Alphatic Reactions Conditions 2

Question 1

CH₂CH₂  → CH₃CH₂Br

Answer 1

electrophilic addition using HBr

Question 2

CH₃CH₂OH → CH₃COOH

Answer 2

oxidation using K₂Cr₂O_7(aq) with H₂SO_4(aq), heat under reflux

Question 3

CH₃CH₂Br → CH₃CH₂OH

Answer 3

nucleophilic substitution using KOH(aq) or NaOH(aq), heat under reflux

Question 4

CH₃CH₂Br → CH₂CH₂

Answer 4

elimination using KOH in ethanol or NaOH in ethanol

Question 5

CH₃CN → CH₃CH₂NH₂

Answer 5

reduction using NaBH₄(aq) or LiAlH₄ in dry ether followed by HCl(aq)

Question 6

C₆H₆ → C₆H₅CH₃

Answer 6

electrophilic substitution using CH₃Cl and AlCl₃ catalyst (Friedel–Crafts reaction)

Question 7

CH₃CHO → CH₃CH(OH)(CN)

Answer 7

nucleophilic addition using HCN

Question 8

CH₃COOH → CH₃COO^–Na⁺

Answer 8

acid–base reaction using NaOH(aq) or NaHCO₃(aq)

Question 9

CH₃CH₂NH₂ → CH₃CH₂NH₃⁺

Answer 9

acid–base reaction using any dilute acid

Question 10

CH₂CH₂ → CH₃CH₂OH

Answer 10

hydration using concentrated sulfuric acid followed by dilution with water

Question 11

CH₃COOH → CH₃COOCH₂CH₂CH₃

Answer 11

esterification (or condensation) using CH₃CH₂CH₂OH with conc. H₂SO₄ catalyst

Question 12

Deduce the reaction type from the reagent, then deduce the product.

(conc. H₂SO₄)

        CH<sub>3</sub>CH<sub>2</sub>OH(l) →   ………………

Answer 12

dehydration to CH₂CH₂ (ethene)

Question 13

Deduce the reaction type from the reagent, then deduce the product.

(KOH(aq))

        CH<sub>3</sub>CH<sub>2</sub>Br(l)→   ………………

Answer 13

nucleophilic substitution to form CH₃CH₂OH (ethanol)

Question 14

Deduce the reaction type from the reagent, then deduce the product.

(KOH in ethanol)

        CH<sub>3</sub>CH<sub>2</sub>Br(l) →   ………………

Answer 14

elimination to form CH₂CH₂ (ethene)

Question 15

Deduce the reaction type from the reagent, then deduce the product.

(LiAlH₄ in dry ether, then add dilute HCl(aq))

        CH<sub>3</sub>COOH(l) →   ………………

Answer 15

reduction to CH₃CH₂OH (ethanol)

Question 16

Deduce the reaction type from the reagent, then deduce the product.

(K₂Cr₂O₇(aq) with H₂SO₄(aq), heat under reflux)

CH<sub>3</sub>CH<sub>2</sub>OH<sub>(l)</sub> →   ………………

Answer 16

oxidation to CH₃COOH (ethanoic acid)

Question 17

CH₃CH₃CN → CH₃CH₂COOH

Answer 17

reflux with HCl