic field a current carrying wire.

A
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11
Q

Lorentz Force

A

Summation of electric and magnetic forces on a charge

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12
Q

True or false: A magnetic field would exert zero force on a proton traveling perpendicular to the direction of the field.

A

This statement is false. Magnetic force is maximized when an object’s velocity vector is perpendicular to the magnetic field lines. Conversely, magnetic fields cannot act on objects with a velocity vector whose direction is parallel to the direction of the magnetic field lines.

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13
Q

True or false: For any two charged particles moving in the same direction through a magnetic field of constant strength, the faster moving charged particle will experience a greater magnetic force.

A

This statement is false. Magnetic force is calculated based on the equation FB = q*v*B * sin(theta), where q is the charge of an object, v is it’s velocity, B is the strength of the magnetic field, and theta is the angle of the velocity of the object relative to the direction of the magnetic field. While a faster velocity will increase the magnetic force experienced by a charge, we would need to know the magnitude of the charge of each particle to determine which particle experiences a greater magnetic force.

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14
Q

Dimagentic

A
  • orbitals are all paired off
  • the material does not create a field ansd cannot be magnetized
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15
Q

Paramagentic

A
  • Unpaired e-
  • Materials as whole has not net dipole but can have one temporarily
  • weakly attracted by mag fields
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16
Q

Ferromagentic

A

can become permanent magnets

17
Q

What is chatge measured in?

A

Couloumbs

18
Q

Ohms Law

A

V=IR

19
Q

Power

A

P=IV,

P=I2R,

P=V2/R

20
Q

What are ohms?

A

Volts/amperes

21
Q

Resistivity

A

rho= omega * m

22
Q

What is the relationship between resistance and capacitance?

A

Opposites

23
Q
A

This is a Physics question that falls under the content category “Electrochemistry and electrical circuits and their elements.” The answer to this question is C because the electrical resistance R of a conductor through which a current I passes when subject to a voltage V is given by Ohm’s law: R = V/I = 80 mV/(400 × 10–12 A) = 200 MΩ. It is a Data-based and Statistical Reasoning question because you must use the data in the graph and determine the maximum value of the current, which corresponds to the minimum value of the resistance.

24
Q

An experimental setup designed to measure the resistance of an unknown resistor R using two known resistors R1 and R2, the variable resistor R3, a voltage source, and a voltmeter is shown. Which relationship gives the value of R when R3 is adjusted so that the voltmeter reading is zero?

R=R3 x R1/R2

R=R3+R2-R1

R=R3-R2+R1

R=R3xR2/R1

A

This is a Physics question that falls under the content category “Electrochemistry and electrical circuits and their elements.” The answer to this question is A, because when the voltmeter reading is zero, the voltage across R is equal to the voltage across R1 and from Ohm’s law, IR = I1R1, where I and I1 are the currents through the resistors. Moreover, IR3 = I1R2. By taking the ratio of these two equations, it follows that R/R3 = R1/R2, which is equivalent to R = R3 × R1/R2. It is a Reasoning about the Design and Execution of Research question because you must reason about the features of this experimental setup and the association between the variables that enable the use of this particular design for its stated purpose.

25
Q

How much energy is stored in a circuit?

A

Energy= 1/2 CV2

26
Q

What units compose a farad?

A

F=Coulumb/Volt

27
Q

What equation relates charge, capacitance, and voltage?

A

Q=CV

28
Q

How is capacitance impacted by parallel plate distance?

A

The longer the distance, the less capacitance. C=e(A/d) where e is the permitivity constant, A is area of plates and d is the distance between them