Applied Biochemical Techniques Flashcards

(41 cards)

1
Q

explain how a spectrophotometer works and how it can be used to determine concentration of analyte

A
  • light of continuous spectrum emerges from light source
  • light passes through prism/grating which splits and refracts light into composite wavelengths
  • sample is held in cuvette
  • incident light enters into sample ad transmitted light emerges from sample
  • intensity of transmitted light is detected by photodetector
  • spectrophotometer then calculates amount of monochromatic light absorbed by sample
  • intensity of light absorbed can be used to determine concentration of analyte
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2
Q

describe each component parts of a spectrophotometer and the function of each part

A

light source - provides light that generates a continuous spectrum

cuvette - holds sample

prism/grating - splits and diffracts light into composite wavelengths

photodetector - detects intensity of transmitted light

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3
Q

what is the difference between incident light and transmitted light?

A
  • incident light enters into the sample
  • transmitted light emerges from the sample
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4
Q

what is absorbance (A)?

A

the amount of monochromatic light absorbed by a sample

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5
Q

what is meant by the term λmax?

A

wavelength of light that is most strongly absorbed by the substance of interest

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6
Q

why is it important to calibrate the spectrophotometer with a blank?

A

to take into account the natural absorbance of the solvent

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7
Q

how is the effect of pH on the absorption spectra minimised?

A

prepare the sample in a suitable buffer solution

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8
Q

explain why it is important to control the temperature of the sample during spectrophotometry?

A

temperature impacts on absorption measurements by causing expansion or contraction of solvent, changes to reaction rates

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9
Q

what are the three factors of Beer-Lambert law that affect how much light is absorbed by a sample?

A

ϵ = molar absorptivity (how strongly a substance absorbs light of a given wavelength)

l = path length of cuvette (cm) (distance the light travels through the sample)

c = concentration of substance in a sample (moll-1)

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10
Q

state the Beer-Lambert equation

A

A = ϵlc

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11
Q

explain how you would use absorbance and concentration to determine the concentration of an unknown sample

A
  • create a standard curve by measuring absorbance of known concentrations

use standard curve
- identify absorbance on y axis
- read along to line of best fit and read down to y axis
- mark this on graphs using dotted line

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12
Q

explain a limitation of the Beer-Lambert law

A

high concentrations
- molecular interactions can take place
- causes changes to the position and shape of absorption bands
- limitation of BL law as it affects linearity of the relationship between sample concentration and absorbance
- low concentrations must be used

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13
Q

state 2 applications of spectrophotometry

A
  • enzyme activity
  • quality/quantity of pharmaceuticals
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14
Q

describe the basic principles of ion exchange chromatography

A
  • matrix in column made up of polymer beads with a charge
  • molecule mixture added to column and opposite charges attract
  • molecules eluted by washing column with increasing concentrations of salt solution (NaCl)
  • molecules move through column at rates determined by their charge
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15
Q

explain how sodium chloride can be used to elute during ion exchange chromatography

A

molecule of interest has negative charge
- chlorine ions compete to bind with the matrix
- molecule with weakest negative charge elutes first

molecule of interest has positive charge
- sodium ions compete to bind with matrix
- molecule with weakest positive charge elutes first

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16
Q

what charge does the column have if it is an ion exchange column?

A

anions are negative so the column must be positive

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17
Q

what charge does the column have if it is a cation exchange column?

A

cations are positive so the column must be negative

18
Q

describe the basic principles of affinity chromatography

A
  • column contains binding ligands that bind to the molecule of interest
  • molecule mixture added to column
  • target molecule becomes trapped (binds to ligand)
  • elute using a ligand solution of higher concentration
19
Q

what is used for elution during affinity chromatography?

A

ligand solution (for example substrate)

20
Q

when separating enzymes using affinity chromatography, what property of the enzyme is being taken advantage of?

A

that it will bind to a substrate

21
Q

why does HPLC give a higher resolution compared to low pressure techniques?

A

sample spends less time in the column

22
Q

what type of gel is used to separate DNA fragments?

23
Q

what type of gel is used to separate proteins?

A

polyacrylamide

24
Q

what is the charge at the top of the tan next to the wells during DNA electrophoresis?

A

negative charge

25
what would happen if you changed the pH if the buffer used during DNA electrophoresis?
change the charge on the phosphate group
26
what part of DNA has a negative charge?
phosphate group
27
what is the purpose of running a marker sample during electrophoresis?
to provide a standard to compare against/to determine DNA band size
28
what could happen to the distance travelled by DNA fragments if the concentration of agarose is increases?
distance travelled would be less
29
what property of proteins is being exploited during gel filtration?
size/molecular weight
30
describe how gel alteration chromatography works
column contains a polymer (beads) that have pores/holes and retain molecules depending on their size
31
what does SDS do in SDS-PAGE
it denatures proteins and coats their surface with negatively charged SDS ions
32
what property of proteins is being exploited in molecular weight?
molecular weight
33
name a stain that is commonly used which binds to proteins but not the gel?
coomassie blue
34
what is meant by 'isoelectric point'?
the pH at which a protein has no charge
35
what property of proteins is being exploited during isoelectric focusing?
each amino acid has its own isoelectric point and will migrate differently under the effect of different pH
36
explain in detail how enzymes act as biological catalysts
- provide alternative mechanism for reaction - substrate binds to active site and enzyme facilitates reaction eg. stresses are brought to bear on chemical bonds in the substrate, makes chemical change more likely - interaction of enzyme and substrate reduces activation energy required for reaction to take place - more molecules can reach transition state therefore more product is formed
37
describe 2 models that are used to describe enzyme activity
lock and key theory - for enzyme to catalyse reaction there must be an exact complementary fit between shape of enzyme's active site and shape of substrate molecule induced fit theory - conformation of an enzyme molecule is slightly altered when the substrate binds to the active site - enzyme folds around the substrate molecule
38
explain how increasing temperature affects enzyme activity
- as temperature increases enzyme activity will initially increase as more molecules will have energy greater then activation energy - this continues until the optimum temperature where there is maximum activity - further increases in temperature will destabilise bonds within the enzyme leading to loss of tertiary structure. - this decreases enzyme activity as the active site will alter in structure - further increase in temperature will cause irreversible change to structure = enzyme denatured
39
explain how pH affects enzyme activity
- bonds that hold substrate to active site depend of the correct charge on amino acid side chains - change the pH = alter charge on the side chains = affects binding - bonds that stabilise enzyme molecule depend on correct charge in amino acid side chains - change the pH= alter the charge on the side chains = affects the bonds - extremes of pH cause conformational change
40
describe what the line in presence of a non-competitive inhibitor would look like in a graph?
- Max decreases because rate of reaction is slowed - proportion of enzyme molecules able to catalyse the reaction is diminished - Km is unchanged as affinity is not affected
41
describe what the line in presence of a competitive inhibitor would look like in a graph?
- Km increases because inhibit compete s for active sites - means more substrate is needed to achieve half of Max - Vmax is unchanged because it is still achievable at high substrate concentrations